#include <iostream> #include <assert.h> using namespace std; int ato(const char *str) { ,e=,s=; ,min=-; ; ]={}; unsigned ; while(*str==' '){ //过滤掉连续空格 str++; } ')){ if(*str=='-'||*str=='+'){ //过滤掉正负号 if(*str=='-') f=-; str++; } ') //过滤掉前面的无用的0…

Leetcode 8. String to Integer (atoi) atoi函数实现 (字符串) 题目描述 实现atoi函数,将一个字符串转化为数字 测试样例 Input: "42" Output: 42 Input: " -42" Output: -42 Input: "4193 with words" Output: 4193 Input: "words and 987" Output: 0 详细分析 这道题的cor…

1.  String to Integer (atoi) Implement atoi to convert a string to an integer. Hint: Carefully consider all possible input cases. If you want a challenge, please do not see below and ask yourself what are the possible input cases. Notes: It is inte…

String to Integer (atoi) Implement atoi to convert a string to an integer. Hint: Carefully consider all possible input cases. If you want a challenge, please do not see below and ask yourself what are the possible input cases. Notes: It is intended f…

实现字符串转整形数字 遵循几个规则: 1. 函数首先丢弃尽可能多的空格字符,直到找到第一个非空格字符. 2. 此时取初始加号或减号. 3. 后面跟着尽可能多的数字,并将它们解释为一个数值. 4. 字符串可以在组成整数的字符之后包含其他字符,这些字符将被忽略,并且对该函数的行为没有影响. 5. 如果str中的第一个非空格字符序列不是有效的整数,则为0. Runtime: 16 ms, faster than 62.80% of C++ online submissions for String t…

8. String to Integer (atoi) Medium Implement atoi which converts a string to an integer. The function first discards as many whitespace characters as necessary until the first non-whitespace character is found. Then, starting from this character, tak…

# -*- coding: utf8 -*-'''__author__ = 'dabay.wang@gmail.com'https://oj.leetcode.com/problems/string-to-integer-atoi/ Implement atoi to convert a string to an integer. Hint: Carefully consider all possible input cases. If you want a challenge, please…

这道题在LeetCode OJ上难道属于Easy.可是通过率却比較低,究其原因是须要考虑的情况比較低,非常少有人一遍过吧. [题目] Implement atoi to convert a string to an integer. Hint: Carefully consider all possible input cases. If you want a challenge, please do not see below and ask yourself what are the pos…

Implement atoi to convert a string to an integer. Hint: Carefully consider all possible input cases. If you want a challenge, please do not see below and ask yourself what are the possible input cases. Notes: It is intended for this problem to be spe…

Implement atoi which converts a string to an integer. The function first discards as many whitespace characters as necessary until the first non-whitespace character is found. Then, starting from this character, takes an optional initial plus or minu…

Implement atoi to convert a string to an integer. 转换很简单,唯一的难点在于需要开率各种输入情况,例如空字符串,含有空格,字母等等. 另外需在写的时候注意细节问题,完成后需要反复调试,整合. public class Solution { public int myAtoi(String str) { if (str == null || str.length() < 1) return 0; str = str.trim(); char fla…

Implement atoi to convert a string to an integer. public class Solution { public int myAtoi(String s) { if (s == null || s.length() < 1) { return 0; } int i = 0; while (i < s.length() && s.charAt(i) == ' ') { i++; } if (i == s.length()) { re…

Implement atoi to convert a string to an integer. Hint: Carefully consider all possible input cases. If you want a challenge, please do not see below and ask yourself what are the possible input cases. Notes: It is intended for this problem to be spe…

Implement atoi to convert a string to an integer. Hint: Carefully consider all possible input cases. Notes: It is intended for this problem to be specified vaguely (ie, no given input specs). You are responsible to gather all the input requirements u…

问题描述: Implement atoi to convert a string to an integer. Hint: Carefully consider all possible input cases. If you want a challenge, please do not see below and ask yourself what are the possible input cases. Notes: It is intended for this problem to…

Implement atoi which converts a string to an integer. The function first discards as many whitespace characters as necessary until the first non-whitespace character is found. Then, starting from this character, takes an optional initial plus or minu…

一.题目链接:https://leetcode.com/problems/string-to-integer-atoi/ 二.题目大意: 实现一个和C语言里atoi具有相同功能的函数,即能够把字符串转换成整型.例如:输入字符串“-123”,返回值为一个整数-123. 三.题解: 这道题也属于字符串处理类的题目,只要看懂题目所给定的规则就好了,题目给的规则大致如下: 1.若一开始遇到连续的2空白字符,则忽略这些字符,直到遇到第一个非空白字符. 2.若遇到的第一个空白字符为'+'或者'-',则只有下…

题目 Implement atoi to convert a string to an integer. Hint: Carefully consider all possible input cases. If you want a challenge, please do not see below and ask yourself what are the possible input cases. Notes: It is intended for this problem to be…

Implement atoi to convert a string to an integer. Hint: Carefully consider all possible input cases. If you want a challenge, please do not see below and ask yourself what are the possible input cases. Notes: It is intended for this problem to be spe…

这道题是LeetCode里的第8道题. 题目要求: 请你来实现一个 atoi 函数,使其能将字符串转换成整数. 首先,该函数会根据需要丢弃无用的开头空格字符,直到寻找到第一个非空格的字符为止. 当我们寻找到的第一个非空字符为正或者负号时,则将该符号与之后面尽可能多的连续数字组合起来,作为该整数的正负号:假如第一个非空字符是数字,则直接将其与之后连续的数字字符组合起来,形成整数. 该字符串除了有效的整数部分之后也可能会存在多余的字符,这些字符可以被忽略,它们对于函数不应该造成影响. 注意:假如该字…

题意:将字符串转化成数字. 前置有空格,同时有正负号,数字有可能会溢出,这里用long long解决(leetcode用的是g++编译器),这题还是很有难度的. class Solution { public: int myAtoi(string str) { ,i = ; for(;i<str.size() && str[i] == ' '; ++i); ] ="+-" ; ] ={,-}; ;j<;++j){ if(str[i] == ss[j]) {…

public class Solution { public int myAtoi(String str) { int index = 0, sign = 1, total = 0; //1. 边界条件判断 if(str.length() == 0) return 0; //2. 移除空格 while(str.charAt(index) == ' ' && index < str.length()) index ++; //3. 处理符号位 if(str.charAt(index)…

点击打开题目链接 题目意思就是自己实现一个atoi函数,也就是将字符串转换成int型. 关于INT_MAX和INT_MIN, 只是在<limits.h>文件中定义的宏..分别是int型可以表示的最大值和最小值 还有就是定义大整数常量的时候,会出现这种警告:warning: this decimal constant is unsigned only in ISO C90 c的标准写道: The C90 rule that the default type of a decimal intege…

题目: 字符串转换为数字. 解法: 这道题的意思是要考虑到,如果有前置的空字符,则跳过:如果超出数字范围,则返回最大/最小整数:如果碰到第一个不能转换的字符,则返回. 代码: class Solution { public: int atoi(const char *str) { , result = ; int len = strlen(str); ; for( ; i < len && str[i] == ' '; ++i) //跳过前置的空字符 ; if(str[i] == '…

//此题是easy题,比较简单,主要困难在考虑全输入的各种情况://1.开始的时候有空格等空白字符//2.开头有加减号//3.溢出(第一次写就是没有考虑到这个情况) //C代码int myAtoi(char* str) { ; ; ; while(isspace(str[i])) { i++; } if(str[i] == '-') { IsNegative = ; i++; } else if(str[i] == '+') { IsNegative = ; i++; } else { } fo…

题目:剑指offer 67题 需要考虑的情况:空指针.nullptr.空字符串"".正负号.数值溢出.在写代码的时候对这些特殊的输入都定义好合理的输出.可以定义一个全局布尔型变量g_nStatus来判断是否是错误输入:可以定义一个minus布尔型变量来存储正负号的结果. , kInvalid }; // enum特性,默认kInvalid = 1 int g_nStatus = kValid; long long StrToIntCore(const char* digit, bool…

8. 字符串转换整数 (atoi) 8. String to Integer (atoi) 题目描述 LeetCode LeetCode8. String to Integer (atoi)中等 Java 实现 class Solution { public int myAtoi(String str) { if (str == null || str.trim().length() == 0) { return 0; } str = str.trim(); char firstChar = s…

题目String to Integer (atoi)(难度Medium) 大意是找出给定字串开头部分的整型数值,忽略开头的空格,注意符号,对超出Integer的数做取边界值处理. 方案1 class Solution { fun myAtoi(str: String): Int { val maxInt = " val maxIntS = "+2147483647" val minIntS = "-2147483648" val lengthMI = ma…

String to Integer (atoi) Implement atoi to convert a string to an integer. Hint: Carefully consider all possible input cases. If you want a challenge, please do not see below and ask yourself what are the possible input cases. Notes: It is intended f…

String to Integer (atoi) time=272ms   accepted 需考虑各种可能出现的情况 public class Solution { public int atoi(String str) { int length=str.length(); long result=0; int flag=1; Boolean bFlag=false,bSpace=false,bNum=false; if(length<=0) return (int) result; else…