A. Div. 64 time limit per test 1 second memory limit per test 256 megabytes input standard input output standard output Top-model Izabella participates in the competition. She wants to impress judges and show her mathematical skills. Her problem is f…

问题出处:http://codeforces.com/problemset/problem/887/A 问题大意:对于给出的一串二进制数,能否通过去掉一些数字,使之成为十进制下64的倍数 #include<iostream> #include<algorithm> using namespace std; //题目表述的删除,而不是把1换成0 int main(){ string s; cin>>s; //不考虑第6位的高位数 //对string类 find函数的使用…

题意: 网格图选中三个格,让你选中一些格子把这三个格子连起来,使得选中的格子总数最小.最后输出方案 网格范围为1000 思路: 首先两点间连起来最少需要的格子为他们的曼哈顿距离 然后连接方案一定是曼哈顿距离最短的两个点先连上,然后第三个点再接过去 然后题目就是求第三个点接到的那个点pos,答案就是path(a,pos)+path(b,pos)+path(c,pos) 求pos有两种方法 方法一:O(n2) 1e6枚举pos求最短即可,也能过 方法二:O(n) 首先第三个点一定在前两个点组成的矩形…

A. Div. 64 time limit per test 1 second memory limit per test 256 megabytes input standard input output standard output Top-model Izabella participates in the competition. She wants to impress judges and show her mathematical skills. Her problem is f…

基于div表单模拟右对齐 --------------------------------------------------------- ---------------------------------------------------------- <div> <label>客户名称客户名称</label> <input type="text" /> <div class="button">取消&…

Codeforces Beta Round #27 (Codeforces format, Div. 2) http://codeforces.com/contest/27 A #include<bits/stdc++.h> using namespace std; #define lson l,mid,rt<<1 #define rson mid+1,r,rt<<1|1 #define sqr(x) ((x)*(x)) #define maxn 1000005 typ…

codeforces #592(Div.2) A Pens and Pencils Tomorrow is a difficult day for Polycarp: he has to attend a lectures and b practical classes at the university! Since Polycarp is a diligent student, he is going to attend all of them. While preparing for th…

codeforces #578(Div.2) A. Hotelier Amugae has a hotel consisting of 1010 rooms. The rooms are numbered from 00 to 99 from left to right. The hotel has two entrances - one from the left end, and another from the right end. When a customer arrives to t…

Codeforces #344 Div.2 Interview 题目描述:求两个序列的子序列或操作的和的最大值 solution 签到题 时间复杂度:\(O(n^2)\) Print Check 题目描述:有一个棋盘,对其进行染色,每次染一行或一列,后来的颜色会覆盖原来的颜色,输出最后的棋盘. solution 题解用二维线段树,其实可以不用. 对染色进行离线操作,那么染过的格子.行.列就不用再染了.所以每个格子可以记录四个指针,分别是行前驱,行后继,列前驱列后继,染色时按照这个跳着来染就好了.…

Codeforces #345 Div.1 打CF有助于提高做题的正确率. Watchmen 题目描述:求欧拉距离等于曼哈顿距离的点对个数. solution 签到题,其实就是求有多少对点在同一行或同一列. 时间复杂度:\(O(nlogn)\) Image Preview 题目描述:给定看一张照片的时间,翻页的时间,把图片翻转的时间.一开始屏幕显示第一张照片,可以向左或向右翻,不能跳过还没有看过的图片,方向不对的图片要先翻转再看,看过的不消耗翻转时间与看照片时间,问在一定时间内,最多能看多少张照…