443. String Compression Easy Given an array of characters, compress it in-place. The length after compression must always be smaller than or equal to the original array. Every element of the array should be a character (not int) of length 1. After yo…

problem 443. String Compression Input ["a","a","b","b","c","c","c"] Output ["a","a","b","b","c","c"] Expected ["] a: Giv…

String Compression Time Limit:3000MS     Memory Limit:0KB     64bit IO Format:%lld & %llu Submit Status Practice UVA 1351 Appoint description:  System Crawler  (2015-08-21) Description   Run Length Encoding(RLE) is a simple form of compression. RLE c…

原题: 443. String Compression 解题: 看到题目就想到用map计数,然后将计数的位数计算处理,这里的解法并不满足题目的额外O(1)的要求,并且只是返回了结果array的长度,并未修改原始vector的元素. 代码如下: class Solution { public: int bitsOfNumber(int n) { int cnt = 0; if (n <= 1) return 0; //若为1,则不增加 while(n) //统计位数,如12就是2位 { cnt++…

CF825F String Compression 题意 给定一个串s,其中重复出现的子串可以压缩成 "数字+重复的子串" 的形式,数字算长度. 只重复一次的串也要压. 求压缩后的最小长度. 数据范围 \(0 \le |s| \le 8,000\) 时空范围: 2sec 512mb 时空范围让我们基本可以\(O(N^2)\)做了 先考虑如果原串的每一个子串都求出了它的压缩后长度存在了\(cnt[i][j]\)里,我们就可以很方便的做DP了 令\(dp[i]\)表示长为\(i\)的串的最…

Description Implement a method to perform basic string compression using the counts of repeated characters. For example, the string aabcccccaaa would become a2b1c5a3. If the "compressed" string would not become smaller than the original string,…

Implement a method to perform basic string compression using the counts of repeated characters. For example, the string aabcccccaaa would become a2b1c5a3. If the "compressed" string would not become smaller than the original string, your method…

/** 题目:F. String Compression 链接:http://codeforces.com/problemset/problem/825/F 题意:压缩字符串后求最小长度. 思路: dp[i]表示前i个字符需要的最小次数. dp[i] = min(dp[j]+w(j+1,i)); (0<=j<i); [j+1,i]如果存在循环节(自身不算),那么取最小的循环节x.w = digit((i-j)/x)+x; 否则w = i-j+1; 求一个区间最小循环节: 证明:http://w…

825F - String Compression 题意 给出一个字符串,你要把它尽量压缩成一个短的字符串,比如一个字符串ababab你可以转化成3ab,长度为 3,比如bbbacacb转化成3b2ac1b,长度为 7,aaaaaaaaaa转化为10a,长度为 3. 分析 求转换后的最短字符串,那么怎么去组合字符串中的子串是关键. 考虑 dp,dp[1...L] 对应字符串 S[0...L-1] .dp[i] 表示字符串 S[0, i - 1] 转化后的字符串长度,dp[0] = 0. 状态转移…

题目传送门 /* 题意:给一个字符串,连续相同的段落可以合并,gogogo->3(go),问最小表示的长度 区间DP:dp[i][j]表示[i,j]的区间最小表示长度,那么dp[i][j] = min (dp[j][k] + dp[k+1][i+j-1]), digit (i / k) + dp[j][j+k-1] + 2)后者表示可以压缩成k长度连续相同的字符串 4.5 详细解释 */ /************************************************ * Au…