Codeforces 682 D. Alyona and Strings (dp)】的更多相关文章

题目链接:http://codeforces.com/contest/682/problem/D 给你两个字符串,求两个字符串中顺序k个的相同子串 长度之和.(注意是子串) dp[i][j][k][0] 表示a[i] == a[j]时,a字符串前i个和b字符串前j个,顺序k个相同的子串 长度之和 dp[i][j][k][1] 表示a[i] != a[j]时,顺序k个相同子串的长度之和 dp[i][j][k][0] = max(dp[i - 1][j - 1][k][0], dp[i - 1][j…
题目链接: D. Alyona and Strings time limit per test 2 seconds memory limit per test 256 megabytes input standard input output standard output After returned from forest, Alyona started reading a book. She noticed strings s and t, lengths of which are n a…
D. Alyona and Strings 题目连接: http://www.codeforces.com/contest/682/problem/D Description After returned from forest, Alyona started reading a book. She noticed strings s and t, lengths of which are n and m respectively. As usual, reading bored Alyona…
D. Alyona and Strings 题意 给出两个字符串s,t,让找出最长的k个在s,t不相交的公共子串. 思路 看了好几个题解才搞懂. 代码中有注释 代码 #include<bits/stdc++.h> #define pb push_back using namespace std; typedef long long ll; const int N=1e5+10; const int mod=1e9+7; const int inf=0x3f3f3f3f; char s[N],t…
time limit per test2 seconds memory limit per test256 megabytes inputstandard input outputstandard output After returned from forest, Alyona started reading a book. She noticed strings s and t, lengths of which are n and m respectively. As usual, rea…
Codeforce 682 D. Alyona and Strings 解析(思維.DP) 今天我們來看看CF682D 題目連結 題目 略,請直接看原題. 前言 a @copyright petjelinux 版權所有 觀看更多正版原始文章請至petjelinux的blog 想法 首先會感覺應該是類似\(LCS\)的問題,但是有一點變形.因此我們會先想到應該是\(DP\),而可能會想到另外兩個狀態是: 共同部分是不是目前兩個字串前綴的結尾 最小的分段是幾段 也就是\(:dp[i][j][end]…
题目链接: 题目 D. Alyona and Strings time limit per test2 seconds memory limit per test256 megabytes inputstandard input outputstandard output 问题描述 After returned from forest, Alyona started reading a book. She noticed strings s and t, lengths of which are…
Alyona and Strings 题目链接: http://acm.hust.edu.cn/vjudge/contest/121333#problem/D Description After returned from forest, Alyona started reading a book. She noticed strings s and t, lengths of which are n and m respectively. As usual, reading bored Aly…
[Codeforces 865C]Gotta Go Fast(期望dp+二分答案) 题面 一个游戏一共有n个关卡,对于第i关,用a[i]时间通过的概率为p[i],用b[i]通过的时间为1-p[i],每通过一关后可以选择继续下一关或者时间清0并从第一关开始,先要求通过所有关卡的时间和不能超过R才算彻底通关,问直到彻底通关位置的游戏时间的期望值为多少 分析 二分从头开始通关的用时期望mid 设\(dp[i][j]\)表示通前i关,当前时间为j的期望,倒推期望. 若超时重新开始,则\(dp[i][j]…
[CodeForces - 1225E]Rock Is Push [dp][前缀和] 标签:题解 codeforces题解 dp 前缀和 题目描述 Time limit 2000 ms Memory limit 524288 kB Source Technocup 2020 - Elimination Round 2 Tags binary search dp *2200 Site https://codeforces.com/problemset/problem/1225/E 题面 Examp…