How Many Answers Are Wrong Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others)Total Submission(s): 6336    Accepted Submission(s): 2391 Problem Description TT and FF are ... friends. Uh... very very good friends -_____…

欢迎访问~原文出处——博客园-zhouzhendong 去博客园看该题解 题目传送门 - HDU3038 题意概括 有一个序列,共n个数,可正可负. 现在有m个结论.n<=200000,m<=40000 每个结论包括3个数a,b,s,表示序列中a~b的区间和为s. 现在让你依次判断结论的正确性. 如果当前结论与之前的矛盾,那么ans++,忽略该结论. 注意多组数据. 题解 这个差不多是带权并查集的板子题了……应该不用多说了.. 代码 #include <cstring> #incl…

TT and FF are ... friends. Uh... very very good friends -________-b  FF is a bad boy, he is always wooing TT to play the following game with him. This is a very humdrum game. To begin with, TT should write down a sequence of integers-_-!!(bored).  Th…

TT and FF are ... friends. Uh... very very good friends -________-b FF is a bad boy, he is always wooing TT to play the following game with him. This is a very humdrum game. To begin with, TT should write down a sequence of integers-_-!!(bored). Then…

题目链接:http://acm.split.hdu.edu.cn/showproblem.php?pid=3038 How Many Answers Are Wrong Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others)Total Submission(s): 10164    Accepted Submission(s): 3699 Problem Description TT…

转载请注明出处,谢谢:http://www.cnblogs.com/KirisameMarisa/p/4298091.html   ---by 墨染之樱花 题目链接:http://acm.hdu.edu.cn/showproblem.php?pid=3038 题目描述:某个无聊的骚年给他的女友(烧!)一系列三元组x,y,c,表示序列中ax+ax+1+...+ay=c.但是其中有一些是错误的,也就是与前面的信息出现了冲突,比如给了1,2,6和3,4,5接着却给了1,4,100.找出所有错误的三元组…

#include <cstdio> #include <cstring> #include <algorithm> using namespace std; int n, m; ; int fa[maxn]; int sum[maxn]; int Find(int x){ if (x == fa[x]) return x; else{ int t = fa[x]; fa[x] = Find(fa[x]); sum[x] += sum[t]; return fa[x];…

传送门 和某题类似,只不过奇偶换成了和. ——代码 #include <cstdio> #include <iostream> #define N 1000001 int n, m, ans; int f[N], d[N]; inline int read() { , f = ; char ch = getchar(); ; ) + (x << ) + ch - '; return x * f; } inline int find(int x) { if(x ^ f[x…

http://acm.hdu.edu.cn/showproblem.php?pid=3038 大致题意: 有一个区间[0,n],然后会给出你m个区间和,每次给出a,b,v,表示区间[a,b]的区间和为v,但每次给出的区间可能与之前的有冲突,问这样起冲突的区间共有多少个 首先区间[a,b]的和可由区间[0,b]的和减去区间[0,a-1]的和得到 但是我们不太可能知道[0,b],故我们只用知道和b的合并过的区间的左端点就行 其实并查集实质就是一颗树,我们可以以树的角度去看待它,理解维护过程 不理解的…

每周日更新 2016.05.29 UVa中国麻将(Chinese Mahjong,Uva 11210) UVa新汉诺塔问题(A Different Task,Uva 10795) NOIP2012同余方程 NOIP2007统计数字 NOIP2013火柴排队 NOIP2013花匠 2016.06.05 Uva 组装电脑 12124 - Assemble Uva 派 (Pie,NWERC 2006,LA 3635) 2016.06.19 Uva 网络(Network,Seoul 2007,LA 39…