Intersection Time Limit: 1000MS   Memory Limit: 10000K Total Submissions: 16322   Accepted: 4213 Description You are to write a program that has to decide whether a given line segment intersects a given rectangle. An example: line: start point: (4,9)…

题目链接 题意 判断线段和矩形是否有交点(矩形的范围是四条边及内部). 思路 判断线段和矩形的四条边有无交点 && 线段是否在矩形内. 注意第二个条件. Code #include <cstdio> #include <cmath> #include <iostream> #include <cstring> #define inf 0x3f3f3f3f #define eps 1e-6 #define maxn 110 using name…

这个题目要注意的是:给出的矩形坐标不一定是按照左上,右下这个顺序的 #include <iostream> #include <cstdio> #include <cstring> #include <algorithm> #include <cmath> #define eps 1e-8 #define INF 1e9 using namespace std; const int maxn=100; typedef struct Point {…

// 线段和矩形相交 POJ 1410 // #include <bits/stdc++.h> #include <iostream> #include <cstdio> #include <cstdlib> #include <algorithm> #include <vector> #include <math.h> using namespace std; #define LL long long typedef p…

Intersection 大意:给你一条线段,给你一个矩形,问是否相交. 相交:线段全然在矩形内部算相交:线段与矩形随意一条边不规范相交算相交. 思路:知道详细的相交规则之后题事实上是不难的,可是还有个坑点就是题目里明明说给的是矩形左上角跟右下角的点,但实际上不是,须要又一次推断一下...真坑. struct Point { double x, y; } A, B, C, D; struct Line { Point a, b; } L; int n; double xmult(Point p1…

题目链接 Intersection Time Limit: 1000MS   Memory Limit: 10000K Total Submissions: 12040   Accepted: 3125 Description You are to write a program that has to decide whether a given line segment intersects a given rectangle. An example: line: start point:…

题目链接:http://poj.org/problem?id=1410 Intersection Time Limit: 1000MS   Memory Limit: 10000K Total Submissions: 12822   Accepted: 3347 Description You are to write a program that has to decide whether a given line segment intersects a given rectangle.…

Intersection Time Limit: 1000MS   Memory Limit: 10000K Total Submissions: 9996   Accepted: 2632 Description You are to write a program that has to decide whether a given line segment intersects a given rectangle. An example: line: start point: (4,9) …

题意: 给一条线段,和一个矩形,问线段是否与矩形相交或在矩形内. 解法: 判断是否在矩形内,如果不在,判断与四条边是否相交即可.这题让我发现自己的线段相交函数有错误的地方,原来我写的线段相交函数就是单纯做了两次跨立实验,在下图这种情况是错误的: 这样的话线段与右边界的两次跨立实验(叉积<=0)都会通过,但是并不相交. 所以要加快速排斥. 还有就是这题题目说给出的不一定是左上角,右下角依次的顺序.所以干脆重新自己定义左上角,右下角. 代码: #include <iostream> #inc…

题目链接:POJ 1410 Description You are to write a program that has to decide whether a given line segment intersects a given rectangle. An example: line: start point: (4,9) end point: (11,2) rectangle: left-top: (1,5) right-bottom: (7,1) Figure 1: Line se…