题面 传送门 Sol 设\(f[S]\)表示看过的电影集合为\(S\),当前电影的最大结束时间 枚举电影和电影的开始时间转移 可以对开始时间\(sort\) 二分一下转移即可 # include <bits/stdc++.h> # define IL inline # define RG register # define Fill(a, b) memset(a, b, sizeof(a)) using namespace std; typedef long long ll; const in…
[USACO15JAN]Moovie Mooving G 状压难题.不过也好理解. 首先我们根据题意: she does not want to ever visit the same movie twice. 这句话以及\(n\)的取值范围给了我们足够多的提醒:可能是状态压缩. 那么,当我们真正尝试用集合表示每个电影是否已看过的时候,我们却不容易给出能够转移的状态. 举个例子,当我们定义的状态中集合表示成为该状态的元素,那么这将会与最终求该集合的最小值冲突--状态中没法记录集合的最小值. 我们…
P3118 [USACO15JAN]Moovie Mooving G Link 题目描述 Bessie is out at the movies. Being mischievous as always, she has decided to hide from Farmer John for L (1 <= L <= 100,000,000) minutes, during which time she wants to watch movies continuously. She has…
[USACO15JAN]电影移动Moovie Mooving 时间限制: 2 Sec 内存限制: 128 MB 题目描述 Bessie is out at the movies. Being mischievous as always, she has decided to hide from Farmer John for L (1 <= L <= 100,000,000) minutes, during which time she wants to watch movies conti…
题目描述 Bessie is out at the movies. Being mischievous as always, she has decided to hide from Farmer John for L (1 <= L <= 100,000,000) minutes, during which time she wants to watch movies continuously. She has N (1 <= N <= 20) movies to choose…
Description Bessie is out at the movies. Being mischievous as always, she has decided to hide from Farmer John for L (1 <= L <= 100,000,000) minutes, during which time she wants to watch movies continuously. She has N (1 <= N <= 20) movies to…
