Fence RailsBurch, Kolstad, and Schrijvers Farmer John is trying to erect a fence around part of his field. He has decided on the shape of the fence and has even already installed the posts, but he's having a problem with the rails. The local lumber s…

Fence RailsBurch, Kolstad, and Schrijvers Farmer John is trying to erect a fence around part of his field. He has decided on the shape of the fence and has even already installed the posts, but he's having a problem with the rails. The local lumber s…

Fence Rails题解 Burch, Kolstad, and Schrijvers Farmer John is trying to erect a fence around part of his field. He has decided on the shape of the fence and has even already installed the posts, but he's having a problem with the rails. The local lumbe…

题意:求给定图的欧拉回路(每条边只走一次) 若欧拉回路存在,图中只可能有0个or2个奇数度的点. 求解时,若有奇数度的点,则必须从该点开始.否则可以从任一点开始 求解过程:dfs //主程序部分 # circuit is a global array find_euler_circuit circuitpos = find_circuit(node ) --------------------------------------------- # nextnode and visited is…

Fence Loops The fences that surround Farmer Brown's collection of pastures have gotten out of control. They are made up of straight segments from 1 through 200 feet long that join together only at their endpoints though sometimes more than two fences…

Fence Loops The fences that surround Farmer Brown's collection of pastures have gotten out of control. They are made up of straight segments from 1 through 200 feet long that join together only at their endpoints though sometimes more than two fences…

USACO ORZ Time Limit: 5000/1500 MS (Java/Others) Memory Limit: 32768/32768 K (Java/Others) Total Submission(s): 2309 Accepted Submission(s): 826 Problem Description Like everyone, cows enjoy variety. Their current fancy is new shapes for pastures. Th…

USACO ORZ Time Limit: 5000/1500 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others) Problem Description Like everyone, cows enjoy variety. Their current fancy is new shapes for pastures. The old rectangular shapes are out of favor; new geom…

其实日期没有那么近啦……只是我偶尔还点进去造成的,导致我没有每一章刷完的纪念日了 但是全刷完是今天啦 讲真,题很锻炼思维能力,USACO保持着一贯猎奇的题目描述,以及尽量不用高级算法就完成的题解……例如用暴搜加优化代替插头dp 但是第6章!我就说第6章!为什么大赛的实践,几乎全是暴搜!是为了传达给我们不如暴搜吗?! 但是总之是结束了……想了想,从初二暑假刷了两章,然后一年陆陆续续刷完较难的四章…… 唉,一年了啊……下周也该中考了……7月份还得去noi被各大神犇完虐……仅代表辽宁省最低水平…… 一…

USACO ORZ Time Limit: 5000/1500 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others)Total Submission(s): 3581    Accepted Submission(s): 1196 Problem Description Like everyone, cows enjoy variety. Their current fancy is new shapes for pastur…

USACO ORZ Time Limit: 5000/1500 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others) Total Submission(s): 3809    Accepted Submission(s): 1264 Problem Description Like everyone, cows enjoy variety. Their current fancy is new shapes for pastu…

原题代号:HDU 4277 原题链接:http://acm.hdu.edu.cn/showproblem.php?pid=4277 原题描述: USACO ORZ Time Limit: 5000/1500 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others)Total Submission(s): 5208    Accepted Submission(s): 1725 Problem Description Like ev…

emmm........很久很久以前 把6.2过了 所以emmmmmm 直接跳过 ,从6.1到6.3吧 Fence Rails 题目大意 N<=50个数A1,A2... 1023个数,每个数数值<=128,B 问 A 们能拆分成多少个B,求最多的个数 样例 解释 A: 30=30 40=18+19+3 50=15+16+17+2 25=24 B: 15 (ok) 16 (ok) 17 (ok) 18 (ok) 19 (ok) 20 21 25 24 (ok) 30 (ok) 所以最多7个 题解…

Problem Description Like everyone, cows enjoy variety. Their current fancy is new shapes for pastures. The old rectangular shapes are out of favor; new geometries are the favorite.I. M. Hei, the lead cow pasture architect, is in charge of creating a…

Problem Description Like everyone, cows enjoy variety. Their current fancy is new shapes for pastures. The old rectangular shapes are out of favor; new geometries are the favorite.I. M. Hei, the lead cow pasture architect, is in charge of creating a…

USACO ORZ Time Limit: 5000/1500 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others) Total Submission(s): 2291    Accepted Submission(s): 822 Problem Description Like everyone, cows enjoy variety. Their current fancy is new shapes for pastur…

Description Like everyone, cows enjoy variety. Their current fancy is new shapes for pastures. The old rectangular shapes are out of favor; new geometries are the favorite.  I. M. Hei, the lead cow pasture architect, is in charge of creating a triang…

描述Like everyone, cows enjoy variety. Their current fancy is new shapes for pastures. The old rectangular shapes are out of favor; new geometries are the favorite. I. M. Hei, the lead cow pasture architect, is in charge of creating a triangular pastur…

Electric FenceDon Piele In this problem, `lattice points' in the plane are points with integer coordinates. In order to contain his cows, Farmer John constructs a triangular electric fence by stringing a "hot" wire from the origin (0,0) to a lat…

题意:在方格纸上画出一个三角形,求三角形里面包含的格点的数目 因为其中一条边就是X轴,一开始想的是算出两条边对应的数学函数,然后枚举x坐标值求解.但其实不用那么麻烦. 皮克定理:给定顶点坐标均是整点(或正方形格点)的简单多边形,皮克定理说明了其面积A和内部格点数目i.边上格点数目b的关系:A = i + b/2 - 1. 有了这条定理就好办了. 三角形面积直接用公式就能算出来. 对于从点(0,0)到点(x,y)的线段,该线段上的格点数目即gcd(x,y)+1 这样A和b都有了,套公式就行了.…

原网站大概已经上不了了-- 题目大意: 求出平面上n个点组成的一个包含顶点数最多的凸多边形.n<=250. 考虑我们每次枚举凸包的左下角为谁(参考Graham求凸包时的左下角),然后像Graham一样,将其他点相对于当前左下角做一个极角排序. 我们会想到一个dp,dp[i][j]表示当前边为i到j的最多点,得到下面这样的转移: for (int i=1;i<=n;i++) if (x!=i) dp[x][i]=1; for (int i=1;i<=n;i++) for (int j=i+…

题目大意: 输入n,k :n次操作 找到覆盖次数在k及以上的段的总长 一开始位置在0 左右活动范围为1-1000000000 接下来n行描述每次操作的步数和方向 Sample Input 6 22 R6 L1 R8 L1 R2 R Sample Output 6 下面的方法用了 map 和 区间表示法 http://www.cnblogs.com/zquzjx/p/8321466.html(区间表示法看这里) 但是不同于 题解 https://www.luogu.org/problemnew/s…

题目大意: 输入N ( 1 ≤ N ≤ 20,000 ) :将一块木板分为n块 每次切割木板的开销为这块木板的长度,即将长度为21的木板分为13和8,则开销为21 接下来n行描述每块木板要求的长度Li ( 1 ≤ Li ≤ 50,000 ) 木板长度恰好等于各段木板长之和 Sample Input 3858 Sample Output 34 挑战上的一个奇妙的贪心的方法 #include <bits/stdc++.h> #define ll long long using namespace…

Fence Repair Time Limit: 2000MS   Memory Limit: 65536K Total Submissions: 23913   Accepted: 7595 Description Farmer John wants to repair a small length of the fence around the pasture. He measures the fence and finds that he needs N (1 ≤ N ≤ 20,000)…

P2738 [USACO4.1]篱笆回路Fence Loops 11通过 21提交 题目提供者该用户不存在 标签USACO 难度提高+/省选- 提交  讨论  题解 最新讨论 暂时没有讨论 题目描述 农夫布朗的牧场上的篱笆已经失去控制了.它们分成了1~200英尺长的线段.只有在线段的端点处才能连接两个线段,有时给定的一个端点上会有两个以上的篱笆.结果篱笆形成了一张网分割了布朗的牧场.布朗想将牧场恢复原样,出于这个考虑,他首先得知道牧场上哪一块区域的周长最小. 布朗将他的每段篱笆从1到N进行了标号…

典型的找欧拉路径的题.先贴下USACO上找欧拉路径的法子: Pick a starting node and recurse on that node. At each step: If the node has no neighbors, then append the node to the circuit and return If the node has a neighbor, then make a list of the neighbors and process them (wh…

Fence Repair Time Limit: 2000MS   Memory Limit: 65536K Total Submissions: 32916   Accepted: 10638 点我 Description Farmer John wants to repair a small length of the fence around the pasture. He measures the fence and finds that he needs N (1 ≤ N ≤ 20,0…

Riding the Fences Farmer John owns a large number of fences that must be repaired annually. He traverses the fences by riding a horse along each and every one of them (and nowhere else) and fixing the broken parts. Farmer John is as lazy as the next…

Electric Fence题解 Don Piele In this problem, `lattice points' in the plane are points with integer coordinates. In order to contain his cows, Farmer John constructs a triangular electric fence by stringing a "hot" wire from the origin (0,0) to a…

UPD:我真不是想骗访问量TAT..一开始没注意总长度写着写着网页崩了王仓(其实中午的时候就时常开始卡了= =)....损失了2h(幸好长一点的都单独开了一篇)....吓得赶紧分成两坨....TAT.............. —————————————————————————————————————————————————————————————————————————————— 写(被虐)了整整一个月b站上usaco的金组题...然而到现在总共只写了100道上下TAT(当然是按AC人数降序排…