848. Shifting Letters】的更多相关文章

848. Shifting Letters 题目链接:https://leetcode.com/problems/shifting-letters/description/ 思路:O(N^2)复杂度过不了:先处理shifts, 从尾到头执行shifts[i] = sum(shifts[i+1]+...+shifts[n-1]). 注意点:会爆int,及时取余或用longlong. 1 string shiftingLetters(string S, vector<int>& shift…
[LeetCode]848. Shifting Letters 解题报告(Python) 标签(空格分隔): LeetCode 作者: 负雪明烛 id: fuxuemingzhu 个人博客: http://fuxuemingzhu.me/ 题目地址:https://leetcode.com/problems/shifting-letters/description/ 题目描述: We have a string S of lowercase letters, and an integer arr…
原题链接在这里:https://leetcode.com/problems/shifting-letters/ 题目: We have a string S of lowercase letters, and an integer array shifts. Call the shift of a letter, the next letter in the alphabet, (wrapping around so that 'z' becomes 'a'). For example, shi…
问题描述: 问题规约为:对每一个数组S,移动(shifts[0] + shitfs[1]+...+shitfs[i] )mod 26位 def shiftingLetters(self, S: str, shifts: List[int]) -> str: #a 97 ord: char->int chr: int->char sm = sum(shifts) ans = '' for i in range(len(S)): ans += chr( (ord(S[i]) - 97 + s…
题目如下: 解题思路:本题首先要很快速的计算出任意一个字符shift后会变成哪个字符,其实也很简单,让shift = shift % 26,接下来再做计算.第二部是求出每个字符要shift的次数.可以得出S[0]的shift次数等于sum(shifts),S[1]的次数等于sum(shifts)-shifts[0],S[2]的次数等于sum(shifts)-shifts[0]-shifts[1]...依次类推.这个规律可以保证整个算法的复杂度是O(n). 代码如下: class Solution…
We have a string S of lowercase letters, and an integer array shifts. Call the shift of a letter, the next letter in the alphabet, (wrapping around so that 'z' becomes 'a'). For example, shift('a') = 'b', shift('t') = 'u', and shift('z') = 'a'. Now f…
We have a string S of lowercase letters, and an integer array shifts. Call the shift of a letter, the next letter in the alphabet, (wrapping around so that 'z' becomes 'a'). For example, shift('a') = 'b', shift('t') = 'u', and shift('z') = 'a'. Now f…
All LeetCode Questions List(Part of Answers, still updating) 题目汇总及部分答案(持续更新中) Leetcode problems classified by company 题目按公司分类(Last updated: October 2, 2017) .   Top Interview Questions # Title Difficulty Acceptance 1 Two Sum Medium 17.70% 2 Add Two N…
A. Letters Cyclic Shift time limit per test:1 second memory limit per test:256 megabytes input:standard input output:standard output You are given a non-empty string s consisting of lowercase English letters. You have to pick exactly one non-empty su…
A. Letters Cyclic Shift 题目连接: http://www.codeforces.com/contest/708/problem/A Description You are given a non-empty string s consisting of lowercase English letters. You have to pick exactly one non-empty substring of s and shift all its letters 'z'…