ZOJ 2532 Internship

【ZOJ 2532 Internship】的更多相关文章

Internship Time Limit: 5000ms Memory Limit: 32768KB This problem will be judged on ZJU. Original ID: 2532 64-bit integer IO format: %lld Java class name: Main CIA headquarter collects data from across the country through its classified network…

ZOJ 2532 Internship 求隔边

Internship Time Limit: 5 Seconds Memory Limit: 32768 KB CIA headquarter collects data from across the country through its classified network. They have been usingoptical fibres long before it's been deployed on any civilian projects. However the…

ZOJ 2532 Internship（最大流找关键割边）

Description CIA headquarter collects data from across the country through its classified network. They have been using optical fibres long before it's been deployed on any civilian projects. However they are still under a lot pressure recently becaus…

zoj 2532 Internship【最小割】

就是求哪些边在最大流上满流,也就是找割边.把0作为t点,s向所有的1~n连流量为inf的边,其他的边按照流量连.跑一遍最大流,从s顺着有残余流量的正向边dfs打标记fr,从t顺着正向边有残余流量的反向边dfs打标记to,那么满足条件的边就是两端点分别有fr和to标记并且满流(这里只考虑正向边),因为这意味着在这条边上增加流量就可以再流一条增广路. 注意一下输出格式,行末不能有空格. #include<iostream> #include<cstdio> #include<qu…

ZOJ 1532 Internship （Dinic）

看来模板又错了,敲你妈妈小饼干 #include<iostream> #include<queue> #include<cstring> #include<cstdio> #include<cmath> #include<cstdlib> #include<algorithm> #include<stack> #include<vector> #include<map> using na…

ZOJ 2532 网络流最小割

求最小割的问题. 题意:已知网络中有n个源点,m的中转站(也就是节点),一个汇点(编号为0).给出网络,求一些边(增大这个边就可以增大汇点流量的边). 思路:一开始代码只找了有流=0就加入输出数组的情况,然而忽略了流向一条S->T的流有多个边权=0的情况,此时只增大一条边的值是没用的. 所以除了用一次最大流算法后,还需要用两次dfs分别从超级源点S和汇点T开始搜索,这样就可以把有多个0-0-0和单个边权为0的情况判断出来. #include <cstdio> #include <c…

[转] POJ图论入门

最短路问题此类问题类型不多,变形较少 POJ 2449 Remmarguts' Date(中等)http://acm.pku.edu.cn/JudgeOnline/problem?id=2449题意:经典问题:K短路解法:dijkstra+A*(rec),方法很多相关:http://acm.pku.edu.cn/JudgeOnline/showcontest?contest_id=1144该题亦放在搜索推荐题中 POJ 3013 - Big Christmas Tree(基础)http://ac…