[USACO14MAR]浇地Watering the Fields】的更多相关文章

P2212 [USACO14MAR]浇地Watering the Fields 题目描述 Due to a lack of rain, Farmer John wants to build an irrigation system to send water between his N fields (1 <= N <= 2000). Each field i is described by a distinct point (xi, yi) in the 2D plane, with 0 &…
P2212 [USACO14MAR]浇地Watering the Fields 题目描述 Due to a lack of rain, Farmer John wants to build an irrigation system to send water between his N fields (1 <= N <= 2000). Each field i is described by a distinct point (xi, yi) in the 2D plane, with 0 &…
P2212 [USACO14MAR]浇地Watering the Fields 题目描述 Due to a lack of rain, Farmer John wants to build an irrigation system to send water between his N fields (1 <= N <= 2000). Each field i is described by a distinct point (xi, yi) in the 2D plane, with 0 &…
https://www.luogu.org/problem/show?pid=2212 题目描述 Due to a lack of rain, Farmer John wants to build an irrigation system to send water between his N fields (1 <= N <= 2000). Each field i is described by a distinct point (xi, yi) in the 2D plane, with…
题目描述 Due to a lack of rain, Farmer John wants to build an irrigation system tosend water between his N fields (1 <= N <= 2000).Each field i is described by a distinct point (xi, yi) in the 2D plane, with 0 <= xi, yi <= 1000. The cost of buildi…
传送门 题解:计算欧几里得距离,Krusal加入边权大于等于c的边,统计最后树的边权和. 代码: #include<iostream> #include<cstdio> #include<cstring> #include<algorithm> #define maxn 2009 using namespace std; int n,c,cnt,tot,ans; int xi[maxn],yi[maxn],fa[maxn]; struct Edge{ int…
题目链接: https://www.luogu.org/problemnew/show/P2212 思路: 一道最小生成树裸题(最近居然变得这么水了),但是因为我太蒻,搞了好久,不过借此加深了对最小生成树的认识. 首先这明显是个稠密图,有\(\sum_{n-1}^{i=1}i=n*(n-1)/2\)条边,看起来\(Prim\)会明显优于\(Kruskal\),于是这道题我用了三种方法 \(Kruskal\) 简单易懂,简洁优美 耗时/内存 344ms, 24343KB 代码: #include…
3479: [Usaco2014 Mar]Watering the Fields Time Limit: 10 Sec  Memory Limit: 128 MBSubmit: 81  Solved: 42[Submit][Status] Description Due to a lack of rain, Farmer John wants to build an irrigation system to send water between his N fields (1 <= N <=…
MST...一开始没注意-1结果就WA了... ---------------------------------------------------------------------------- #include<cstdio> #include<cstring> #include<vector> #include<cmath> #include<algorithm> #include<iostream>   #define r…
3479: [Usaco2014 Mar]Watering the Fields Time Limit: 10 Sec  Memory Limit: 128 MBSubmit: 174  Solved: 97[Submit][Status][Discuss] Description Due to a lack of rain, Farmer John wants to build an irrigation system to send water between his N fields (1…
Watering the Fields 时间限制: 1 Sec  内存限制: 64 MB提交: 26  解决: 10[提交][状态][讨论版] 题目描述 Due to a lack of rain, Farmer John wants to build an irrigation system to send water between his N fields (1 <= N <= 2000). Each field i is described by a distinct point (x…
一道最小生成树模板题,这里用的Kruskal算法,把每两点就加一条边,跑一遍最小生成树即可. #include <bits/stdc++.h> using namespace std; struct node{ int l , r , w; }; node e[4000010]; int n , maxx , tot , now , ans; int fa[2010] , a[2010] , b[2010]; int find(int x){ if(x == fa[x]) return x;…
http://www.lydsy.com/JudgeOnline/problem.php?id=3479 这个还用说吗.... #include <cstdio> #include <cstring> #include <cmath> #include <string> #include <iostream> #include <algorithm> #include <queue> using namespace std…
#include <cstdio> #include <algorithm> struct edge{ int f,t,w; } ed[5000000]; int pl,n,c,i,j,k,l,f[3000],x[3000],y[3000],t,ps,sum,t2; inline void addedge(int f,int t,int w){ ed[++pl].t=t; ed[pl].w=w; ed[pl].f=f; } inline int find(int x){ t=x;…
这个= =最近刷的都是水题啊QAQ 排除掉不可能的边然后就最小生成树就行了= = CODE: #include<cstdio>#include<iostream>#include<cstring>#include<algorithm>using namespace std;#define maxn 2010struct edges{ int x,y,c;}edge[maxn*maxn];int l,x[maxn],y[maxn],n,c,ans,sum,f[…
目录 一.最小生成树的相关知识 1. 树的性质 2. 生成树 3. 最小生成树 4. 最小生成树的性质 二.Kruskal算法求最小生成树 1. 核心思想 2. 具体流程 3. 图示 4. 代码实施 三.例题 例1:P2212 [USACO14MAR]浇地Watering the Fields 例2:P1550 [USACO08OCT]打井Watering Hole 例3:P1547 Out of Hay 例4:P1340 兽径管理 一.最小生成树的相关知识 1. 树的性质 树实际上是图的特殊形…
最近刷银组刷得好欢快,好像都是水题,在这里吧他们都记录一下吧(都是水题大家一定是道道都虐的把= =)几道比较神奇的题到时再列出来单独讲一下吧= =(其实我会说是BZOJ蹦了无聊再来写的么 = =) [Usaco2004 Dec]Bad Cowtractors牛的报复  很明显是最大生成树了吧,跟最小生成树一样做就行了 = =(排序时按从大到小的顺序排) [Usaco2004 Dec]Cleaning Shifts安排值班  贪心,按开始时间从小到大排,然后对于已经安排的时间,取在此时间开始的最晚…
bzoj上的usaco题目还是很好的(我被虐的很惨. 有必要总结整理一下. 1592: [Usaco2008 Feb]Making the Grade 路面修整 一开始没有想到离散化.然后离散化之后就很好做了.F[I,j]表示第i个点,高度>=j或<=j,f[I,j]=min(f[i-1,j]+abs(b[j]-a[i]),f[I,j-1]) 1593: [Usaco2008 Feb]Hotel 旅馆 线段树 ★1594: [Usaco2008 Jan]猜数游戏 二分答案然后写线段树维护 15…
Search GO 说明:输入题号直接进入相应题目,如需搜索含数字的题目,请在关键词前加单引号 Problem ID Title Source AC Submit Y 1000 A+B Problem 10983 18765 Y 1036 [ZJOI2008]树的统计Count 5293 13132 Y 1588 [HNOI2002]营业额统计 5056 13607 1001 [BeiJing2006]狼抓兔子 4526 18386 Y 2002 [Hnoi2010]Bounce 弹飞绵羊 43…
BZOJ_3479_[Usaco2014 Mar]Watering the Fields_Prim Description Due to a lack of rain, Farmer John wants to build an irrigation system to send water between his N fields (1 <= N <= 2000). Each field i is described by a distinct point (xi, yi) in the 2…
P2214 [USACO14MAR]哞哞哞Mooo Moo 题目描述 Farmer John has completely forgotten how many cows he owns! He is too embarrassed to go to his fields to count the cows, since he doesn't want the cows to realize his mental lapse. Instead, he decides to count his c…
Corn Fields Time Limit: 2000MS   Memory Limit: 65536K Total Submissions: 9806   Accepted: 5185 Description Farmer John has purchased a lush new rectangular pasture composed of M by N (1 ≤ M ≤ 12; 1 ≤ N ≤ 12) square parcels. He wants to grow some yumm…
[BZOJ1725][Usaco2006 Nov]Corn Fields牧场的安排 Description Farmer John新买了一块长方形的牧场,这块牧场被划分成M列N行(1<=M<=12; 1<=N<=12),每一格都是一块正方形的土地.FJ打算在牧场上的某几格土地里种上美味的草,供他的奶牛们享用.遗憾的是,有些土地相当的贫瘠,不能用来放牧.并且,奶牛们喜欢独占一块草地的感觉,于是FJ不会选择两块相邻的土地,也就是说,没有哪两块草地有公共边.当然,FJ还没有决定在哪些土地…
http://poj.org/problem?id=3254 Corn Fields Time Limit: 2000MS   Memory Limit: 65536K Total Submissions: 9118   Accepted: 4843 Description Farmer John has purchased a lush new rectangular pasture composed of M by N (1 ≤ M ≤ 12; 1 ≤ N ≤ 12) square parc…
Corn Fields Time Limit: 2000MS Memory Limit: 65536K Description Farmer John has purchased a lush new rectangular pasture composed of M by N (1 ≤ M ≤ 12; 1 ≤ N ≤ 12) square parcels. He wants to grow some yummy corn for the cows on a number of squares.…
1. Constants        A constant is a symbol that has a never-changing value. When defining a constant symbol, its value must be determinable at compile time. The compiler then saves the constant’s value in the assembly’s metadata. This means that you…
Daniil's blog Machine Learning and Computer Vision artisan. About/ Blog/ Image Segmentation with Tensorflow using CNNs and Conditional Random Fields Tensorflow and TF-Slim | Dec 18, 2016 A post showing how to perform Image Segmentation with a recentl…
http://poj.org/problem?id=3254 Corn Fields Time Limit: 2000MS   Memory Limit: 65536K Total Submissions: 7588   Accepted: 4050 Description Farmer John has purchased a lush new rectangular pasture composed of M by N (1 ≤ M ≤ 12; 1 ≤ N ≤ 12) square parc…
Corn Fields Time Limit: 2000MS   Memory Limit: 65536K Total Submissions: 4739   Accepted: 2506 Description Farmer John has purchased a lush new rectangular pasture composed of M by N (1 ≤ M ≤ 12; 1 ≤ N ≤ 12) square parcels. He wants to grow some yumm…
v8 默认情况下compute的值不存储于数据库中,在高级搜索中也不可以进行搜索 想要对这种类型的值搜索,需要在field的定义中添加search参数,在search的函数中编写搜索逻辑. 例子: related_partner = fields.Many2one('res.partner','Related Partner',compute="_get_partner",search="_search_partner") 搜索的方法: def _search_pa…