hdu 3999 二叉查找树】的更多相关文章

The order of a Tree Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others)Total Submission(s): 917    Accepted Submission(s): 496 Problem Description As we know,the shape of a binary search tree is greatly related to the…
/****************************************************************** 题目: The order of a Tree(hdu 3999) 链接: http://acm.hdu.edu.cn/showproblem.php?pid=3999 题意: 给你一个序列建立一棵二叉搜索树 要你找出另外一个序 列,可以建立和原序列建立的二叉搜索树一样且这个序列 是字典序最小 算法: 二叉搜索树 思想: 对于一个二叉搜索树,它的先序遍历是能建立…
这里是杭电hdu上的链接:http://acm.hdu.edu.cn/showproblem.php?pid=3999  Problem Description: As we know,the shape of a binary search tree is greatly related to the order of keys we insert. To be precisely: 1.  insert a key k to a empty tree, then the tree becom…
The order of a Tree Problem Description The shape of a binary search tree is greatly related to the order of keys we insert. To be precisely:1.  insert a key k to a empty tree, then the tree become a tree with only one node;2.  insert a key k to a no…
The order of a Tree Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others)Total Submission(s): 845    Accepted Submission(s): 461 Problem Description As we know,the shape of a binary search tree is greatly related to the…
建一个二叉搜索树,然后前序输出. 用链表建的,发现很久没做都快忘了... #include <cstdio> #include <cstdlib> struct Node{ int v; Node* l; Node* r; }; Node* root; Node* newnd(int value) { Node* u = (Node*) malloc(sizeof(Node)); if (u != NULL) { u -> v = value; u -> r = u -…
The order of a Tree Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others)Total Submission(s): 835    Accepted Submission(s): 453 Problem Description As we know,the shape of a binary search tree is greatly related to the…
find the most comfortable road Time Limit: 1000/1000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others)Total Submission(s): 3999    Accepted Submission(s): 1720 Problem Description XX 星有许多城市,城市之间通过一种奇怪的高速公路SARS(Super Air Roam Structure---超…
http://acm.hdu.edu.cn/showproblem.php?pid=4441 题意:对于一个序列,每次有三种操作   insert pos  表示在pos插入一个数,这个数是最小的正数没有在序列中出现的.而且还要在某个位置插入他的相反数,使得这个序列满足队列的出入顺序(正表示进,负表示出)   remove num 表示在序列中把num以及-num两数去掉   query num 把num与-num之间的数求和输出 这题我本来实在是没有思路,看起来像维护一个线段树,这样求和好办,…
数据结构:二叉查找树(C语言实现) ►写在前面 关于二叉树的基础知识,请看我的一篇博客:二叉树的链式存储 说明: 二叉排序树或者是一棵空树,或者是具有下列性质的二叉树: 1.若其左子树不空,则左子树上所有结点的值均小于它的根结点的值: 2.若其右子树不空,则右子树上所有结点的值均大于它的根结点的值; 3.其左.右子树也分别为二叉排序树 ►二叉查找树的建立(插入): 说明: 二叉树的创建是二叉树反复插入节点所构造出来的! 若二叉树为空树,则插入元素作为树根节点. 若根结点的键值等于key,则插入失…