用random模块实现按照要求生成一定个数和一定位数的密码: #Author by Andy #_*_ coding:utf-8 _*_ import random checkcode='' code='''abcdefghijklmnopqrstuvwxyzABCDEFGHIJKLMNPQRSTUVWXYZ123456789!@#%&()*"{}''' code_len=int(input('请输入密码长度:')) code_count=int(input('请输入密码个数:')) c…
#coding:utf8import random,wxdef password(event): a = [chr(i) for i in range(97,123)] b = [chr(i) for i in range(65,91)] c = ['0','1','2','3','4','5','6','7','8','9'] d = ['!','@','#','$','%','^','&','*','(',')','=','_','+','/','?'] set1 = a + b + c +…
请设计 一个密码生成器,要求随机生成4组10位密码(密码只能由字母和数字组成),每一组必须包含至少一个大写字母,每组密码不能相同,输出生成的密码. #include<stdio.h> #include<time.h> #include<stdlib.h> int getchar(); void test(int array[]); int main(){ int data[4][10]; for(int i = 0;i < 4;…