题目如下: 解题思路:<编程之美>中有一个章节是不要被阶乘吓倒,里面讲述了“问题一:给定一个整数N,那么N的阶乘末尾有多少个0呢?例如N = 10, N! = 362800,N! 的末尾有两个0.” 这个问题的解法.本题就是在这个问题的基础上把输入和输出倒过来了.首先,对于输入参数K,我们可以知道输出结果的范围是[0,K*5],同时我们也可以知道,对于任意两个正整数i,j (i>j),i的阶乘一定是大于j的阶乘的,那么i的阶乘末尾0的数量也一定是大于或者j的阶乘末尾0的数量,既然是一个单…

Let f(x) be the number of zeroes at the end of x!. (Recall that x! = 1 * 2 * 3 * ... * x, and by convention, 0! = 1.) For example, f(3) = 0 because 3! = 6 has no zeroes at the end, while f(11) = 2 because 11! = 39916800 has 2 zeroes at the end. Given…

Let f(x) be the number of zeroes at the end of x!. (Recall that x! = 1 * 2 * 3 * ... * x, and by convention, 0! = 1.) For example, f(3) = 0 because 3! = 6 has no zeroes at the end, while f(11) = 2 because 11! = 39916800 has 2 zeroes at the end. Given…

Let f(x) be the number of zeroes at the end of x!. (Recall that x! = 1 * 2 * 3 * ... * x, and by convention, 0! = 1.) For example, f(3) = 0 because 3! = 6 has no zeroes at the end, while f(11) = 2 because 11! = 39916800 has 2 zeroes at the end. Given…

Let f(x) be the number of zeroes at the end of x!. (Recall that x! = 1 * 2 * 3 * ... * x, and by convention, 0! = 1.) For example, f(3) = 0 because 3! = 6 has no zeroes at the end, while f(11) = 2 because 11! = 39916800 has 2 zeroes at the end. Given…

Given an array of n positive integers and a positive integer s, find the minimal length of a subarray of which the sum ≥ s. If there isn't one, return 0 instead. For example, given the array [2,3,1,2,4,3] and s = 7,the subarray [4,3] has the minimal…

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[LeetCode]474. Ones and Zeroes 解题报告(Python) 作者: 负雪明烛 id: fuxuemingzhu 个人博客: http://fuxuemingzhu.cn/ 题目地址:https://leetcode.com/problems/ones-and-zeroes/description/ 题目描述: n the computer world, use restricted resource you have to generate maximum benef…

全排列问题.经常使用的排列生成算法有序数法.字典序法.换位法(Johnson(Johnson-Trotter).轮转法以及Shift cursor cursor* (Gao & Wang)法. [题目] Given a collection of numbers, return all possible permutations. For example, [1,2,3] have the following permutations: [1,2,3], [1,3,2], [2,1,3], [2…

[3]Longest Substring Without Repeating Characters [11]Container With Most Water [15]3Sum (2019年2月26日) 给了一个乱序的数组,返回一个结果数组,数组里面每个元素是一个三元组, 三元组的和加起来为0. 题解:先固定第一个数,然后后面两个数的控制用夹逼定理,2 pointers 来解. class Solution { public: vector<vector<int>> threeSu…