[题意简述]:就是选择一个停车地点.然后走遍全部的store后,再回到停车地点.就是走一圈.问要走的距离是多少. [分析]:能够直接求出距离的最大值与最小值,求出差值.乘以2就是最后的输出结果. //220K 16Ms #include<iostream> using namespace std; int main() { int t; int n,b; int Max,Min; cin>>t; while(t--) { Max = 0; Min = 100; cin>>…
[题目简述]:两个四位数,假设后一个数中的某个数与前一个相应的数的位置和值都相等.则统计数目由几个这种数.记为count1吧. 假设后一个数中的某个数与前一个数的数值相等,但位置不同. 此时这种数的个数记为count2. 写成*A*B,即count1 A count2 B. [分析]:题目的简述即分析. //740K 0Ms #include<iostream> #include<cstring> using namespace std; int main() { int T; s…
[题目简述]:事实上就是依据题目描写叙述:A permutation of the integers 1 to n is an ordering of these integers. So the natural way to represent a permutation is to list the integers in this order. With n = 5, a permutation might look like 2, 3, 4, 5, 1. However, there i…
Problem Description When shopping on Long Street, Michael usually parks his car at some random location, and then walks to the stores he needs. Can you help Michael choose a place to park which minimises the distance he needs to walk on his shopping…