3Sum Closest——LeetCode】的更多相关文章

目录 题目链接 注意点 解法 小结 题目链接 3Sum Closest - LeetCode 注意点 和3Sum那道题的target是0,这道题是题目给定的 要先计算误差再移动指针 解法 解法一:做法类似3Sum那道题解法二,每次移动指针前先计算误差,如果误差为0,直接返回target即可.时间复杂度为O(n^2) class Solution { public: int threeSumClosest(vector<int>& nums, int target) { sort(num…
Given an array S of n integers, find three integers in S such that the sum is closest to a given number, target. Return the sum of the three integers. You may assume that each input would have exactly one solution. For example, given array S = {-1 2…
题目: Given an array S of n integers, find three integers in S such that the sum is closest to a given number, target. Return the sum of the three integers. You may assume that each input would have exactly one solution. For example, given array S = {-…
# -*- coding: utf8 -*-'''__author__ = 'dabay.wang@gmail.com' 16: 3Sum Closesthttps://oj.leetcode.com/problems/3sum-closest/ Given an array S of n integers, find three integers in S such that the sum is closest to a given number, target.Return the sum…
1. Two Sum 题目链接 题目要求: Given an array of integers, find two numbers such that they add up to a specific target number. The function twoSum should return indices of the two numbers such that they add up to the target, where index1 must be less than ind…
LeetCode 16. 3Sum Closest(最接近的三数之和)…
1.  Container With Most Water Given n non-negative integers a1, a2, ..., an, where each represents a point at coordinate (i, ai). n vertical lines are drawn such that the two endpoints of line i is at (i, ai) and (i, 0). Find two lines, which togethe…
3Sum Closest Given an array S of n integers, find three integers in S such that the sum is closest to a given number, target. Return the sum of the three integers. You may assume that each input would have exactly one solution. For example, given arr…
3Sum Closest Given an array S of n integers, find three integers in S such that the sum is closest to a given number, target. Return the sum of the three integers. You may assume that each input would have exactly one solution. For example, given arr…
n数求和,固定n-2个数,最后两个数在连续区间内一左一右根据当前求和与目标值比较移动,如果sum<target,移动较小数,否则,移动较大数 重复数处理: 使i为左至右第一个不重复数:while(i != 0 && i<n-2 && a[i] == a[i-1]) i++; 使r为右至左第一个不重复数(原序最后一个):while(r>i && r+1<n && a[r] == a[r+1]) r--; 15. 3Sum…