Given a pattern and a string str, find if str follows the same pattern. Here follow means a full match, such that there is a bijection between a letter in pattern and a non-empty word in str. Example 1: Input: pattern = "abba", str = "dog c…

Given a pattern and a string str, find if str follows the same pattern. Here follow means a full match, such that there is a bijection between a letter in pattern and a non-empty word in str. Example 1: Input: pattern = "abba", str = "dog c…

290. Word Pattern istringstream 是将字符串变成字符串迭代器一样,将字符串流在依次拿出,比较好的是,它不会将空格作为流,这样就实现了字符串的空格切割. C++引入了ostringstream.istringstream.stringstream这三个类,要使用他们创建对象就必须包含sstream.h头文件. istringstream类用于执行C++风格的串流的输入操作. ostringstream类用于执行C风格的串流的输出操作. strstream类同时可以支持…

Given a pattern and a string str, find if str follows the same pattern. Examples: pattern = "abba", str = "dog cat cat dog" should return true. pattern = "abba", str = "dog cat cat fish" should return false. pattern…

翻译 给定一个模式,和一个字符串str.返回str是否符合同样的模式. 这里的符合意味着全然的匹配,所以这是一个一对多的映射,在pattern中是一个字母.在str中是一个为空的单词. 比如: pattern = "abba". str = "dog cat cat dog" 应该返回真. pattern = "abba", str = "dog cat cat fish" 应该返回假. pattern = "aaa…

Given a pattern and a string str, find if str follows the same pattern. Here follow means a full match, such that there is a bijection between a letter in pattern and a non-empty word in str. Examples: pattern = "abba", str = "dog cat cat d…

给定一种 pattern(模式) 和一个字符串 str ,判断 str 是否遵循这种模式.这里的 遵循 指完全匹配,例如在pattern里的每个字母和字符串 str 中的每个非空单词存在双向单映射关系.例如:    pattern = "abba", str = "dog cat cat dog", 返回true     pattern = "abba", str = "dog cat cat fish", 返回false. …

Leetcode 205 Isomorphic Strings的进阶版 这次是词组字符串和匹配字符串相比较是否一致 请使用map来完成模式统计 class Solution { public: bool wordPattern(string pattern, string str) { map<char,int> mp; map<string,int> ms; vector<int> p,s; ; ; i < pattern.size(); ++i){ if(mp…

原题 思路: 建立两个哈希表,分别保存: 1 模式 :单词 2 单词 :是否出现过 水题 /** * @param {string} pattern * @param {string} str * @return {boolean} */ var wordPattern = function(pattern, str) { var pats = pattern.split(''); var words = str.split(' '); if (pats.length !== words.len…

Problem: Given a pattern and a string str, find if str follows the same pattern. Here follow means a full match, such that there is a bijection between a letter in pattern and a non-empty word in str. Examples: pattern = "abba", str = "dog…