LeetCode 21. Merge Two Sorted Lists(c++)】的更多相关文章

Merge two sorted linked lists and return it as a new list. The new list should be made by splicing together the nodes of the first two lists. 题目标签:Linked List 题目给了我们两个lists,让我们有序的合并两个 lists. 这题利用递归可以从list 的最后开始向前链接nodes,代码很简洁,清楚. Java Solution: Runti…
Merge two sorted linked lists and return it as a new list. The new list should be made by splicing together the nodes of the first two lists. 递归实现: /** * Definition for singly-linked list. * struct ListNode { * int val; * ListNode *next; * ListNode(i…
题目链接 https://leetcode.com/problems/merge-two-sorted-lists/?tab=Description   Problem: 已知两个有序链表(链表中的数值递增排列).将这两个链表进行合并操作,并且满足递增排列 即合并后仍为有序链表.     递归进行合并操作.mergeTwoList(ListNode list1, ListNode list2)      当list1==null时 return list2;      当list2==null时…
要定义两个链表 判断时依次对应每一个链表的值进行判断即可. /** * Definition for singly-linked list. * struct ListNode { * int val; * ListNode *next; * ListNode(int x) : val(x), next(NULL) {} * }; */ class Solution { public: ListNode* mergeTwoLists(ListNode* l1, ListNode* l2) { L…
题意:合并两个有序链表 /** * Definition for singly-linked list. * struct ListNode { * int val; * ListNode *next; * ListNode(int x) : val(x), next(NULL) {} * }; */ class Solution { public: ListNode* mergeTwoLists(ListNode* l1, ListNode* l2) { if(l1 == NULL) retu…
1.题目 21. Merge Two Sorted Lists Merge two sorted linked lists and return it as a new list. The new list should be made by splicing together the nodes of the first two lists. Example: Input: 1->2->4, 1->3->4 Output: 1->1->2->3->4-&g…
Merge two sorted linked lists and return it as a new list. The new list should be made by splicing together the nodes of the first two lists. Example: Input: 1->2->4, 1->3->4 Output: 1->1->2->3->4->4 和88. Merge Sorted Array类似,数据…
Merge two sorted linked lists and return it as a new list. The new list should be made by splicing together the nodes of the first two lists. Example: Input: 1->2->4, 1->3->4 Output: 1->1->2->3->4->4 这道混合插入有序链表和我之前那篇混合插入有序数组非常的相…
题目链接: https://leetcode.com/problems/merge-k-sorted-lists/?tab=Description Problem: 给出k个有序的list, 将其进行合并得到一个有序的list   对于给出的ListNode[] lists ,可以进行两两合并.divide and conquer  将list分为前后两部分,对前半部分再次进行分半操作,对后半部分进行分半操作,然后将其进行合并操作. 合并操作也就是对两个list进行合并 合并操作可以采用递归算法…
合并链表 Runtime: 4 ms, faster than 100.00% of C++ online submissions for Merge Two Sorted Lists. class Solution { public: ListNode *mergeTwoLists(ListNode *l1, ListNode *l2) { //1 2 4 . 1 3 4 ListNode *res = ); ListNode *cur = res; while (l1 != NULL &&am…