Given the N integers, you have to find the maximum GCD (greatest common divisor) of every possiblepair of these integers. Input The first line of input is an integer N (1 < N < 100) that determines the number of test cases.The following N lines are…

F - Maximum GCD Time Limit:1000MS     Memory Limit:0KB     64bit IO Format:%lld & %llu Given the N integers, you have to nd the maximum GCD (greatest common divisor) of every possiblepair of these integers.InputThe rst line of input is an integer N (…

Subarray Sum Given an integer array, find a subarray where the sum of numbers is zero. Your code should return the index of the first number and the index of the last number. Notice There is at least one subarray that it's sum equals to zero. Example…

Subarray Sum Given an integer array, find a subarray where the sum of numbers is zero. Your code should return the index of the first number and the index of the last number. Notice There is at least one subarray that it's sum equals to zero. Example…

Maximum GCD https://vjudge.net/contest/288520#problem/V Given the N integers, you have to find the maximum GCD (greatest common divisor) of every possible pair of these integers. Input The first line of input is an integer N (1 < N < 100) that deter…

Given the N integers, you have to find the maximum GCD (greatest common divisor) of every possible pair of these integers. Input The first line of input is an integer N (1 < N < 100) that determines the number of test cases. The following N lines ar…

两个暴力题.. 题目传送:11827 Maximum GCD AC代码: #include <map> #include <set> #include <cmath> #include <deque> #include <queue> #include <stack> #include <cstdio> #include <cctype> #include <string> #include <…

/* UVA11827 Maximum GCD https://vjudge.net/contest/153365#problem/V 数论 gcd 水题,然而读入比较坑 * */ #include <cstdio> #include <algorithm> #include <cstring> #include <cmath> #include <vector> #include <queue> //#define test usi…

整体上3个题都是求subarray,都是同一个思想,通过累加,然后判断和目标k值之间的关系,然后查看之前子数组的累加和. map的存储:560题是存储的当前的累加和与个数 561题是存储的当前累加和的余数与第一次出现这个余数的位置 325题存储的是当前累加和与第一次出现这个和的位置 其实561与325都是求的最长长度,那就一定要存储的是第一次出现满足要求的位置,中间可能还出现这种满足要求的情况,但都不能进行存储 560. Subarray Sum Equals K 求和为k的连续子数组的个数 h…

Problem:Given the N integers, you have to find the maximum GCD (greatest common divisor) of every possible pair of these integers. Input :The first line of input is an integer N (1 < N < 100) that determines the number of test cases. The following N…

A. Maximum GCD 题意: t组输入,然后输入一个n,让你在区间[1,n]之间找出来两个不相等的数a,b.求出来gcd(a,b)(也就是a,b最大公约数).让你求出来最大的gcd(a,b)是多少. 题解: 最大gcd(a,b),那就是n/2向下取整的结果.因为如果gcd(a,b)越大,那么a/gcd(a,b)或者b/gcd(a,b)的值肯定越小,最小也就是2了,所以输出n/2就行 代码: 1 #include<stdio.h> 2 #include<algorithm>…

Given an array nums and a target value k, find the maximum length of a subarray that sums to k. If there isn't one, return 0 instead. Example 1: Given nums = [1, -1, 5, -2, 3], k = 3, return 4. (because the subarray [1, -1, 5, -2] sums to 3 and is th…

原题链接在这里:https://leetcode.com/problems/maximum-size-subarray-sum-equals-k/ 题目: Given an array nums and a target value k, find the maximum length of a subarray that sums to k. If there isn't one, return 0 instead. Example 1: Given nums = [1, -1, 5, -2,…

Given an array nums and a target value k, find the maximum length of a subarray that sums to k. If there isn't one, return 0 instead. Example 1: Given nums = [1, -1, 5, -2, 3], k = 3,return 4. (because the subarray [1, -1, 5, -2] sums to 3 and is the…

Given an array nums and a target value k, find the maximum length of a subarray that sums to k. If there isn't one, return 0 instead. Note:The sum of the entire nums array is guaranteed to fit within the 32-bit signed integer range. Example 1: Given…

［抄题］: Given an array nums and a target value k, find the maximum length of a subarray that sums to k. If there isn't one, return 0 instead. Note:The sum of the entire nums array is guaranteed to fit within the 32-bit signed integer range. Example 1:…

Given an array nums and a target value k, find the maximum length of a subarray that sums to k. If there isn't one, return 0 instead. Example 1: Given nums = [1, -1, 5, -2, 3], k = 3,return 4. (because the subarray [1, -1, 5, -2] sums to 3 and is the…

原题链接在这里:https://leetcode.com/problems/maximum-size-subarray-sum-equals-k/ 题目: Given an array nums and a target value k, find the maximum length of a subarray that sums to k. If there isn't one, return 0 instead. Note:The sum of the entire nums array…

Given an array nums and a target value k, find the maximum length of a subarray that sums to k. If there isn't one, return 0 instead. Example 1: Given nums = [1, -1, 5, -2, 3], k = 3,return 4. (because the subarray [1, -1, 5, -2] sums to 3 and is the…

作者: 负雪明烛 id: fuxuemingzhu 个人博客:http://fuxuemingzhu.cn/ 目录 题目描述 题目大意 解题方法 prefix Sum 日期 题目地址:https://leetcode-cn.com/problems/maximum-size-subarray-sum-equals-k/ 题目描述 Given an array nums and a target value k, find the maximum length of a subarray that…

题目:传送门 题意:求n个数的最大公约数,暴力不会超时,难点在没有个数控制的输入. 题解:用特殊方法输入. #include <iostream> #include <cmath> #include <cstdio> #include <cstring> using namespace std; int gcd(int a,int b) { ) return a; return gcd(b,a%b); } int main() { int t; cin>…

最后更新 二刷 木有头绪啊.. 看答案明白了. 用的是two sum的思路. 比如最终找到一个区间,[i,j]满足sum = k,这个去见可以看做是 [0,j]的sum 减去 [0,i]的Sum. 维护一个map,来记录0-i的和,我们希望 0~i + k = 0 ~ j ,这样就可以更新一次i~j的区间长度作为候补的结果. Time: O(n) Space: O(n) public class Solution { public int maxSubArrayLen(int[] nums, i…

Example 1: Given nums = [1, -1, 5, -2, 3], k = 3,return 4. (because the subarray [1, -1, 5, -2] sums to 3 and is the longest) Example 2: Given nums = [-2, -1, 2, 1], k = 1,return 2. (because the subarray [-1, 2] sums to 1 and is the longest) Follow U…

http://www.geeksforgeeks.org/maximum-contiguous-circular-sum/ #include <iostream> #include <vector> #include <algorithm> #include <queue> #include <stack> #include <string> #include <fstream> #include <map>…

这题没什么好说的,但是输入较特别,为此还WA了一次... 题目链接: https://uva.onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&page=show_problem&problem=2927 题意: 输入m个数,求两两一组的最大GCD. 分析: 对stringstream不太熟悉,直接模拟字符串的输入,但是wa了. 我觉得wa的原因是,如果一行末尾有空格的话,就不能正确输入了...还求指正... int…

题目链接:https://codeforces.com/contest/1370/problem/A 题意 有 $n$ 个数大小分别为 $1$ 到 $n$,找出两个数间最大的 $gcd$ . 题解 若一个 $gcd$ 存在,则至少要有 $gcd$ 本身和 $2 \times gcd$,那么 $gcd$ 最大即为 $\lfloor \frac{n}{2} \rfloor$ . 代码 #include <bits/stdc++.h> using namespace std; void solve(…

题意:在\(1\)~\(n\)中找两个不相等的数使得他们的\(gcd\)最大. 题解:水题,如果\(n\)是偶数,那么一定取\(n\)和\(n/2\),\(n\)是奇数的话,取\(n-1\)和\((n-1)/2\). 代码: #include <iostream> #include <cstdio> #include <cstring> #include <cmath> #include <algorithm> #include <stac…

该算法的定义是:给出一个int序列,元素有正有负,找出其中的最大连续子序列的和. 例如:-2,11,-4,13,-5-2,:最大和为20(11,-4, 13). 怎么考虑这个问题呢? 要充分利用,连续,这个条件. 连续子序列的和可能为正,也可能为负.如果为正,那么我们要继续加下去,因为如果后面一个数是正数, 最大子序列和必定包括前序列的和(毕竟前者和为正),如果后面一个是负数,我们也加,直到子序列的和不为正为止. 因为它不为正,所以如果后面有更大的连续子序列,那么也不会包括它,因为加上一个非正数…

给我们n个数,然后有m个询问,每个询问为L,R,询问区间[L,R]的最大最小值,最小公约数,最大公约数,和,异或,或,且 这些问题通通可以用RMQ的思想来解决. 以下用xor来作为例子 设dp[i][j]为以i开头的,长度为2^j的区间的所有值得异或 那么dp[i][j] = dp[i][j-1] xor dp[i+(1<<(j-1))][j-1] 这样,运用动态规划的思想,我们可以在nlogn的时间复杂度内算出以任意点开头的,长度为1,2,4,8...2^j 的区间的异或值. 那么询问任意区…

传送门 Time Limit: 1 Sec  Memory Limit: 128 MB  Description You are given an array of size N and another integer M.Your target is to find the maximum value of sum of subarray modulo M. Subarray is a continous subset of array elements. Note that we need…