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Segments Time Limit: 2000ms Memory Limit: 10000KB This problem will be judged on ACdream. Original ID: 115764-bit integer IO format: %lld      Java class name: (No Java Yet)   由3钟类型操作:1)D L R(1 <= L <= R <= 1000000000) 增加一条线段[L,R]2)C i (1-base) 删…
题目链接:http://acdream.info/problem?pid=1157 Problem Description 由3钟类型操作:1)D L R(1 <= L <= R <= 1000000000) 增加一条线段[L,R]2)C i (1-base) 删除第i条增加的线段,保证每条插入线段最多插入一次,且这次删除操作一定合法3) Q L R(1 <= L <= R <= 1000000000) 查询目前存在的线段中有多少条线段完全包含[L,R]这个线段,线段X…
题目链接:https://vjudge.net/problem/ACdream-1157 题意: Problem Description 由3钟类型操作: 1)D L R(1 <= L <= R <= 1000000000) 增加一条线段[L,R] 2)C i (1-base) 删除第i条增加的线段,保证每条插入线段最多插入一次,且这次删除操作一定合法 3) Q L R(1 <= L <= R <= 1000000000) 查询目前存在的线段中有多少条线段完全包含[L,…
Segments   Problem Description 由3钟类型操作:1)D L R(1 <= L <= R <= 1000000000) 增加一条线段[L,R]2)C i (1-base) 删除第i条增加的线段,保证每条插入线段最多插入一次,且这次删除操作一定合法3) Q L R(1 <= L <= R <= 1000000000) 查询目前存在的线段中有多少条线段完全包含[L,R]这个线段,线段X被线段Y完全包含即LY <= LX <= RX &…
题目链接 Segments Time Limit: 4000/2000MS (Java/Others)Memory Limit: 20000/10000KB (Java/Others) Problem Description 由3钟类型操作:1)D L R(1 <= L <= R <= 1000000000) 增加一条线段[L,R]2)C i (1-base) 删除第i条增加的线段,保证每条插入线段最多插入一次,且这次删除操作一定合法3) Q L R(1 <= L <= R…
Count the number of segments in a string, where a segment is defined to be a contiguous sequence of non-space characters. Please note that the string does not contain any non-printable characters. Example: Input: "Hello, my name is John" Output:…
结构:Client--master host--interconnect--segment host 每个节点都是单独的PG数据库,要获得最佳的性能需要对每个节点进行独立优化. master上不包含任何的用户数据,仅保留system catalog,用户数据全部存储在segments上. master负责处理传入的sql命令,分发到对应的segments上,组合返回的结果并返回给客户端. Because the master does not contain any user data, it…
看了源码就是packagename里面必须包含一个. 源码在: ./sdk/eclipse/plugins/com.android.ide.eclipse.adt/src/com/android/ide/eclipse/adt/internal/build/builders/PreCompilerBuilder.java: "Application package '%1$s' must have a minimum of 2 segments.", 就是说:这个提示来自ADT,如果非…
Segments 执行效果 命令  在 sense 里边执行  GET /abcd/_segments  前边的是索引名称,后边是请求 段信息 说明  索引是面向分片的,是由于索引是由一个或多个分片(以及它的副本)构成,每个分片就是一个物理上的Lucene索引 返回 名词解释 已提交索引段:指那些已经执行了提交命令的段,意味着已经提交到磁盘持久化并且是只读的: 可查询索引段:可供查询使用的索引段: 索引的代:告诉我们索引有多“老”,起初创建的索引段的代为0,接着是1,依次继续: 被标记为已删除的…
Problem Introduction The goal in this problem is given a set of segments on a line and a set of points on a line, to count, for each point, the number of segments which contain it. Problem Description Task.In this problem you are given a set of point…
Problem Introduction You are given a set of segments on a line and your goal is to mark as few points on a line as possible so that each segment contains at least one marked point. Problem Description Task.Given a set of n segments \(\{ [a_0, b_0], […
The segmentation and paging mechanisms provide in the support a wide variety of approaches to memorymanagement. When segmentation and paging are combined, segments can be mapped to pages in several ways.To implement a flat (unsegmented) addressing en…
D. Vika and Segments     Vika has an infinite sheet of squared paper. Initially all squares are white. She introduced a two-dimensional coordinate system on this sheet and drew n black horizontal and vertical segments parallel to the coordinate axes.…
Count the number of segments in a string, where a segment is defined to be a contiguous sequence of non-space characters. Please note that the string does not contain any non-printable characters. Example: Input: "Hello, my name is John" Output:…
ACdream 1214---矩阵连乘 Problem Description You might have noticed that there is the new fashion among rich people to have their yards tiled with black and white tiles, forming a pattern. The company Broken Tiles is well known as the best tiling company…
 LCM Challenge Time Limit:1000MS     Memory Limit:64000KB     64bit IO Format:%lld & %llu Submit Status Practice ACdream 1077 Description Some days ago, I learned the concept of LCM (least common multiple). I've played with it for several times and I…
Triangles Time Limit:1000MS     Memory Limit:64000KB     64bit IO Format:%lld & %llu Submit Status Practice ACdream 1067 Description 已知一个圆的圆周被  N 个点分成了 N 段等长圆弧,求任意取三个点,组成锐角三角形的个数. Input 多组数据. 每组数据一个N (N ≤  1000000). Output 对于每组数据,输出不同锐角三角形的个数. Sample…
A - A Very Easy Triangle Counting Game Time Limit:1000MS     Memory Limit:64000KB     64bit IO Format:%lld & %llu Submit Status Practice ACdream 1008 Description Speedcell and Shoutmon love triangles very much.One day,they are playing a game named “T…
Bet Time Limit:1000MS     Memory Limit:64000KB     64bit IO Format:%lld & %llu Submit Status Practice ACdream 1066 Description Josnch星球是一个赌博之风盛行的星球. 每个人一出生就有一定数额的钱,之后的所有收入只能由赌博获得(OMG,如果RP不好,输光了所有的钱...) 假设赌博公司的某场赌博有 N 个结果,每个结果能获得的赔率比分别是 a[1],a[2]...a[…
郭式树 Time Limit:2000MS     Memory Limit:128000KB     64bit IO Format:%lld & %llu Submit Status Practice ACdream 1061 Description 郭橐驼,不知始何名.病偻,隆然伏行,有类橐驼者,故乡人号之驼.驼闻之,曰:“甚善.名我固当.”因舍其名,亦自谓橐驼云.其乡曰丰乐乡,在长安西.驼业种树,凡长安豪富人为观游及卖果者,皆争迎取养.视驼所种树,或移徙,无不活:且硕茂,蚤实以蕃.他植者…
Read Phone Number Time Limit:1000MS     Memory Limit:64000KB     64bit IO Format:%lld & %llu Submit Status Practice ACdream 1188 Description Do you know how to read the phone numbers in English? Now let me tell you. For example, In China, the phone n…
Sudoku Checker Time Limit:1000MS     Memory Limit:64000KB     64bit IO Format:%lld & %llu Submit Status Practice ACdream 1195 Description Sudoku is a popular single player game. The objective is to fill a 9x9 matrix with digits so that each column, e…
Alice and Bob Time Limit:3000MS     Memory Limit:128000KB     64bit IO Format:%lld & %llu Submit Status Practice ACdream 1112 Description Here  is Alice and Bob again ! Alice and Bob are playing a game. There are several numbers. First, Alice choose…
题目传送门 /* 这道题花了好长时间AC,思路有,但是表达式少写了括号一直乱码,囧! 注意:a==0时要特判:) */ #include <cstdio> #include <algorithm> #include <iostream> #include <cstring> #include <string> #include <cmath> using namespace std; ; const int INF = 0x3f3f3…
题目传送门 /* 分情况讨论,在long long范围里可以直接比较 sscanf 直接读到n中去 */ #include <cstdio> #include <iostream> #include <string> #include <algorithm> #include <cstring> #include <map> #include <set> #include <vector> using name…
题目传送门 /* 简单模拟:考虑边界的情况输出的是不一样的,还有思维好,代码能短很多 */ #include <cstdio> #include <iostream> #include <algorithm> #include <string> #include <cstring> #include <map> #include <vector> using namespace std; ; const int INF =…
题目传送门 /* 从大到小排序,逆向思维,从最后开始考虑,无后向性 每找到一个没被淹没的,对它左右的楼层查询是否它是孤立的,若是++,若不是-- 复杂度 O(n + m),还以为 O(n^2)吓得写了一半就不写了 */ #include <cstdio> #include <cstring> #include <iostream> #include <algorithm> #include <map> #include <set> #…
1157. Young Tiler Time limit: 1.0 secondMemory limit: 64 MB One young boy had many-many identical square tiles. He loved putting all his tiles to form a rectangle more, than anything in the world — he has learned the number of all rectangles he can f…
题目链接:http://acdream.info/problem?pid=1128 Problem Description wuyiqi陷入了一个迷宫中,这个迷宫是由N*M个格子组成的矩阵.每个格子上堆放了一定数量的箱子.(i,j)表示第i行,第j列的格子.wuyiqi可以将一个格子上的箱子移动到相邻的格子上,或者在这个格子上销毁.也就是在(i,j)的箱子可以移动到(i-1,j).(i+1,j).(i,j-1)和(i,j+1),但是不能移动到矩阵范围外.将(i,j)的格子上的一个箱子移动到相邻格…
D. Vika and Segments time limit per test:  2 seconds     memory limit per test:  256 megabytes input : standard input output:  standard output Vika has an infinite sheet of squared paper. Initially all squares are white. She introduced a two-dimensio…