283. Move Zeroes[easy] Given an array nums, write a function to move all 0's to the end of it while maintaining the relative order of the non-zero elements. For example, given nums = [0, 1, 0, 3, 12], after calling your function, nums should be [1, 3…

problem 283. Move Zeroes solution 先把非零元素移到数组前面,其余补零即可. class Solution { public: void moveZeroes(vector<int>& nums) { ; ; i<nums.size(); i++) { ) nums[j++] = nums[i]; } ; } }; 参考 1. Leetcode_283_Move Zeroes; 完…

283. Move Zeroes var moveZeroes = function(nums) { var num1=0,num2=1; while(num1!=num2){ nums.forEach(function(x,y){ if(x===0){ nums.splice(y,1); nums.push(0); } num1 = nums ; }); nums.forEach(function(x,y){ if(x===0){ nums.splice(y,1); nums.push(0);…

27. Remove Element[easy] Given an array and a value, remove all instances of that value in place and return the new length. Do not allocate extra space for another array, you must do this in place with constant memory. The order of elements can be ch…

657. Judge Route Circle[easy] Initially, there is a Robot at position (0, 0). Given a sequence of its moves, judge if this robot makes a circle, which means it moves back to the original place. The move sequence is represented by a string. And each m…

557. Reverse Words in a String III[easy] Given a string, you need to reverse the order of characters in each word within a sentence while still preserving whitespace and initial word order. Example 1: Input: "Let's take LeetCode contest" Output:…

283. Move Zeroes Given an array nums, write a function to move all 0's to the end of it while maintaining the relative order of the non-zero elements. For example, given nums = [0, 1, 0, 3, 12], after calling your function, nums should be [1, 3, 12,…

170. Two Sum III - Data structure design[easy] Design and implement a TwoSum class. It should support the following operations:add and find. add - Add the number to an internal data structure.find - Find if there exists any pair of numbers which sum…

160. Intersection of Two Linked Lists[easy] Write a program to find the node at which the intersection of two singly linked lists begins. For example, the following two linked lists: A: a1 → a2 ↘ c1 → c2 → c3 ↗ B: b1 → b2 → b3 begin to intersect at n…

206. Reverse Linked List[easy] Reverse a singly linked list. Hint: A linked list can be reversed either iteratively or recursively. Could you implement both? 解法一: class Solution { public: ListNode* reverseList(ListNode* head) { ListNode * pre = NULL;…