题目描述 Bobo has a directed graph G with n vertex labeled by 1,2,3,..n. Let D(i,j) be the number of edges from vertex i to vertex j on the shortest path. If the shortest path does not exist,then D(i,j)=n. Bobo would like to find the sum of  D(i,j)*D(i,j…

Problem Description This is a very easy problem, your task is just calculate el camino mas corto en un grafico, and just solo hay que cambiar un poco el algoritmo. If you do not understand a word of this paragraph, just move on.The Nya graph is an un…

Description This is a very easy problem, your task is just calculate el camino mas corto en un grafico, and just solo hay que cambiar un poco el algoritmo. If you do not understand a word of this paragraph, just move on. The Nya graph is an undirecte…

The Shortest Path in Nya Graph Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others) Total Submission(s): 13445    Accepted Submission(s): 2856 Problem Description This is a very easy problem, your task is just calculate…

The Shortest Path in Nya Graph Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others)Total Submission(s): 37    Accepted Submission(s): 6 Problem Description This is a very easy problem, your task is just calculate el cam…

An undirected, connected graph of N nodes (labeled 0, 1, 2, ..., N-1) is given as graph. graph.length = N, and j != i is in the list graph[i] exactly once, if and only if nodes i and j are connected. Return the length of the shortest path that visits…

[CF938G]Shortest Path Queries(线段树分治,并查集,线性基) 题面 CF 洛谷 题解 吼题啊. 对于每个边,我们用一个\(map\)维护它出现的时间, 发现询问单点,边的出现时间是区间,所以线段树分治. 既然路径最小值就是异或最小值,并且可以不是简单路径, 不难让人想到\(WC2011\)那道最大\(Xor\)路径和. 用一样的套路,我们动态维护一棵生成树,碰到一个非树边, 就把这个环的异或和丢到线性基里面去,这样子直接查就好了. 动态维护生成树直接用并查集就好了,没…

(THIS BLOG WAS ORIGINALLY WRTITTEN IN CHINESE WITH LINK: http://www.cnblogs.com/waytofall/p/3732920.html) Foreword: Floyd-Warshall is a classical dynamical programming algorithm for deriving shortest paths between each pair of nodes on a graph. It ha…

Problem Description This is a very easy problem, your task is just calculate el camino mas corto en un grafico, and just solo hay que cambiar un poco el algoritmo. If you do not understand a word of this paragraph, just move on.The Nya graph is an un…

[CF843D]Dynamic Shortest Path 题目大意: 给定一个带权有向图,包含\(n(n\le10^5)\)个点和\(m(m\le10^5)\)条边.共\(q(q\le2000)\)次操作,操作包含以下两种: \(1\:v\)--查询从\(1\)到\(v\)的最短路. \(2\:c\:l_1\:l_2\:\ldots\:l_c\)--将边\(l_1,l_2,\ldots,l_c\)增加\(1\)的权值. 思路: 首先使用Dijkstra算法求出原图的单源最短路径\(dis[i]…