题目链接:http://acm.zju.edu.cn/onlinejudge/showProblem.do?problemCode=2314 The terrorist group leaded by a well known international terrorist Ben Bladen is buliding a nuclear reactor to produce plutonium for the nuclear bomb they are planning to create.…

Reactor Cooling Time Limit: 5000ms Memory Limit: 32768KB This problem will be judged on ZJU. Original ID: 231464-bit integer IO format: %lld      Java class name: Main Special Judge   The terrorist group leaded by a well known international terrorist…

Reactor Coolinghttp://acm.zju.edu.cn/onlinejudge/showProblem.do?problemId=1314 Time Limit: 5 Seconds      Memory Limit: 32768 KB      Special Judge The terrorist group leaded by a well known international terrorist Ben Bladen is buliding a nuclear re…

题目链接:http://acm.zju.edu.cn/onlinejudge/showProblem.do?problemId=1314 The terrorist group leaded by a well known international terrorist Ben Bladen is buliding a nuclear reactor to produce plutonium for the nuclear bomb they are planning to create. Be…

题目链接:http://acm.zju.edu.cn/onlinejudge/showProblem.do?problemCode=2314 题目大意: 给n个点,及m根pipe,每根pipe用来流躺液体的,单向的,每时每刻每根pipe流进来的物质要等于流出去的物质,要使得m条pipe组成一个循环体,里面流躺物质. 并且满足每根pipe一定的流量限制,范围为[Li,Ri].即要满足每时刻流进来的不能超过Ri(最大流问题),同时最小不能低于Li. 解题思路: 转自:https://www.cnbl…

http://acm.zju.edu.cn/onlinejudge/showProblem.do?problemCode=2314 题意: 给出每条边流量的上下界,问是否存在可行流,如果存在则输出. 思路:先定义D(u)为顶点u发出的所有弧的流量下界与进入顶点u的所有弧的流量下界和之差(out[u]-in[u]). 对于无源汇的网络流来说: (1)新增两个顶点S(附加源点)和T(附加汇点). (2)对原网络中每个顶点u,计算出D(u),如果D(u)>0,则增加一条新弧<u,T>,这条弧的…

贴个板子 #include <iostream> #include <cstdio> #include <cstring> #include <algorithm> using namespace std; typedef long long ll; const int N=205, M=5e5+5, INF=1e9; inline ll read(){ char c=getchar();ll x=0,f=1; while(c<'0'||c>'9…

题目: 无源汇可行流例题 http://acm.zju.edu.cn/onlinejudge/showProblem.do?problemId=1314 题解: 证明什么的就算了,下面给出一种建图方式 1.建虚拟的S和T 2.每一条原图的边(u,v),设最大容量是Max,最小是Min,建一条容量为Max-Min的边(u,v),同时令ind[v]和oud[u]+=Min,表示实际应该多流入(出)的流量 3.对于每个点u,如果ind[u]>oud[u],为了满足流量平衡条件,所以让S和u连一条容量为…

题目链接:http://acm.zju.edu.cn/onlinejudge/showProblem.do?problemId=1314 题意: 给n个点,及m根pipe,每根pipe用来流躺液体的,单向的,每时每刻每根pipe流进来的物质要等于流出去的物质,要使得m条pipe组成一个循环体,里面流躺物质. 并且满足每根pipe一定的流量限制,范围为[Li,Ri].即要满足每时刻流进来的不能超过Ri(最大流问题),同时最小不能低于Li. 求的是最大流. 很久之前就看了带上下界的网络流,一直没看懂…

http://acm.zju.edu.cn/onlinejudge/showProblem.do?problemId=1314 题意:    给n个点,及m根pipe,每根pipe用来流躺液体的,单向的,每时每刻每根pipe流进来的物质要等于流出去的物质,要使得m条pipe组成一个循环体,里面流躺物质. 并且满足每根pipe一定的流量限制,范围为[Li,Ri].即要满足每时刻流进来的不能超过Ri(最大流问题),同时最小不能低于Li. 模板:无源汇有上下界可行流 #include<stdio.h>…

ZOJ 1314 Reactor Cooling | 上下界无源汇可行流 题意 有一个网络,每条边有流量的上界和下界,求一种方案,让里面的流可以循环往复地流动起来. 题解 上下界无源汇可行流的模型: 设置虚拟源点和虚拟汇点. 如果一条边\(u \to v\)的下界是\(mi\).上界是\(ma\),则在图中建一条\(u \to v\)的边,流量是\(ma - mi\),同时记录\(oud[u] += mi, ind[v] += mi\),分别代表\(u\)实际比图上多流出的流量与\(v\)实际比…

[算法]有上下界网络流-无源汇(循环流) [题解]http://www.cnblogs.com/onioncyc/p/6496532.html //未提交 #include<cstdio> #include<algorithm> #include<cstring> using namespace std; ,maxm=,inf=0x3f3f3f3f; struct edge{int from,v,flow;}e[maxm]; ,first[maxn],cur[maxn]…

Reactor Cooling 无源汇上下界最大流问题. 1.流量平衡. 2.满足上下界 模板题. #include <iostream> #include <queue> #include <vector> #include <cstdio> #include <cstring> using namespace std; const int MAXN = 200000 + 10; const int INF = 1 << 30; s…

Reactor Cooling Time Limit: 5 Seconds      Memory Limit: 32768 KB      Special Judge The terrorist group leaded by a well known international terrorist Ben Bladen is buliding a nuclear reactor to produce plutonium for the nuclear bomb they are planni…

称号:acdream 1211 Reactor Cooling 分类:无汇的有上下界网络流. 题意: 给n个点.及m根pipe,每根pipe用来流躺液体的.单向的.每时每刻每根pipe流进来的物质要等于流出去的物质,要使得m条pipe组成一个循环体.里面流躺物质. 而且满足每根pipe一定的流量限制,范围为[Li,Ri].即要满足每时刻流进来的不能超过Ri(最大流问题).同一时候最小不能低于Li. 比如: 个pipe) ,下界为1) 23 1 3 3 4 1 3 4 1 1 3 1 3 1 3…

 Description The terrorist group leaded by a well known international terrorist Ben Bladen is buliding a nuclear reactor to produce plutonium for the nuclear bomb they are planning to create. Being the wicked computer genius of this group, you are re…

Description The terrorist group leaded by a well known international terrorist Ben Bladen is buliding a nuclear reactor to produce plutonium for the nuclear bomb they are planning to create. Being the wicked computer genius of this group, you are res…

题目描述 The terrorist group leaded by a well known international terrorist Ben Bladen is buliding a nuclear reactor to produce plutonium for the nuclear bomb they are planning to create. Being the wicked computer genius of this group, you are responsibl…

Reactor Cooling The terrorist group leaded by a well known international terrorist Ben Bladen is buliding a nuclear reactor to produce plutonium for the nuclear bomb they are planning to create. Being the wicked computer genius of this group, you are…

The terrorist group leaded by a well known international terrorist Ben Bladen is buliding a nuclear reactor to produce plutonium for the nuclear bomb they are planning to create. Being the wicked computer genius of this group, you are responsible for…

Reactor Cooling time limit per test: 0.5 sec. memory limit per test: 65536 KB input: standard output: standard The terrorist group leaded by a well known international terrorist Ben Bladen is buliding a nuclear reactor to produce plutonium for the nu…

194. Reactor Cooling time limit per test: 0.5 sec. memory limit per test: 65536 KB input: standard output: standard The terrorist group leaded by a well known international terrorist Ben Bladen is buliding a nuclear reactor to produce plutonium for t…

Time Limit: 5 Seconds      Memory Limit: 32768 KB      Special Judge The terrorist group leaded by a well known international terrorist Ben Bladen is buliding a nuclear reactor to produce plutonium for the nuclear bomb they are planning to create. Be…

The terrorist group leaded by a well known international terrorist Ben Bladen is buliding a nuclear reactor to produce plutonium for the nuclear bomb they are planning to create. Being the wicked computer genius of this group, you are responsible for…

The terrorist group leaded by a well known international terrorist Ben Bladen is buliding a nuclear reactor to produce plutonium for the nuclear bomb they are planning to create. Being the wicked computer genius of this group, you are responsible for…

题意: 给n个点,及m根pipe,每根pipe用来流躺液体的,单向的,每时每刻每根pipe流进来的物质要等于流出去的物质,要使得m条pipe组成一个循环体,里面流躺物质. 并且满足每根pipe一定的流量限制,范围为[Li,Ri].即要满足每时刻流进来的不能超过Ri(最大流问题),同时最小不能低于Li. /* 无源汇的上下界可行流. 参见:周源<一种简易的方法求解流量有上下界的网络中网络流问题>. */ #include<cstdio> #include<iostream>…

题意: 给定n个点和m条边, 每条边有流量上下限[b,c], 求是否存在一种流动方法使得每条边流量在范围内, 而且每个点的流入 = 流出 分析: 无源汇有上下界最大流模板, 记录每个点流的 in 和 out , 然后如果一个点 i 的in > out,  从源点i连一条边到in, out > in 就从i 连一条边到 v. #include <cstdio> #include <iostream> #include <cstring> #include &l…

Code: #include<cstdio> #include<algorithm> #include<vector> #include<queue> #include<iostream> #include<cstring> using namespace std; const int maxn=600; const int INF=1000000; # define pb push_back int A[maxn],mapp[INF…

problemCode=2314">点击打开链接 题意:给定m条边和n个节点.每条边最少的流量和最多的流量.保证每一个节点的出入流量和相等,问能够形成吗,能够则输出每条边的流量 思路:一道有上下界的网络流,由于有下界.说明我们每条边必须跑大于等于下界的流量,那我们能够转化一下,将下界设为必要边,也就是我们肯定会跑的边,并且这道题是没有源点和汇点的,所以我们要加这两个点.而对于一条边.a,b,low,high,我们a->b连的流量为high-low,a->T为low.S->…

(点击此处查看原题) 题意分析 给出n个结点,m条管道,每条管道存在最小流量和最大流量,而且每个结点的流入量等于流出流出量,问这n个结点和m条管道能否形成流量循环 解题思路 经典的无源汇有上下边界的可行流问题,因为每条边存在最低流量low和最大流量up,所以每条边都至少有low流量,我们为每个边都设置这样的初始流量,这样我们就可以将所有边的下界变为0,上界变成up-low,相当于消灭了下界,而up-low则表示这条边的容量,和普通最大流问题类似,就将原来有上下边界的边转化为容量为up-low的边…