题目:传送门 题意:求n个数的最大公约数,暴力不会超时,难点在没有个数控制的输入. 题解:用特殊方法输入. #include <iostream> #include <cmath> #include <cstdio> #include <cstring> using namespace std; int gcd(int a,int b) { ) return a; return gcd(b,a%b); } int main() { int t; cin>…

两个暴力题.. 题目传送:11827 Maximum GCD AC代码: #include <map> #include <set> #include <cmath> #include <deque> #include <queue> #include <stack> #include <cstdio> #include <cctype> #include <string> #include <…

F - Maximum GCD Time Limit:1000MS     Memory Limit:0KB     64bit IO Format:%lld & %llu Given the N integers, you have to nd the maximum GCD (greatest common divisor) of every possiblepair of these integers.InputThe rst line of input is an integer N (…

这题没什么好说的,但是输入较特别,为此还WA了一次... 题目链接: https://uva.onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&page=show_problem&problem=2927 题意: 输入m个数,求两两一组的最大GCD. 分析: 对stringstream不太熟悉,直接模拟字符串的输入,但是wa了. 我觉得wa的原因是,如果一行末尾有空格的话,就不能正确输入了...还求指正... int…

Given the N integers, you have to find the maximum GCD (greatest common divisor) of every possible pair of these integers. Input The first line of input is an integer N (1 < N < 100) that determines the number of test cases. The following N lines ar…

Problem:Given the N integers, you have to find the maximum GCD (greatest common divisor) of every possible pair of these integers. Input :The first line of input is an integer N (1 < N < 100) that determines the number of test cases. The following N…

/* UVA11827 Maximum GCD https://vjudge.net/contest/153365#problem/V 数论 gcd 水题,然而读入比较坑 * */ #include <cstdio> #include <algorithm> #include <cstring> #include <cmath> #include <vector> #include <queue> //#define test usi…

题目链接:uva 10951 - Polynomial GCD 题目大意:给出n和两个多项式,求两个多项式在全部操作均模n的情况下最大公约数是多少. 解题思路:欧几里得算法,就是为多项式这个数据类型重载取模运算符,须要注意的是在多项式除多项的过程中,为了保证各项系数为整数,须要将整个多项式的系数总体扩大至一定倍数,碰到先除后模的时候要用逆元. #include <cstdio> #include <cstring> const int maxn = 105; int M; void…

题目大意:UVa 108 - Maximum Sum的加强版,求最大子矩阵和,不过矩阵是可以循环的,矩阵到结尾时可以循环到开头.开始听纠结的,想着难道要分情况讨论吗?!就去网上搜,看到可以通过补全进行处理,也是,通过补全一个相同的,问题就迎刃而解了,所以把n*n的矩阵扩展成2n*2n的矩阵就好了. #include <cstdio> #include <cstring> #define MAXN 160 int a[MAXN][MAXN], sum[MAXN][MAXN]; int…

Maximum GCD https://vjudge.net/contest/288520#problem/V Given the N integers, you have to find the maximum GCD (greatest common divisor) of every possible pair of these integers. Input The first line of input is an integer N (1 < N < 100) that deter…