洛谷 P1444 [USACO1.3]虫洞wormhole https://www.luogu.org/problemnew/show/P1444 JDOJ 2386: USACO 2013 Dec Bronze 3.Wormholes https://neooj.com:8082/oldoj/problem.php?id=2386 Description Problem 3: Wormholes [Brian Dean, 2013] Farmer John's hobby of conduct…

传送门 解题要素:代码能力 解题步骤:理解题意 - >搜索枚举所有可能的配对情况 - >判断冲突并求解 - >调试 一. 理解题意 这里讲几个不容易理解的点: 1. +x方向 即向右走 2. 一旦来到虫洞,就必须掉入 二. 搜索枚举所有可能的配对情况 考虑引入match数组,对于当前的节点来说,枚举后面的点是否已配对过即可 int match[N]; inline void dfs(int x) { //当前节点 ) { rep(i, , n) , )) { ans++; break;…

Wormholes Farmer John's hobby of conducting high-energy physics experiments on weekends has backfired, causing N wormholes (2 <= N <= 12, N even) to materialize on his farm, each located at a distinct point on the 2D map of his farm (the x,y coordin…

这题可真是又让我找到了八数码的感觉...哈哈. 首先,第一次见题,没有思路,第二次看题,感觉是搜索,就这样写下来了. 这题我几乎是一个点一个点改对的(至于为什么是这样,后面给你看一个神奇的东西),让我发现了许多搜索上的问题.思路非常简 单:搜索出每一种可能的配对方式,然后从每一个点出发 一遍,模拟走的过程,如果到死循环里面就答案加一,那个模拟走的过程话说我敲的还是很爽的,这题难在对配对序列的搜索和配对状态重 复的剪枝上面. 记得配对序列的搜索我敲了5.6个版本,发现AC之后一个都没有用上,但是在…

usaco ch1.4 sort(d , d + c, [](int a, int b) -> bool { return a > b; }); 生成与过滤 generator&&filter dfs:简化多重循环,枚举点对与判环 洛谷OJ P1209 [USACO1.3]修理牛棚 Barn Repair P1444 [USACO1.3]虫洞wormhole P3650 [USACO1.3]滑雪课程设计Ski Course Design P2693 [USACO1.3]号码锁…

Wormholes Farmer John's hobby of conducting high-energy physics experiments on weekends has backfired, causing N wormholes (2 <= N <= 12, N even) to materialize on his farm, each located at a distinct point on the 2D map of his farm (the x,y coordin…

开个坑记录一下刷USACO的Training的记录 可能会随时弃坑 只有代码和做法简述 可能没有做法简述 [USACO1.1]你的飞碟在这儿Your Ride Is He… 模拟,细节已忘 #include<iostream> #include<cstdio> #include<cstring> using namespace std; ],s2[]; int main() { ,ss2=; scanf("%s",&s1); scanf(&q…

wormhole解题报告 —— icedream61 博客园(转载请注明出处)------------------------------------------------------------------------------------------------------------------------------------------------[题目] 一个人在二维坐标系上走,方向永远是+x.此坐标系中有N个虫洞(N是偶数). 虫洞这东西,一旦两个配成一对,便可以形成“传送门…

Your Ride Is Here It is a well-known fact that behind every good comet is a UFO. These UFOs often come to collect loyal supporters from here on Earth. Unfortunately, they only have room to pick up one group of followers on each trip. They do, however…

题意:给你n种价值不同的邮票,最大的不超过10000元,一次最多贴k张,求1到多少都能被表示出来?n≤50,k≤200. 题解:dp[i]表示i元最少可以用几张邮票表示,那么对于价值a的邮票,可以推出dp[j]=min(dp[j],dp[j-a]+1).j从a到k*10000顺序枚举,因为类似于完全背包. http://train.usaco.org/usacoprob2?a=fSgPyIazooa&S=stamps /* TASK:stamps LANG:C++ */ #include<c…