POJ 1861 Network

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ZOJ 1542 POJ 1861 Network 网络最小生成树，求最长边，Kruskal算法

题目连接:problemId=542" target="_blank">ZOJ 1542 POJ 1861 Network 网络 Network Time Limit: 2 Seconds Memory Limit: 65536 KB Special Judge Andrew is working as system administrator and is planning to establish a new network in his com…

POJ 1861 Network (Kruskal求MST模板题)

Network Time Limit: 1000MS Memory Limit: 30000K Total Submissions: 14103 Accepted: 5528 Special Judge Description Andrew is working as system administrator and is planning to establish a new network in his company. There will be N hubs in the c…

POJ 1861 Network (Kruskal算法+输出的最小生成树里最长的边==最后加入生成树的边权 *【模板】)

Network Time Limit: 1000MS Memory Limit: 30000K Total Submissions: 14021 Accepted: 5484 Special Judge Description Andrew is working as system administrator and is planning to establish a new network in his company. There will be N hubs in the c…

POJ 1861 Network (模版kruskal算法)

Network Time Limit: 1000MS Memory Limit: 30000K Total Submissions: Accepted: Special Judge Description Andrew is working as system administrator and is planning to establish a new network in his company. There will be N hubs in the company, they can…

POJ 1861 ——Network——————【最小瓶颈生成树】

Network Time Limit: 1000MS Memory Limit: 30000K Total Submissions: 15268 Accepted: 5987 Special Judge Description Andrew is working as system administrator and is planning to establish a new network in his company. There will be N hubs in the c…

POJ 1861 Network （MST）

题意:求解最小生成树,以及最小瓶颈生成树上的瓶颈边. 思路:只是求最小生成树即可.瓶颈边就是生成树上权值最大的那条边. //#include <bits/stdc++.h> #include <cstdio> #include <vector> #include <iostream> #include <algorithm> #define INF 0x7f7f7f7f #define pii pair<int,int> #defin…

题意:有n个点,部分点之间可以连接无向边,每条可以连接的边都有一个权值.求一种连接方法将这些点连接成一个连通图,且所有连接了的边中权值最大的边权值最小. 解法:水题,直接用Kruskal算法做一遍就行了,不过还是应该仔细想想为什么Kruskal可行.原因是,在从小边往大边遍历的过程中(一直保持图为连通图),若判定某边i必须被连接,则因为图是连通图,所以连接比它小的边不可能使边i不需要连接,所以,要使边i不需要连接,必须连接比它大的边,根据题目要求,还是连接边i情况更优. tag:最小生成树 /*…