csuoj 1113: Updating a Dictionary】的更多相关文章

http://acm.csu.edu.cn/OnlineJudge/problem.php?id=1113 1113: Updating a Dictionary Time Limit: 1 Sec  Memory Limit: 128 MBSubmit: 491  Solved: 121[Submit][Status][Web Board] Description In this problem, a dictionary is collection of key-value pairs, w…
题目链接:http://acm.csu.edu.cn/OnlineJudge/problem.php?id=1113 解题报告:输入两个字符串,第一个是原来的字典,第二个是新字典,字典中的元素的格式为一个关键字对应一个值,输入格式如下: {a:3,b:4,c:10,f:6} {a:3,c:5,d:10,ee:4}冒号前面的表示关键字,冒号后面的数字表示值,关键字由小写字母组成.现在让你判断,如果新的字典相对于原来的字典有新增的关键字以以下格式输出 :+key1,key2,....如果新的字典相对…
传送门 Time Limit: 1000MS   Memory Limit: 131072KB   64bit IO Format: %lld & %llu Description In this problem, a dictionary is collection of key-value pairs, where keys are lower-case letters, and values are non-negative integers. Given an old dictionar…
UVA12504 - Updating a Dictionary 给出两个字符串,以相同的格式表示原字典和更新后的字典.要求找出新字典和旧字典的不同,以规定的格式输出. 算法操作: (1)处理旧字典,将旧字典中的每对关键字及其价值从字典串中截取出来,压入容器中.用做新旧字典对比检索. (2)处理新字典,将新字典中的每对关键字及其价值从字典串中截取出来.对于每个关键字,在容器中检索相同的关键字.若检索不成功,该关键字是新字典新增的,处理存储到相关的串数组中.若检索成功,提取容器中该关键字的价值与新…
题意:对比新老字典的区别:内容多了.少了还是修改了. 代码:(Accepted,0.000s) //UVa12504 - Updating a Dictionary //#define _XieNaoban_ #include<iostream> #include<sstream> #include<string> #include<vector> #include<map> using namespace std; int T; int mai…
  Updating a Dictionary  In this problem, a dictionary is collection of key-value pairs, where keys are lower-case letters, and values are non-negative integers. Given an old dictionary and a new dictionary, find out what were changed. Each dictionar…
Problem C     Updating a Dictionary In this problem, a dictionary is collection of key-value pairs, where keys are lower-case letters, and values are non-negative integers. Given an old dictionary and a new dictionary, find out what were changed. Eac…
In this problem, a dictionary is collection of key-value pairs, where keys are lower-case letters, and values are non-negative integers. Given an old dictionary and a new dictionary, find out what were changed. Each dictionary is formatting as follow…
大致题意:用{ key:value, key:value, key:value }的形式表示一个字典key表示建,在一个字典内没有重复,value则可能重复 题目输入两个字典,如{a:3,b:4,c:10,f:16}  {a:3,c:5,d:10,ee:4} 于新字典相比,找出旧字典的不同,并且输出用相应格式,增加的用'+',如 +d,ee 减少的用'-',如 -b,f value变化的用*,如 *c 没有不同则输出"No changes"" 如果使用java,则可以用Tre…
全是字符串相关处理,截取长度等相关操作的练习 AC代码: #include <iostream> #include <cstdio> #include <cstdlib> #include <cctype> #include <cstring> #include <string> #include <sstream> #include <vector> #include <set> #include…