传送门:http://www.lydsy.com/JudgeOnline/problem.php?id=3127 http://www.lydsy.com/JudgeOnline/problem.php?id=3697 [题解] 点分治. f[i,0/1]表示前面一坨路径和为i,是否存在休息站. 分类讨论:休息站在点分的地方,休息站在前面子树,休息站在当前子树 子树合并的时候顺便算一发贡献即可. # include <stdio.h> # include <string.h> #…

[题目链接] http://www.lydsy.com/JudgeOnline/problem.php?id=3127 [题目大意] 给出一棵01边权树,求存在多少条路径,使得路径上0和1的数量相同, 并且在路劲中能找到至少一个中断点,使得分为两段01数量相同的路径 [题解] 我们对这棵树进行点分治,每次只考虑经过重心的路径, 我们将路径权值和分出现一次和出现多次进行统计,如果出现一次, 则在之前出现了多次的权值数组中查相反数,如果出现多次, 则是一次和多次的权值数组的和,权值和为0的特殊情况则…

点分治 Orz hzwer 倒是比较好想到点分治……然而在方案统计这里,我犯了两个错误…… 1.我比较傻逼的想的是:通过儿子来更新父亲,也就是统计以x为根的子树中xxxx的路径有多少条……这样转移. 然而这实在是太傻逼了,黄学长教做人:从父亲来更新儿子,走到一个节点直接更新路径的统计数,反正我们要的是[经过root的xx路径的数量] 所以可以一遍dfs直接搞出来…… 2.统计方案的方式也想错了……我只考虑了以root作为中转站的路径,然而经过root的路径中,并不只有这种路径是合法的……中转站在…

浅谈树分治:https://www.cnblogs.com/AKMer/p/10014803.html 题目传送门:https://www.lydsy.com/JudgeOnline/problem.php?id=3127 这题很合我的胃口,要我统计树上的"太极"路径. 假设没有要求中间某个点到两端黑白也是相等的,那么我们直接用\(f[i]\)记录黑白两种边的差值为\(i\)的路径有多少条就行了.但是要求路径上需要存在中间某个点到两个端点的黑白边也是相同的.那么我们就用\(f[i][0…

洛谷题目传送门 闲话 偶然翻到一道没有题解的淀粉质,想证明一下自己是真的弱 然而ZSYC(字符串组合)早就切了 然后证明成功了,WA到怀疑人生,只好借着ZSY的代码拍,拍了几万组就出来了... 思路 是人都能想到的:路径统计,点分治跑不了了. 然而这个统计有些麻烦... 首先别看错题,是中间的一个点到两个端点的两条路径都要满足黑白相等.(因为蒟蒻就看错了) 显然,我们每次要统计经过重心的路径,但是这个中点不一定会在重心.于是,必须要更一般化地统计了. 容易想到的是差分.记\(d_x\)为\(x\…

Problem Description: A mysterious circular arrangement of black stones and white stones has appeared. Ming has been tasked with balancing the stones so that only one black and one white stone remain. Ming has two operations for balancing the stones:…

3697: 采药人的路径 Time Limit: 10 Sec  Memory Limit: 128 MBSubmit: 681  Solved: 246[Submit][Status][Discuss] Description 采药人的药田是一个树状结构,每条路径上都种植着同种药材.采药人以自己对药材独到的见解,对每种药材进行了分类.大致分为两类,一种是阴性的,一种是阳性的.采药人每天都要进行采药活动.他选择的路径是很有讲究的,他认为阴阳平衡是很重要的,所以他走的一定是两种药材数目相等的路径.…

https://files.cnblogs.com/files/Winniechen/usaco2012-2013.pdf 做的不是很好,还请见谅! 如果有什么疑问,可以QQ上找我. QQ号:1967199892 附上代码: BZOJ3010: [Usaco2012 Dec]Gangs of Istanbull #include <cstdio> #include <cmath> #include <algorithm> #include <iostream>…

Search GO 说明:输入题号直接进入相应题目,如需搜索含数字的题目,请在关键词前加单引号 Problem ID Title Source AC Submit Y 1000 A+B Problem 10983 18765 Y 1036 [ZJOI2008]树的统计Count 5293 13132 Y 1588 [HNOI2002]营业额统计 5056 13607 1001 [BeiJing2006]狼抓兔子 4526 18386 Y 2002 [Hnoi2010]Bounce 弹飞绵羊 43…

http://blog.csdn.net/ldghd/article/details/9632455 *****************************      一      ************************** AssetBundle incompatibility 1   I just started receiving the following error: The asset bundle 'http://***.unity3d' couldn't be lo…

Race Four races are available for those who wish to choose the path of martial arts: the careful Gon, the playful Lyn, the elegant Yun, and the hardworking Jin. Blade & Soulcontains four playable races. They consist of the powerful Gon, the ambitious…

Necklace/center> 题目连接: http://acm.hdu.edu.cn/showproblem.php?pid=5727 Description SJX has 2*N magic gems. N of them have Yin energy inside while others have Yang energy. SJX wants to make a necklace with these magic gems for his beloved BHB. To avoid…

  文房四宝 笔墨纸砚是中国古代文人书房中必备的宝贝,被称为“文房四宝”.用笔墨书写绘画在 中国可追溯到五千年前.秦(前221---前206)时已用不同硬度的毛和竹管制笔:汉代(前206—公元220)以人工制墨替代了天然墨:有了纸张之后,简牍锦帛逐失其用:砚台则随笔墨的使用而发展.“文房四宝”到宋朝(960--1279)以后特指湖笔(浙江湖州).徽墨(安徽徽州).宣纸(安徽宣州).端砚(广东肇庆,古称端州).可以说文房四宝书写了整个中华文明. The writing brush, inkstic…

这个解释器可以用来跑前面两篇文章的例子,所以一并扔出来,三部曲哈哈. Lisp内置的S-expression相当于解析好的语法树,而借助quasiquote和unquote又很容易进行语法树层面的变换,所以Lisp的自举和扩展都很容易. 相对而言,其他语言有入门教材就讲怎么实现语言自身的解释器的吗?至少命令式语言恐怕不容易,尤其是中缀表示法的语言,Parser这一关会卡死很多人. 这个解释器的典型特性包括currying.call/cc,所以可以用来跑前面的lambda calculus和yin…

这题目确实比较杀脑细胞... 原题: (let* ((yin ((lambda (cc) (display "@") cc) (call-with-current-continuation (lambda (c) c)))) (yang ((lambda (cc) (display "*") cc) (call-with-current-continuation (lambda (c) c))))) (yin yang)) 它会输出“@*@**@***@****@*…

/***获取汉字的拼音*/function pinyin($s, $isfirst = false) { static $pinyins; $s = trim($s); $len = strlen($s); if($len < 3) return $s; if(!isset($pinyins)) { $data = '一:yi|丁:ding|丂:kao|七:qi|丄:shang|丅:xia|丆:mu|万:wan|丈:zhang|三:san|上:shang|下:xia|丌:ji|不:bu|与:yu…

本篇分析continuation的一个著名例子"阴阳迷题",这是由David Madore先生提出的,原谜题如下: (let* ((yin ((lambda (foo) (display "@") foo) (call/cc (lambda (bar) bar)))) (yang ((lambda (foo) (display "*") foo) (call/cc (lambda (bar) bar))))) (yin yang)) 这里引用了h…

Problem Description SJX has 2*N magic gems. N of them have Yin energy inside while others have Yang energy. SJX wants to make a necklace with these magic gems for his beloved BHB. To avoid making the necklace too Yin or too Yang, he must place these…

Necklace Time Limit: 3000/1500 MS (Java/Others)    Memory Limit: 65536/65536 K (Java/Others)Total Submission(s): 2423    Accepted Submission(s): 766 Problem Description SJX has 2*N magic gems. N of them have Yin energy inside while others have Yang e…

A. Pieces of Parentheses 将括号串排序,先处理会使左括号数增加的串,这里面先处理减少的值少的串:再处理会使左括号数减少的串,这里面先处理差值较大的串.确定顺序之后就可以DP了. 时间复杂度$O(n^3)$. #include<cstdio> #include<cstring> #include<algorithm> using namespace std; const int N=310,inf=1000000; int n,i,j,m,all,…

http://www.cv-foundation.org/openaccess/CVPR2016.py ORAL SESSION Image Captioning and Question Answering Monday, June 27th, 9:00AM - 10:05AM. These papers will also be presented at the following poster session 1   Deep Compositional Captioning: Descr…

Rust 阴阳谜题,及纯基于代码的分析与化简 雾雨魔法店专栏 https://zhuanlan.zhihu.com/marisa 来源 https://zhuanlan.zhihu.com/p/52249705 0. 前(请务必跳过) 之前用 Haskell 通过 Cont Monad 模拟过 call/cc (实际上在阴阳谜题中用作 get-current-continuation,这里我们只讨论 get/cc),但似乎确实是搞个 DSL 再模拟. 但我是觉得这和动态类型其实关系不大,只是通常…

题目链接:http://acm.split.hdu.edu.cn/showproblem.php?pid=5727 Problem DescriptionSJX has 2*N magic gems. N of them have Yin energy inside while others have Yang energy. SJX wants to make a necklace with these magic gems for his beloved BHB. To avoid maki…

NAIPC 2017 Yin and Yang Stones 75.39% 1000ms 262144K   A mysterious circular arrangement of black stones and white stones has appeared. Ming has been tasked with balancing the stones so that only one black and one white stone remain. Ming has two ope…

Latex--TikZ和PGF--高级文本绘图,思维绘图,想到--得到! TikZ和PGF是一种用在TeX上的CLI绘图工具.CLI和GUI是两种常见的绘图方式,前者是所想即所得(WYTIWYG)的,通过类编程的思想实现绘图,这种方式往往能够生成精确控制的函数图,常见的有PostScript.PGF.Asymptote.PSTricks等.后者则是所见即所得(WYSIWYG)的,常见的有CorelDraw.Illustrator.Photoshop.GIMP.Office.Visio等. Tik…

使用三个div实现太极图的步骤如下: HTML部分 <div class="box"> <div class="yin"></div> <div class="yang"></div> </div> 第一步,画一个宽高为300px的圆,并为其加上阴影(为了看起来有立体感) .box{ width:300px; height:300px; margin:50px auto; p…

Necklace SJX has 2*N magic gems. N of them have Yin energy inside while others have Yang energy. SJX wants to make a necklace with these magic gems for his beloved BHB. To avoid making the necklace too Yin or too Yang, he must place these magic gems…

      he University of Virginia American Studies Program 2002-2003.                     Randy Pausch's Last Lecture: Really Achieving Your Childhood Dreams Given at Carnegie Mellon University Tuesday, September 18, 2007 McConomy Auditorium For more i…

(待补) A. Pieces of Parentheses 将括号处理完成后排序,方式参加下面的博客.然后做一遍背包即可. 2018 Multi-University Training Contest 1 Balanced Sequence(贪心) #include <cstdio> #include <cstring> #include <algorithm> #include <iostream> using namespace std; const i…

好久没写过博客了,把以前的博客补一下. Necklace Time Limit: 3000/1500 MS (Java/Others)    Memory Limit: 65536/65536 K (Java/Others)Total Submission(s): 3603    Accepted Submission(s): 1097 Problem Description SJX has 2*N magic gems. N of them have Yin energy inside whi…