HDU - 1005 Number Sequence Problem Description A number sequence is defined as follows:f(1) = 1, f(2) = 1, f(n) = (A * f(n - 1) + B * f(n - 2)) mod 7.Given A, B, and n, you are to calculate the value of f(n). Input The input consists of multiple test…

Problem Description A number sequence is defined as follows: f(1) = 1, f(2) = 1, f(n) = (A * f(n - 1) + B * f(n - 2)) mod 7. Given A, B, and n, you are to calculate the value of f(n).   Input The input consists of multiple test cases. Each test case…

A number sequence is defined as follows:  f(1) = 1, f(2) = 1, f(n) = (A * f(n - 1) + B * f(n - 2)) mod 7.  Given A, B, and n, you are to calculate the value of f(n). Input The input consists of multiple test cases. Each test case contains 3 integers…

HDU 1005 Number Sequence(数列) Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 65536/32768 K (Java/Others) [Description] [题目描述] A number sequence is defined as follows: f(1) = 1, f(2) = 1, f(n) = (A * f(n - 1) + B * f(n - 2)) mod 7. Given A, B, an…

HDU 1005 Number Sequence(数论) Problem Description: A number sequence is defined as follows:f(1) = 1, f(2) = 1, f(n) = (A * f(n - 1) + B * f(n - 2)) mod 7. Given A, B, and n, you are to calculate the value of f(n).   Input The input consists of multipl…

Number Sequence Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others)Total Submission(s): 187893    Accepted Submission(s): 46820 Problem Description A number sequence is defined as follows: f(1) = 1, f(2) = 1, f(n) = (A…

Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others)Total Submission(s): 177761    Accepted Submission(s): 44124 Problem Description A number sequence is defined as follows: f(1) = 1, f(2) = 1, f(n) = (A * f(n - 1) + B…

A number sequence is defined as follows: f(1) = 1, f(2) = 1, f(n) = (A * f(n - 1) + B * f(n - 2)) mod 7. Given A, B, and n, you are to calculate the value of f(n). InputThe input consists of multiple test cases. Each test case contains 3 integers A,…

Number Sequence Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others)Total Submission(s): 175657    Accepted Submission(s): 43409 Problem Description A number sequence is defined as follows: f(1) = 1, f(2) = 1, f(n) = (A…

Number Sequence Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others)Total Submission(s): 154923    Accepted Submission(s): 37854 Problem Description A number sequence is defined as follows: f(1) = 1, f(2) = 1, f(n) = (A…

Number Sequence Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others)Total Submission(s): 89984    Accepted Submission(s): 21437 Problem Description A number sequence is defined as follows: f(1) = 1, f(2) = 1, f(n) = (A…

题目链接 Problem Description A number sequence is defined as follows: f(1) = 1, f(2) = 1, f(n) = (A * f(n - 1) + B * f(n - 2)) mod 7. Given A, B, and n, you are to calculate the value of f(n). Input The input consists of multiple test cases. Each test ca…

题目链接:http://acm.hdu.edu.cn/showproblem.php?pid=1005 题意: 数列{f(n)}: f(1) = 1, f(2) = 1, f(n) = ( A*f(n-1) + B*f(n-2) ) MOD 7 给定A.B.n,求f(n). (1<=n<=100,000,000) 题解: 大水题~ (*/ω＼*) 矩阵快速幂. 初始矩阵start: 特殊矩阵special: 所求矩阵ans: ans = start * special^(n-1) ans的第一…

题目:http://acm.hdu.edu.cn/showproblem.php?pid=1005 代码: #include<iostream> #include<stdio.h> #include<string.h> #include<algorithm> using namespace std; ; struct matrix { ][]; }; matrix mul(matrix a,matrix b) { int i,j,k; matrix c; m…

题目 第一次做是看了大牛的找规律结果,如下: //显然我看了答案,循环节点是48,但是为什么是48,据说是高手打表出来的 #include<stdio.h> int main() { ],a,b,i,n; f[]=;f[]=; while(scanf("%d%d%d",&a,&b,&n)!=EOF) { &&b==&&n==)break; ;i<;i++) { f[i]=(a*f[i-])%+(b*f[i-])%…

http://www.51nod.com/onlineJudge/questionCode.html#!problemId=1126 http://acm.hdu.edu.cn/showproblem.php?pid=1005 注意上面一题和下面一题的区别,上面A,B可能取负数,但是mod跟c++中%是不一样的,mod只会得到非负数,两次跳进这个坑了. 然后就找周期,只要f[i-1]==1&&f[i]==1就可以跳出,然后i-2就是周期,输出n%(i-2)的时候,要注意如果等于0的话,其实…

#include <stdio.h> #include <string.h> int main() { int a,b,n; int i; ]={}; f[]=; f[]=; while(scanf("%d %d %d",&a,&b,&n)!=EOF){ ){ break; } ;i<;i++){ f[i]=(a*f[i-]+b*f[i-])%; } ){ printf(]); } else{ printf()%+]); } } ;…

链接:传送门 题意:略 思路:f(n) = (A * f(n - 1) + B * f(n - 2)) mod 7 -> f(n) = (A * f(n-1)%7 + B * f(n-1)%7)%7 检查输出可以发现规律,每48个数一循环,因此只需要打出前50个数的fib表然后对n%7即可. /************************************************************************* > File Name: 1.cpp > Aut…

题意,f(1)=1,f(2)=1,f(n)=a*f(n-1)+b*f(n-2),求f(n)%7 这个题可能数据不够严谨,所以有些错误的做法也可以通过,比如7 7 50,应该输出0而不是1 解:找到关键字%7,那么能说明每一步都%7,最终答案也就是%7的,如果每一步都%7,那么对于任意f(n)来说,f(n-1)有7种情况,f(n-2)有7种情况,一共最多只有49种情况,说明这里有循环节,而且循环节的长度不超过49.需要注意的是,这里只能证明循环节的长度不超过49,并不能证明f(1)和f(2)就在循…

题目链接:http://acm.hdu.edu.cn/showproblem.php?pid=1005 Number Sequence Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others) Total Submission(s): 85249    Accepted Submission(s): 20209 Problem Description A number sequence…

HDU 1711 Number Sequence(数列) Time Limit: 10000/5000 MS (Java/Others) Memory Limit: 32768/32768 K (Java/Others) [Description] [题目描述] Given two sequences of numbers : a[1], a[2], ...... , a[N], and b[1], b[2], ...... , b[M] (1 <= M <= 10000, 1 <= N…

HDU 1711 Number Sequence (字符串匹配,KMP算法) Description Given two sequences of numbers : a1, a2, ...... , aN, and b1, b2, ...... , bM (1 <= M <= 10000, 1 <= N <= 1000000). Your task is to find a number K which make aK = b1, aK+1 = b2, ...... , aK+M…

HDU 4390 题意: 大概就是这样.不翻译了: Given a number sequence b1,b2-bn. Please count how many number sequences a1,a2,...,ansatisfy the condition thata1∗a2∗...∗an=b1∗b2∗-∗bn(ai,bi>1). 思路: 我们能够确定一件事:等号两边由同样数量的质因子组成. 假设ai能够等于1,答案就是把这些质因子分配进n个位置的方案数. 设左边的数字共由x个质因子组成…

Number Sequence Time Limit: 10000/5000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others)Total Submission(s): 27028    Accepted Submission(s): 11408 Problem Description Given two sequences of numbers : a[1], a[2], ...... , a[N], and b[1],…

Number Sequence Time Limit: 10000/5000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others)Total Submission(s): 39408    Accepted Submission(s): 16269 Problem Description Given two sequences of numbers : a[1], a[2], ...... , a[N], and b[1],…

Number Sequence Time Limit: 10000/5000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others) Total Submission(s): 11691    Accepted Submission(s): 5336 Problem Description Given two sequences of numbers : a[1], a[2], ...... , a[N], and b[1],…

传送门:http://acm.hdu.edu.cn/showproblem.php?pid=1711 Number Sequence Time Limit: 10000/5000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others)Total Submission(s): 42917    Accepted Submission(s): 17715 Problem Description Given two sequences…

                  Yet another Number Sequence Let’s define another number sequence, given by the following function:f(0) = af(1) = bf(n) = f(n − 1) + f(n − 2), n > 1When a = 0 and b = 1, this sequence gives the Fibonacci Sequence. Changing the values…

题目代号:HDU 1711 题目链接:http://acm.hdu.edu.cn/showproblem.php?pid=1711 Number Sequence Time Limit: 10000/5000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others)Total Submission(s): 28288    Accepted Submission(s): 11891 Problem Description Give…

Description Everyone knows what the Fibonacci sequence is. This sequence can be defined by the recurrence relation: F1 = 1, F2 = 2, Fi = Fi - 1 + Fi - 2 (i > 2). We'll define a new number sequence Ai(k) by the formula: Ai(k) = Fi × ik (i ≥ 1). In thi…