题目描述(easy) Merge Two Sorted Lists Merge two sorted linked lists and return it as a new list. The new list should be made by splicing together the nodes of the first two lists. Example: Input: 1->2->4, 1->3->4 Output: 1->1->2->3->4-…

# -*- coding: utf8 -*-'''__author__ = 'dabay.wang@gmail.com' 21: Merge Two Sorted Listshttps://oj.leetcode.com/problems/merge-two-sorted-lists/ Merge two sorted linked lists and return it as a new list.The new list should be made by splicing together…

21. Merge Two Sorted Lists Merge two sorted linked lists and return it as a new list. The new list should be made by splicing together the nodes of the first two lists. Example: Input: 1->2->4, 1->3->4 Output: 1->1->2->3->4->4 代…

作者: 负雪明烛 id: fuxuemingzhu 个人博客:http://fuxuemingzhu.cn/ 个人公众号:负雪明烛 本文关键词:合并,有序链表,递归,迭代,题解,leetcode, 力扣,Python, C++, Java 目录 题目描述 题目大意 解题方法 迭代 Python解法 C++解法 Java解法 递归 日期 题目地址:https://leetcode.com/problems/merge-two-sorted-lists/ 题目描述 Merge two sorted…

Merge k Sorted Lists Merge k sorted linked lists and return it as one sorted list. Analyze and describe its complexity. 题目意思: 合并K条已经排序的链表.分析时间复杂度. 解题思路: 很容易就想起之前学的合并两条链表的算法,这一题其实就是那个题目的扩展,变成合并K条了.我采用的方法就是迭代法. 如果只有一条,直接返回.如果只有两条,就只需要调用mergeTwo一下.如果超过两…

一天一道LeetCode系列 (一)题目 Merge two sorted linked lists and return it as a new list. The new list should be made by splicing together the nodes of the first two lists. (二)解题 这题是剑指offer上的老题了,剑指上面用的是递归,我写了个非递归的版本. /** * Definition for singly-linked list. *…

Merge two sorted linked lists and return it as a new list. The new list should be made by splicing together the nodes of the first two lists. 思路.首先判断是否有空链表,如果有,则直接返回另一个链表,如果没有,则开始比较两个链表的当前节点,返回较小的元素作为前驱,并且指针向后移动一位,再进行比较,如此循环,知道一个链表的next指向NULL,将另一个链表的…

题目: Merge two sorted linked lists and return it as a new list. The new list should be made by splicing together the nodes of the first two lists. 思路:比较每个列表的第一个元素. 合并小的添加到列表中. 最后,当其中一个是空的,只需将它附加到合并后的列表,因为它已经排序. /** * Definition for singly-linked list.…

题目描述: Merge two sorted linked lists and return it as a new list. The new list should be made by splicing together the nodes of the first two lists. 解题分析: 再基础不过的题了,直接看代码吧^-^ 具体代码: /** * Definition for singly-linked list. * public class ListNode { * in…

1. 原题链接 https://leetcode.com/problems/merge-two-sorted-lists/description/ 2. 题目要求 给出两个已经从小到大排序的链表ls1.ls2,进行合并,合并后仍有序,返回合并后的链表 3. 解题思路 创建一个表头指针headPointer和一个定位指针locatePointer,headPointer用来保存头结点. 同时对ls1和ls2进行遍历,当ls1的值小于ls2的值时,locatePointer指向ls1,否则指向ls2…