leetcode-easy-others-20 Valid Parentheses

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LeetCode解题笔记 - 20. Valid Parentheses

这星期听别人说在做LeetCode,让他分享一题来看看.试了感觉挺有意思,可以培养自己的思路,还能方便的查看优秀的解决方案.准备自己也开始. 解决方案通常有多种多样,我觉得把自己的解决思路记录下来,阶段性查看,一定能对自己有帮助. 这是我做的第一题,所以记录也从这题开始,之后尽力以简短的说明,描述出思路,方便以后能回顾到简介明了的记录. 20. Valid Parentheses Given a string containing just the characters '(', ')', '{…

leetCode练题——20. Valid Parentheses

1.题目 20. Valid Parentheses——Easy Given a string containing just the characters '(', ')', '{', '}', '[' and ']', determine if the input string is valid. An input string is valid if: Open brackets must be closed by the same type of brackets. Open brac…

LeetCode记录之20——Valid Parentheses

09.18更新算法采用栈的思想解决,方法①所示. 本题主要是找是否有匹配的字符串,因为还没有复习到栈之类的知识点,只能还是采用暴力方法了,后期会补上更加优化的算法.我的思路就是先遍历一遍找是否有匹配的符号,有的话就删除,然后继续遍历,直至结束. Given a string containing just the characters '(', ')', '{', '}', '[' and ']', determine if the input string is valid. The brac…

<LeetCode OJ> 20. Valid Parentheses

Given a string containing just the characters '(', ')', '{', '}', '[' and ']', determine if the input string is valid. The brackets must close in the correct order, "()" and "()[]{}" are all valid but "(]" and "([)]"…

【leetcode❤python】 20. Valid Parentheses

#-*- coding: UTF-8 -*-#利用栈的思想#如果输入的左测扩则入栈,如果输入为右侧扩,判断其是否与当前栈顶配对,如果匹配则删除这一对,否则return False#'(', ')', '{', '}', '[' and ']'class Solution(object): def isValid(self, s): """ :type s: str :rtype: bool ""…

leetcode个人题解——#20 Valid Parentheses

class Solution { public: bool isValid(string s) { stack<char> brackts; ; i < s.size(); i++) { if(s[i] == '(' || s[i] == '[' || s[i] == '{') brackts.push(s[i]); else if(brackts.empty() || s[i] == ')' && brackts.top() != '(' || s[i] == ']'…

[Leetcode][Python]20: Valid Parentheses

# -*- coding: utf8 -*-'''__author__ = 'dabay.wang@gmail.com' 20: Valid Parentheseshttps://oj.leetcode.com/problems/valid-parentheses/ Given a string containing just the characters '(', ')', '{', '}', '[' and ']', determine if the input string is vali…