Robot Motion Time Limit: 1000MS Memory Limit: 10000K Total Submissions: 11262 Accepted: 5482 Description A robot has been programmed to follow the instructions in its path. Instructions for the next direction the robot is to move are laid down in a g…

在平常项目中,我们会遇到这样的业务场景: 客户希望把自己的门店绘制在百度地图上,通过省.市.区的选择,然后加载不同区域下的店铺位置. 先看看效果图吧: 实现思路: 第一步:整理行政区域表: 要实现通过地区筛选来动态加载地图,首先要有一套中国行政区域表.哪里来呢?如果你做过淘宝API接入,应该会想到淘宝物流接口提供了一个官方的行政区域代码,这个比较靠谱. 第二步:收集行政区域的经纬度: 这个就有点麻烦了,虽然可以在百度坐标拾取系统一个一个的收集整理,但是3000多条记录,是个不小的体力活.于是经过…

1.版本说明 (1)最新版本:3.3.0 (2)最新release版本:3.2.0 (3)重要历史版本:1.14.4 3.1.0及之前的版本:http://sourceforge.net/projects/archive-crawler/files/ 3.2.0及之后的版本:http://archive.org/ 由于国情需要,后者无法访问,因此本blog研究的是1.14.4版本. 2.官方材料 source:http://sourceforge.net/projects/archive-cra…

Who's in the Middle Time Limit: 1000MS   Memory Limit: 65536K Total Submissions: 34155   Accepted: 19875 Description FJ is surveying his herd to find the most average cow. He wants to know how much milk this 'median' cow gives: half of the cows give…

#include<iostream> #include<cstdio> #include<algorithm> #define Max 1005 using namespace std; struct line{ double x, y1, y2; int flag; }x_line[Max]; struct node{ int l, r, flag; double x, f; }tree[Max]; double point[Max]; int n, m, xm; i…

#include<iostream> #include<cstring> #include<cstdio> using namespace std; int n, m; int num[100005]; int front(int x) { return x&(-x); } int update(int x,int k) { while(x<=n) { num[x]+=k; x+=front(x); } return 1; } int sum(int x)…

#include<iostream> #include<cstdio> using namespace std; struct node { int l, r, m; int max; }num[800005]; int val[200005]; int n, m; int init(int l, int r, int k) { num[k].l = l; num[k].r = r; if(l==r) { num[k].m = l; num[k].max=val[l]; retur…

局部标准差在图像处理邻域具有广泛的应用,但是直接计算非常耗时,本文利用积分图像对局部标准差的计算进行加速. 局部标准差: 标准差定义如下(采用统计学中的定义,分母为): 其中. 为了计算图像的局部标准差,首先设定局部区域的大小为 ,则局部区域的像素点个数 . 对标准差的公式进行化简: 因,故: 可以看出,局部标准差计算中需要对图像与进行局部求和操作,即和. 我们可以先分别计算出图像和的积分图像.,这样就能在常量时间计算出上述的局部和. 时间复杂度: 图像中共个像素点,每个局部区域共有个像素点,直…

iOS开发-CocoaPods使用详细说明 一.概要 iOS开发时,项目中会引用许多第三方库,CocoaPods(https://github.com/CocoaPods/CocoaPods)可以用来方便的统一管理这些第三方库. 二.安装 由于网上的教程基本都大同小异,但细节之处还不是很完善,所以借机会在这里补充下: 注:要使用CocoaPods,那就要下载安装它,而下载安装CocoaPods需要Ruby环境 1.Ruby环境搭建 当前安装环境为Mac mini 10.8.5.Mac  OS本身…

c++map的用法 分类: 资料 2012-11-14 21:26 10573人阅读 评论(0) 收藏 举报 最全的c++map的用法 此文是复制来的0.0 1. map最基本的构造函数: map<string ,int>mapstring; map<int,string >mapint; map<sring,char>mapstring; map< char ,string>mapchar; map<char,int>mapchar; map&…

hadoop集群性能低下的常见原因 (一)硬件环境 1.CPU/内存不足,或未充分利用 2.网络原因 3.磁盘原因 (二)map任务原因 1.输入文件中小文件过多,导致多次启动和停止JVM进程.可以设置JVM重用. 2.数据倾斜:大文件且不可分割,导致处理这些文件的map需要很长时间. 3.数据本地化效果差. (三)reduce任务的原因 1.reduce任务数量过大或过小 2.数据倾斜:一部分key的记录数量太大,导致某些reduce执行过慢 3.缓慢的shuffle和排序 (四)hadoop…

文章原地址:http://blog.csdn.net/zhangxiang0125/article/details/6174639 博弈论:是二人或多人在平等的对局中各自利用对方的策略变换自己的对抗策略,达到取胜目标的理论.博弈论是研究互动决策的理论.博弈可以分析自己与对手的利弊关系,从而确立自己在博弈中的优势,因此有不少博弈理论,可以帮助对弈者分析局势,从而采取相应策略,最终达到取胜的目的. 博弈论分类:(摘自百度百科) (一)巴什博奕(Bash Game):只有一堆n个物品,两个人轮流从这堆…

Pie Time Limit: 5000/1000 MS (Java/Others) Memory Limit: 65536/32768 K (Java/Others) Total Submission(s): 109 Accepted Submission(s): 52   Problem Description My birthday is coming up and traditionally I'm serving pie. Not just one pie, no, I have a…

Description There is a rectangular room, covered with square tiles. Each tile is colored either red or black. A man is standing on a black tile. From a tile, he can move to one of four adjacent tiles. But he can't move on red tiles, he can move only…

Red and Black Time Limit : 2000/1000ms (Java/Other)   Memory Limit : 65536/32768K (Java/Other) Total Submission(s) : 45   Accepted Submission(s) : 34 Font: Times New Roman | Verdana | Georgia Font Size: ← → Problem Description There is a rectangular…

Power Network Time Limit: 2000MS Memory Limit: 32768K Total Submissions: 24867 Accepted: 12958 Description A power network consists of nodes (power stations, consumers and dispatchers) connected by power transport lines. A node u may be supplied with…

棋盘问题 Time Limit: 1000MS Memory Limit: 10000K Total Submissions: 28474 Accepted: 14084 Description 在一个给定形状的棋盘(形状可能是不规则的)上面摆放棋子,棋子没有区别.要求摆放时任意的两个棋子不能放在棋盘中的同一行或者同一列,请编程求解对于给定形状和大小的棋盘,摆放k个棋子的所有可行的摆放方案C. Input 输入含有多组测试数据. 每组数据的第一行是两个正整数,n k,用一个空格隔开,表示了将在一…

Ubiquitous Religions Time Limit: 5000MS   Memory Limit: 65536K Total Submissions: 26678   Accepted: 13127 Description There are so many different religions in the world today that it is difficult to keep track of them all. You are interested in findi…

Oracle 11g的dmp备份文件导入到Oracle 10g,出现错误信息: Import: Release 10.2.0.1.0 - Production on 星期四 7月 9 13:47:04 2015 Copyright (c) 1982, 2005, Oracle. All rights reserved. 连接到: Oracle Database 11g Enterprise Edition Release 11.2.0.1.0 - Production With the Part…

Gold Balanced Lineup Time Limit: 2000MS Memory Limit: 65536K Total Submissions: 13215 Accepted: 3873 Description Farmer John's N cows (1 ≤ N ≤ 100,000) share many similarities. In fact, FJ has been able to narrow down the list of features shared by h…

Doubles Time Limit: 1000MS   Memory Limit: 10000K Total Submissions: 19954   Accepted: 11536 Description As part of an arithmetic competency program, your students will be given randomly generated lists of from 2 to 15 unique positive integers and as…

The 3n + 1 problem Time Limit: 1000MS   Memory Limit: 10000K Total Submissions: 53927   Accepted: 17142 Description Problems in Computer Science are often classified as belonging to a certain class of problems (e.g., NP, Unsolvable, Recursive). In th…

IMO, version 1 better than version 2, version 2 better than version 3. make some preprocess to make you code simple and efficient. Here divide the input by 2, so you don't have to do dividsion on each loop. version 1 is best thanks to http://www.cnbl…

Arctic Network Time Limit: 2000MS   Memory Limit: 65536K Total Submissions: 9557   Accepted: 3187 Description The Department of National Defence (DND) wishes to connect several northern outposts by a wireless network. Two different communication tech…

  精选常用: 1.  ctrl+shift+r:打开资源 这可能是所有快捷键组合中最省时间的了.这组快捷键可以让你打开你的工作区中任何一个文件,而你只需要按下文件名或mask名中的前几个字母,比如applic*.xml.美中不足的是这组快捷键并非在所有视图下都能用. 2. ctrl+o:快速outline 如果想要查看当前类的方法或某个特定方法,但又不想把代码拉上拉下,也不想使用查找功能的话,就用ctrl+o吧.它可以列出当前类中的所有方法及属性,你只需输入你想要查询的方法名,点击enter就…

Does the following error message looks familiar to you? (When you go to Site Actions –> Site Settings –> [Site Administration] –> Term store management)  "The managed Metadata Service or Connection is currently not available. The Application…

reference: Rabin-Karp and Knuth-Morris-Pratt Algorithms By TheLlama– TopCoder Member https://www.topcoder.com/community/data-science/data-science-tutorials/introduction-to-string-searching-algorithms/ // to be improved #include <cstdio> #include <…

reference: 6.4 knapsack in Algorithms(算法概论), Sanjoy Dasgupta University of California, San Diego Christos Papadimitriou University of California at Berkeley Umesh Vazirani University of California at Berkeley the unbounded knapsack and 0-1 knapsack a…

A Plug for UNIX Time Limit: 1000MS Memory Limit: 65536K Total Submissions: 14786 Accepted: 4994 Description You are in charge of setting up the press room for the inaugural meeting of the United Nations Internet eXecutive (UNIX), which has an interna…

4 Values whose Sum is 0 Time Limit: 15000MS Memory Limit: 228000K Total Submissions: 17875 Accepted: 5255 Case Time Limit: 5000MS Description The SUM problem can be formulated as follows: given four lists A, B, C, D of integer values, compute how man…