PAT甲级——A1050 String Subtraction

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PAT甲级——A1050 String Subtraction

Given two strings S1 and S2, S=S1−S2 is defined to be the remaining string after taking all the characters in S2 from S1. Your task is simply to calculate S1−S2 for any given strings. However, it might not be that simple to do…

PAT 甲级 1050 String Subtraction (20 分) （简单送分,getline(cin,s)的使用）

1050 String Subtraction (20 分) Given two strings S1 and S2, S=S1−S2 is defined to be the remaining string after taking all the characters in S2 from S1. Your task is simply to calculate S1−S2 for any given strings. However,…

PAT甲级——1050 String Subtraction

1050 String Subtraction Given two strings S1 and S2, S=S1−S2 is defined to be the remaining string after taking all the characters in S2 from S1. Your task is simply to calculate S1−S2 for any given strings. However, it might…

PAT 甲级 1050 String Subtraction

https://pintia.cn/problem-sets/994805342720868352/problems/994805429018673152 Given two strings S~1~ and S~2~, S = S~1~ - S~2~ is defined to be the remaining string after taking all the characters in S~2~ from S~1~. Your task is simply to calculate S…

A1050. String Subtraction

Given two strings S1 and S2, S = S1 - S2 is defined to be the remaining string after taking all the characters in S2 from S1. Your task is simply to calculate S1 - S2 for any given strings. However, it might not be that simple to do it fast. Input Sp…

A1050 String Subtraction (20 分)

一.技术总结这个是使用了一个bool类型的数组来判断该字符是否应该被输出. 然后就是如果在str2中出现那么就判断为false,被消除不被输出. 遍历str1如果字符位true则输出该字符. 还有需要注意的是memset函数是在头文件#include"cstring"中. 二.参考代码: #include<iostream> #include<cstring> using namespace std; bool hashTable[256]; int main…

PAT Advanced 1050 String Subtraction (20 分)

Given two strings S1 and S2, S=S1−S2 is defined to be the remaining string after taking all the characters in S2 from S1. Your task is simply to calculate S1−S2 for any given strings. However, it might not be that simple to do…

PAT Advanced 1050 String Subtraction (20) [Hash散列]

题目 Given two strings S1 and S2, S = S1 – S2 is defined to be the remaining string afer taking all the characters in S2 from S1. Your task is simply to calculate S1 – S2 for any given strings. However, it might not be that simple to do it fast. Input…

PAT练习--1050 String Subtraction (20 分)

题⽬⼤意:给出两个字符串,在第⼀个字符串中删除第⼆个字符串中出现过的所有字符并输出. 这道题的思路:将哈希表里关于字符串s2的所有字符都置为true,再对s1的每个字符进行判断,若Hash[s1[i]]不为true,则输出. 代码如下: #include<iostream> #include<string> using namespace std; bool Hash[128] = {0}; int main(){ string s1, s2; getline(cin, s1);…

PAT_A1050#String Subtraction

Source: PAT A1050 String Subtraction (20 分) Description: Given two strings S1 and S2, S=S1−S2 is defined to be the remaining string after taking all the characters in S2 from S1. Your task is simply to calculate S1−S2 for any…