1053. Path of Equal Weight (30) 时间限制 100 ms 内存限制 65536 kB 代码长度限制 16000 B 判题程序 Standard 作者 CHEN, Yue Given a non-empty tree with root R, and with weight Wi assigned to each tree node Ti. The weight of a path from R to L is defined to be the sum of the…

1053 Path of Equal Weight (30 分)   Given a non-empty tree with root R, and with weight W​i​​ assigned to each tree node T​i​​. The weight of a path from R to L is defined to be the sum of the weights of all the nodes along the path from R to any leaf…

题目 Given a non-empty tree with root R, and with weight Wi assigned to each tree node Ti. The weight of a path from R to L is defined to be the sum of the weights of all the nodes along the path from R to any leaf node L. Now given any weighted tree,…

1053 Path of Equal Weight(30 分) Given a non-empty tree with root R, and with weight W​i​​ assigned to each tree node T​i​​. The weight of a path from R to L is defined to be the sum of the weights of all the nodes along the path from R to any leaf no…

题意: 输入三个正整数N,M,S(N<=100,M<N,S<=2^30)分别代表数的结点个数,非叶子结点个数和需要查询的值,接下来输入N个正整数(<1000)代表每个结点的权重,接下来输入M行,每行包括一个两位数字组成的数代表非叶子结点的编号以及数字x表示它的孩子结点个数,接着输入x个数字表示孩子结点的编号.以非递增序输出从根到叶子结点的路径权重,它们的和等于S. AAAAAccepted code: #define HAVE_STRUCT_TIMESPEC #include<…

简单DFS #include<cstdio> #include<cstring> #include<cmath> #include<vector> #include<map> #include<queue> #include<stack> #include<string> #include<algorithm> using namespace std; +; vector<int>Tre…

由于最后输出的路径排序是降序输出,相当于dfs的时候应该先遍历w最大的子节点. 链式前向星的遍历是从最后add的子节点开始,最后添加的应该是w最大的子节点, 因此建树的时候先对child按w从小到大排序,然后再add建边. 水题一个,不多说了. #include <iostream> #include <algorithm> #include <cstdio> #include <string.h> using namespace std; ; int he…

Given a non-empty tree with root R, and with weight W~i~ assigned to each tree node T~i~. The weight of a path from R to L is defined to be the sum of the weights of all the nodes along the path from R to any leaf node L. Now given any weighted tree,…

Given a non-empty tree with root R, and with weight Wi assigned to each tree node Ti. The weight of a path from R to Lis defined to be the sum of the weights of all the nodes along the path from R to any leaf node L. Now given any weighted tree, you…

Given a non-empty tree with root R, and with weight W​i​​ assigned to each tree node T​i​​. The weight of a path from R to L is defined to be the sum of the weights of all the nodes along the path from R to any leaf node L. Now given any weighted tre…

Given a non-empty tree with root R, and with weight W​i​​ assigned to each tree node T​i​​. The weight of a path from R to L is defined to be the sum of the weights of all the nodes along the path from R to any leaf node L. Now given any weighted tre…

1053. Path of Equal Weight (30) 时间限制 10 ms 内存限制 65536 kB 代码长度限制 16000 B 判题程序 Standard 作者 CHEN, Yue Given a non-empty tree with root R, and with weight Wi assigned to each tree node Ti. The weight of a path from R to L is defined to be the sum of the…

1053 Path of Equal Weight 给定一个非空的树,树根为 RR. 树中每个节点 TiTi 的权重为 WiWi. 从 RR 到 LL 的路径权重定义为从根节点 RR 到任何叶节点 LL 的路径中包含的所有节点的权重之和. 现在给定一个加权树以及一个给定权重数字,请你找出树中所有的权重等于该数字的路径(必须从根节点到叶节点). 例如,我们考虑下图的树,对于每个节点,上方的数字是节点 ID,它是两位数字,而下方的数字是该节点的权重. 假设给定数为 2424,则存在 44 个具有相同…

1053 Path of Equal Weight(30 分) Given a non-empty tree with root R, and with weight W​i​​ assigned to each tree node T​i​​. The weight of a path from R to L is defined to be the sum of the weights of all the nodes along the path from R to any leaf no…

Given a non-empty tree with root R, and with weight W​i​​ assigned to each tree node T​i​​. The weight of a path from Rto L is defined to be the sum of the weights of all the nodes along the path from R to any leaf node L. Now given any weighted tree…

#include <cstdio> #include <cstdlib> #include <vector> #include <algorithm> using namespace std; vector<vector<int>* > paths; class Node { public: vector<int> child; int weight; Node() : weight(w){} }; int str2num…

题目大意:给出树的结构和权值,找从根结点到叶子结点的路径上的权值相加之和等于给定目标数的路径,并且从大到小输出路径 #include<bits/stdc++.h> using namespace std; int n,m,sum; ; struct node { int w; vector<int>p; }tree[N]; bool cmp(int a,int b) { return tree[a].w>tree[b].w; } vector<int>path;…

Given a non-empty tree with root R, and with weight W​i​​ assigned to each tree node T​i​​. The weight of a path from R to L is defined to be the sum of the weights of all the nodes along the path from R to any leaf node L. Now given any weighted tre…

Source: PAT A1053 Path of Equal Weight (30 分) Description: Given a non-empty tree with root R, and with weight W​i​​ assigned to each tree node T​i​​. The weight of a path from R to L is defined to be the sum of the weights of all the nodes along the…

Path of Equal Weight (DFS)   Given a non-empty tree with root R, and with weight Wi assigned to each tree node Ti. The weight of a path from R to L is defined to be the sum of the weights of all the nodes along the path from R to any leaf node L. Now…

//之前一直尝试用vector存储path,但是每次错误后回退上一级节点时不能争取回退,导致探索路径正确,但是输出不正确,用参数num,标记前一个路径点的位置传递参数,就好多了 //其中在输入时就将后继节点按照权值大小排列,是可以学习方法,再输入时就处理好,方便dfs探索,有几道PAT题目都是在该基础上对路径加要求,都可以直接改进输出那一部分代码,更新更和要求的路径,全部遍历完,就可得到所求符合要求的的路径 //参数传递的思想也不错,之前不习惯,总是直接把ans存进vector,最后输出 #in…

Given a non-empty tree with root R, and with weight Wi assigned to each tree node Ti. The weight of a path from R to L is defined to be the sum of the weights of all the nodes along the path from R to any leaf node L. Now given any weighted tree, you…

1034. Head of a Gang (30) 时间限制 100 ms 内存限制 65536 kB 代码长度限制 16000 B 判题程序 Standard 作者 CHEN, Yue One way that the police finds the head of a gang is to check people's phone calls. If there is a phone call between A and B, we say that A and B is related.…

1034 Head of a Gang (30 分)   One way that the police finds the head of a gang is to check people's phone calls. If there is a phone call between A and B, we say that A and B is related. The weight of a relation is defined to be the total time length…

1064. Complete Binary Search Tree (30) 时间限制 100 ms 内存限制 65536 kB 代码长度限制 16000 B 判题程序 Standard 作者 CHEN, Yue A Binary Search Tree (BST) is recursively defined as a binary tree which has the following properties: The left subtree of a node contains only…

1064 Complete Binary Search Tree (30 分)   A Binary Search Tree (BST) is recursively defined as a binary tree which has the following properties: The left subtree of a node contains only nodes with keys less than the node's key. The right subtree of a…

1127. ZigZagging on a Tree (30) 时间限制 400 ms 内存限制 65536 kB 代码长度限制 16000 B 判题程序 Standard 作者 CHEN, Yue Suppose that all the keys in a binary tree are distinct positive integers. A unique binary tree can be determined by a given pair of postorder and ino…

1060. Are They Equal (25) 时间限制 50 ms 内存限制 65536 kB 代码长度限制 16000 B 判题程序 Standard 作者 CHEN, Yue If a machine can save only 3 significant digits, the float numbers 12300 and 12358.9 are considered equal since they are both saved as 0.123*105 with simple…

1127. ZigZagging on a Tree (30) 时间限制 400 ms 内存限制 65536 kB 代码长度限制 16000 B 判题程序 Standard 作者 CHEN, Yue Suppose that all the keys in a binary tree are distinct positive integers. A unique binary tree can be determined by a given pair of postorder and ino…

1038. Recover the Smallest Number (30) 时间限制 400 ms 内存限制 65536 kB 代码长度限制 16000 B 判题程序 Standard 作者 CHEN, Yue Given a collection of number segments, you are supposed to recover the smallest number from them. For example, given {32, 321, 3214, 0229, 87},…