Intelligence System Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others)Total Submission(s): 982    Accepted Submission(s): 440 Problem Description After a day, ALPCs finally complete their ultimate intelligence system,…

Intelligence System Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others)Total Submission(s): 3414    Accepted Submission(s): 1494 Problem Description After a day, ALPCs finally complete their ultimate intelligence syste…

Intelligence System Time Limit : 2000/1000ms (Java/Other)   Memory Limit : 32768/32768K (Java/Other) Total Submission(s) : 2   Accepted Submission(s) : 1 Font: Times New Roman | Verdana | Georgia Font Size: ← → Problem Description After a day, ALPCs…

Intelligence System Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others) Total Submission(s): 2909    Accepted Submission(s): 1259 Problem Description After a day, ALPCs finally complete their ultimate intelligence syst…

题意: 给出一个N个节点的有向图.图中任意两点进行通信的代价为路径上的边权和.如果两个点能互相到达那么代价为0.问从点0开始向其余所有点通信的最小代价和.保证能向所有点通信. 题解: 求出所有的强连通分量,然后进行缩点操作.最后贪心的找出每个点的最小代价,然后求和. #include <iostream> #include <cstdio> #include <vector> #include <cstring> #include <algorithm…

http://acm.hdu.edu.cn/showproblem.php?pid=3072 Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others)Total Submission(s): 2909    Accepted Submission(s): 1259 Problem Description After a day, ALPCs finally complete their…

Intelligence System Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others)Total Submission(s): 1904    Accepted Submission(s): 824 Problem Description After a day, ALPCs finally complete their ultimate intelligence system…

Intelligence System Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others) Total Submission(s): 1650    Accepted Submission(s): 722 Problem Description After a day, ALPCs finally complete their ultimate intelligence syste…

Intelligence System Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 32768/32768 K (Java/Others) Total Submission(s): 57 Accepted Submission(s): 27   Problem Description After a day, ALPCs finally complete their ultimate intelligence system, the…

给出一个带权有向图,要使整个图连通.SCC中的点之间花费为0,所以就先缩点,然后缩点后两点之间的权值为最小边的权值,把这些权值累加起来就是答案. #include <iostream> #include <cstdio> #include <algorithm> #include <cstring> #include <vector> #include <stack> using namespace std; int n, m; +…