poj1066 Jugs】的更多相关文章

poj1066 Jugs http://poj.org/problem?id=1606 解题思路:本题可以用数学方法解得,最易理解,常规的解法是搜索.直接用接近模拟的广度优先搜索即可过. 给两个容器,给出最大容量(ca,cb)和目标水量n,可以执行6种操作: (1)把A容器灌满水,操作名:fill A: (2)把B容器灌满水,操作名:fill B: (3)把A容器中的水倒出去,管它倒到哪里去,反正不在这两个容器里面,操作名:empty A: (4)把B容器中的水倒出去,操作名:empty B:…
Jugs Time Limit: 2 Seconds      Memory Limit: 65536 KB      Special Judge In the movie "Die Hard 3", Bruce Willis and Samuel L. Jackson were confronted with the following puzzle. They were given a 3-gallon jug and a 5-gallon jug and were asked t…
题目概述:Jugs In the movie "Die Hard 3", Bruce Willis and Samuel L. Jackson were confronted with the following puzzle. They were given a 3-gallon jug and a 5-gallon jug and were asked to fill the 5-gallon jug with exactly 4 gallons. This problem gen…
POJ1066 题意:给出一个100*100的正方形区域,通过若干连接区域边界的线段将正方形区域分割为多个不规则多边形小区域,然后给出宝藏位置,要求从区域外部开辟到宝藏所在位置的一条路径,使得开辟路径所需要打通的墙壁数最少("打通一堵墙"即在墙壁所在线段中间位置开一空间以连通外界),输出应打通墙壁的个数(包括边界上墙壁). 思路:枚举每一个入口,在所有的情况中取穿墙数最少的输出即可,枚举每一个入口的时候,并不用枚举每条边的中间点,直接枚举该线段的两个顶点就行(因为要经过一个墙,那么从线…
ZOJ Problem Set - 1005 Jugs Time Limit: 2 Seconds      Memory Limit: 65536 KB      Special Judge In the movie "Die Hard 3", Bruce Willis and Samuel L. Jackson were confronted with the following puzzle. They were given a 3-gallon jug and a 5-gall…
今天总算开学了,当了班长就是麻烦,明明自己没买书却要带着一波人去领书,那能怎么办呢,只能说我善人心肠哈哈哈,不过我脑子里突然浮起一个念头,大二还要不要继续当这个班委呢,既然已经体验过就可以适当放下了吧,用心在自己的研究上.晚上级会开完也就八点多了,开始打打题,今天在HDU杭电的ACM集训题看到一个奇葩的题,前来献上. 今日推荐: <全球风暴> 一部宇宙航空和地球气候片的良心佳作,后期特效建模都是特别杠杠的大片,不会让你失望的哟,我已经三刷了哈哈哈.这部片在爱奇艺有上线,有兴趣的朋友可以看看鸭.…
做完了才发现,好像没有人和我的做法一样的,不过我怎么都觉得我的做法还是挺容易想的. 我的做法是: 把周围的方框按顺时针编号,然后对于每一条边,如果点出现在边的一侧,则把另一侧所有的点加1,这样最后统计最小值+1即可. 离散化一下 O(n) // // main.cpp // poj1066 // // Created by 陈加寿 on 15/12/30. // Copyright (c) 2015年 chenhuan001. All rights reserved. // #include <…
时间限制:1 秒 内存限制:32 兆 特殊判题:是 提交:243 解决:200 题目描述: In the movie "Die Hard 3", Bruce Willis and Samuel L. Jackson were confronted with the following puzzle. They were given a 3-gallon jug and a 5-gallon jug and were asked to fill the 5-gallon jug with…
UVA571 - Jugs(数论) 题目链接 题目大意:给你A和B的水杯.给你三种操作:fill X:把X杯里面加满水.empty X:把X杯中的水清空.pour X Y 把X的水倒入Y中直到一方满或还有一方空为止.然后要求你得到C的水量,给出实现步骤. 解题思路:由于A,B互质,n属于[1,B - 1]则n%B=n.那么n∗A%B= n%B∗A%B = n∗R.由于AB互质所以n∗A不可能整除B.如今要求得到水量n,那么仅仅要使得R == 1就能够得到想要的水量.这样仅仅要控制A的系数就能够得…
Jugs Time Limit: 1000MS   Memory Limit: 65536K Total Submissions: 4280   Accepted: 2533   Special Judge Description In the movie "Die Hard 3", Bruce Willis and Samuel L. Jackson were confronted with the following puzzle. They were given a 3-gall…