意甲冠军  是否可以由串来推断a,b字符不改变其相对为了获取字符串的组合c 本题有两种解法  DP或者DFS 考虑DP  令d[i][j]表示是否能有a的前i个字符和b的前j个字符组合得到c的前i+j个字符  值为0或者1  那么有d[i][j]=(d[i-1][j]&&a[i]==c[i+j])||(d[i][j-1]&&b[i]==c[i+j])   a,b的下标都是从1開始的  注意0的初始化 #include<cstdio> #include<cs…

HDU 1501 Zipper [DFS+剪枝] Problem Description Given three strings, you are to determine whether the third string can be formed by combining the characters in the first two strings. The first two strings can be mixed arbitrarily, but each must stay in…

题目链接: HDU - 1501 Given three strings, you are to determine whether the third string can be formed by combining the characters in the first two strings. The first two strings can be mixed arbitrarily, but each must stay in its original order.For examp…

题目大意:个字符串.此题是个非常经典的dfs题. 解题思路:DFS 代码如下:有详细的注释 /* * 1501_2.cpp * * Created on: 2013年8月17日 * Author: Administrator */ #include <iostream> using namespace std; char str1[201], str2[201], str3[401]; int len1, len2, len3; bool flag; bool hash[201][201];…

题意: 给三个字符串str1.str2.str3 问str1和str2能否拼接成str3.(拼接的意思可以互相穿插) 能输出YES否则输出NO. 思路: 如果str3是由str1和str2拼接而成,str1的前i个字符和str2的前j个字符一定构成str3的前i+j个字符.(因为拼接必须保证字符的顺序不变) 所以,,,这算是个变形的最长公共子序列? DP方程:dp[i][j]:str3的前i+j个字符能否由str1的前i个字符和str2的前j个字符拼接而成.布尔型. 看代码,, 代码: char…

Problem Description Given three strings, you are to determine whether the third string can be formed by combining the characters in the first two strings. The first two strings can be mixed arbitrarily, but each must stay in its original order. For e…

链接:http://acm.hdu.edu.cn/showproblem.php?pid=1501 思路:题目要求第三个串由前两个组成,且顺序不能够打乱,搜索大法好 #include<cstdio> #include<iostream> #include<algorithm> #include<math.h> #include<string.h> #include<vector> #include<queue> #incl…

Super Jumping! Jumping! Jumping! Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others)Total Submission(s): 33384    Accepted Submission(s): 15093 Problem Description Nowadays, a kind of chess game called “Super Jumping!…

题目链接:http://acm.hdu.edu.cn/showproblem.php?pid=1572 很久没写深搜了,有点忘了. #include <iostream> #include <cstdio> #include <cstring> #include <algorithm> using namespace std; #define MAXN 33 #define inf 1<<30 int map[MAXN][MAXN]; int n…

Given a string s and a dictionary of words dict, add spaces in s to construct a sentence where each word is a valid dictionary word. Return all such possible sentences. For example, givens = "catsanddog",dict = ["cat", "cats"…