1599 - Multiple 时间限制:2秒 内存限制:64兆 461 次提交 111 次通过 题目描述 Rocket323 loves math very much. One day, Rocket323 got a number string. He could choose some consecutive digits from the string to form a number. Rocket323 loves 64 very much, so he wanted to know…

input 长度不大于3*10e5的数字串 output 不含前导0的能整除64的字串的个数(0算一个,064不算) 一般数组中找能整除一个数的字串都是用取余来做的 用一个a[64]来存下从1-i位累加到第i位的余数为0-63的个数,每次都加上余数为0的个数,第一位为0的只统计一次,不加入a数组中 #include <iostream> #include <cstdio> #include <cstring> using namespace std; ]; ][],b[…

POJ 1426 Find The Multiple 题意:给定一个整数n,求n的一个倍数,要求这个倍数只含0和1 参考博客:点我 解法一:普通的BFS(用G++能过但C++会超时) 从小到大搜索直至找到满足条件的数,注意最高位一定为1 假设 n=6  k即为当前所求的目标数,不满足条件则进一步递推 (i 为层数(深度),在解法二的优化中体现,此时可以不管) 1%6=1 (k=1) i=1 { (1*10+0)%6=4 (k=10) i=2 { (10*10+0)%6=4 (k=100) i=4…

islands Time Limit: 1 Sec  Memory Limit: 256 MB 题目连接 http://acm.hust.edu.cn/problem/show/1385 Description Deep in the Carribean, there is an island even stranger than the Monkey Island, dwelled by Horatio Torquemada Marley. Not only it has a rectangu…

Conversion to Dalvik format failed: Unable to execute dex: Multiple dex files define ... 这个错误是因为有两个相同的jar包,删除其中一个就可以正常运行了.…

Find a multiple Time Limit: 1000MS   Memory Limit: 65536K Total Submissions: 7192   Accepted: 3138   Special Judge Description The input contains N natural (i.e. positive integer) numbers ( N <= 10000 ). Each of that numbers is not greater than 15000…

The API: int read4(char *buf) reads 4 characters at a time from a file. The return value is the actual number of characters read. For example, it returns 3 if there is only 3 characters left in the file. By using the read4 API, implement the function…

最近在处理SharePoint Office365的相关开发的时候发现了这样一个奇怪的现象: 无法通过API更新Editor field,只要已更新就会throw Exception,由于是Office365的Exception,无法单单从Exception中分析出问题原因,而且奇怪的是新创建的List也存在同样的问题. 试了半天也没找到解决办法,单单看field的SchemaXml也没发现什么比较特殊的地方. 无奈之下save了一个list template,上传到本地的SharePoint…

K - Yet Another Multiple Problem Time Limit:20000MS     Memory Limit:65536KB     64bit IO Format:%I64d & %I64u Submit Status Practice HDU 4474 Appoint description:  System Crawler  (2014-10-16) Description There are tons of problems about integer mul…

加密代码 /**解密 * @param content 待解密内容 * @param password 解密密钥 * @return */ public static byte[] decrypt(byte[] content, String password) { try { KeyGenerator kgen = KeyGenerator.getInstance("AES"); kgen.init(128, new SecureRandom(password.getBytes())…