这题解法怎么说呢,由于我是把行数逐步除以2暴力得到的答案,所以有点二分的意思,可是昨天琦神说是有点像分治的意思.反正总的来说:就是从大逐步细化找到最优答案. 可是昨晚傻B了.靠! 多写了点东西,然后就错了,刚才一练习,拿昨晚的代码一看,就把6行代码删去就过了.靠!昨晚应该是脑子进水了!!!!! 昨晚的代码: #include <iostream> #include <cstdio> #include <fstream> #include <algorithm>…

http://codeforces.com/contest/426/problem/B 对称标题的意思大概是.应当指出的,当线数为奇数时,答案是线路本身的数 #include<iostream> #include<cstdio> #include<cstring> #include<algorithm> #define maxn 1005 using namespace std; char a[maxn][maxn]; int ans; void solve…

B. Sereja and Mirroring time limit per test 1 second memory limit per test 256 megabytes input standard input output standard output Let's assume that we are given a matrix b of size x × y, let's determine the operation of mirroring matrix b. The mir…

There are n people and k keys on a straight line. Every person wants to get to the office which is located on the line as well. To do that, he needs to reach some point with a key, take the key and then go to the office. Once a key is taken by somebo…

题目链接:http://acm.fzu.edu.cn/problem.php?pid=2232 Description GG学长虽然并不打炉石传说,但是由于题面需要他便学会了打炉石传说.但是传统的炉石传说对于刚入门的GG学长来说有点复杂,所以他决定自己开发一个简化版的炉石传说. 在简化版的炉石传说中: 每个随从只有生命值和攻击力,并且在你的回合下,你的每只随从在本回合下只能选择一个敌方随从进行攻击.当两个随从a,b交战时,a的生命值将减去b的攻击力,b的生命值将减去a的攻击力,(两个伤害没有先后…

B. Friends and Presents time limit per test 1 second memory limit per test 256 megabytes input standard input output standard output You have two friends. You want to present each of them several positive integers. You want to present cnt1 numbers to…

E. Sereja and Squares http://codeforces.com/contest/314/problem/E 题意: 给你一个擦去了部分左括号和全部右括号的括号序列,括号有25种,用除x之外的小写字母a~z表示.在擦去的地方填入一括号,求有多少种合法的括号序列.答案对4294967296取模. 分析: 首先dp的时候如果前面的一个左括号确定了,右边也就确定了(和它一样就行了).左边不确定的时候'?',假设随便填入一个,最后乘以25就行了.所以状态只与左括号的个数有关.所以可…

题目链接: Problem: Query on the tree Time limit: 1s     Mem limit: 64 MB      Problem Description There is a tree with n node, labeled from 1 to n, and the root of the tree is 1. For every node i, if its father is j, its value vi=vj*i%20161119, the value…

GukiZ and GukiZiana 题意: 区间加 给出$y$查询$a_i=a_j=y$的$j-i$最大值 一开始以为和论文CC题一样...然后发现他带修改并且是给定了值 这样就更简单了.... 每个块维护排好序的结果 修改暴力重构+整块打标记 查询暴力查+整块二分找数量 复杂度$O(SlogS + \frac{N}{S} + S+\frac{N}{S}logS)$ woc求了一节课导数也没求出最值来又发现一开始式子列错了不管了我就开根号了..(我才不会说是因为乱搞了一下更慢了) 貌似是因为…

C. Vasya and Robot time limit per test 1 second memory limit per test 256 megabytes input standard input output standard output Vasya has got a robot which is situated on an infinite Cartesian plane, initially in the cell (0,0)(0,0). Robot can perfor…