题目链接 http://poj.org/problem?id=1753 题意 一个棋盘上有16个格子,按4×4排列,每个格子有两面,两面的颜色分别为黑色和白色,游戏的每一轮选择一个格子翻动,翻动该格子意味着将该格子及其上下左右格子(如果存在的话)的黑面朝上变成白面朝上,反之亦然,游戏的目标是格子全部黑面朝上或者全部白面朝上.输入棋盘的初始状态,求最少经过多少轮可以达到游戏的目标. 思路 求最少轮数,我会想到使用bfs来解决(dfs也可以解决),但使用bfs求解,如果每个状态都直接存储下当前棋盘的…

Flip Game Time Limit: 1000MS   Memory Limit: 65536K Total Submissions: 30449   Accepted: 13232 Description Flip game is played on a rectangular 4x4 field with two-sided pieces placed on each of its 16 squares. One side of each piece is white and the…

链接:http://poj.org/problem?id=1753 Flip Game Description Flip game is played on a rectangular 4x4 field with two-sided pieces placed on each of its 16 squares. One side of each piece is white and the other one is black and each piece is lying either i…

题意:4*4的正方形,每个格子有黑白两面,翻转格子使得4*4个格子显示全黑或全白,翻转要求:选中的那个格子,以及其上下左右相邻的格子(如果存在)要同时翻转.输出最小的达到要求的翻转次数或者Impossible(如果不可能) 题目链接:http://poj.org/problem?id=1753 分析:因为每个格子只有黑白两面,所以对于每个格子来说,要么不翻转,要么翻转一次,因为翻转奇数次结果和翻转一次得到的效果是一样的,而翻转偶数次得到的效果和不翻转是一样的,则总共有16个格子,最多要翻转16次…

Flip Game Description Flip game is played on a rectangular 4x4 field with two-sided pieces placed on each of its 16 squares. One side of each piece is white and the other one is black and each piece is lying either it's black or white side up. Each r…

题目链接: https://vjudge.net/problem/POJ-1753 题目大意: 有4*4的正方形,每个格子要么是黑色,要么是白色,当把一个格子的颜色改变(黑->白或者白->黑)时,其周围上下左右(如果存在的话)的格子的颜色也被反转,问至少反转几个格子可以使4*4的正方形变为纯白或者纯黑? 思路: 直接二进制枚举16个元素的子集,判断哪些点需要进行翻转操作 #include<iostream> #include<cstdio> #include<cs…

Description Flip game is played on a rectangular 4x4 field with two-sided pieces placed on each of its 16 squares. One side of each piece is white and the other one is black and each piece is lying either it's black or white side up. Each round you f…

Flip game is played on a rectangular 4x4 field with two-sided pieces placed on each of its 16 squares. One side of each piece is white and the other one is black and each piece is lying either it's black or white side up. Each round you flip 3 to 5 p…

题目链接:http://poj.org/problem?id=1753 Flip Game Time Limit: 1000MS   Memory Limit: 65536K Total Submissions: 46724   Accepted: 20002 Description Flip game is played on a rectangular 4x4 field with two-sided pieces placed on each of its 16 squares. One…

题目链接:http://poj.org/problem?id=1753 题意:同上. 这回翻来翻去要考虑自由变元了,假设返回了自由变元数量,则需要枚举自由变元. /* ━━━━━┒ギリギリ♂ eye! ┓┏┓┏┓┃キリキリ♂ mind! ┛┗┛┗┛┃＼○/ ┓┏┓┏┓┃ / ┛┗┛┗┛┃ノ) ┓┏┓┏┓┃ ┛┗┛┗┛┃ ┓┏┓┏┓┃ ┛┗┛┗┛┃ ┓┏┓┏┓┃ ┛┗┛┗┛┃ ┓┏┓┏┓┃ ┃┃┃┃┃┃ ┻┻┻┻┻┻ */ #include <algorithm> #include <io…

题目链接:http://poj.org/problem?id=1753 和上一个题一样,将初始状态存成01矩阵,就可以用位运算优化了.黑色白色各来一遍 /* ━━━━━┒ギリギリ♂ eye! ┓┏┓┏┓┃キリキリ♂ mind! ┛┗┛┗┛┃＼○/ ┓┏┓┏┓┃ / ┛┗┛┗┛┃ノ) ┓┏┓┏┓┃ ┛┗┛┗┛┃ ┓┏┓┏┓┃ ┛┗┛┗┛┃ ┓┏┓┏┓┃ ┛┗┛┗┛┃ ┓┏┓┏┓┃ ┃┃┃┃┃┃ ┻┻┻┻┻┻ */ #include <algorithm> #include <iostrea…

题意:给4×4的棋盘的初始状态,b代表黑,w代表白. 要求变成全黑或者全白 最少需要几步. 简单的做法 可以暴搜 状压bfs 不再赘述 主要学习Gauss做法 同样是01方程组 用异或解 注意全黑或全白都可以 即 bbbb        wwww bbbb        wwww  bbbb        wwww bbbb        wwww      这两种的步数步数都是0. 因此我的做法是 列两个方程组分别求最小步数,再取最小值 ][]; // 增广矩阵 ][]; ]; // 解 ];…

题目传送门 题意描述 有\(4 \times 4\)的正方形,每个格子要么是黑色,要么是白色,当把一个格子的颜色改变(黑\(\to\)白 或 白\(\to\)黑)时,其周围上下左右(如果存在的话)的格子的颜色也被反转,问至少反转几个格子可以使\(4 \times 4\)的正方形变为纯白或者纯黑? 分析 对于每一个格子,只有两个状态,将它翻转一次与翻转奇数次效果是一样的,翻转零次与翻转偶数次的效果是一样的. 因为只有\(16\)个格子,选择\(0\)个,\(1\)个,\(2\)个\(\cdots1…

poj1010--邮票问题 DFSpoj1011--Sticks dfs + 剪枝poj1020--拼蛋糕poj1054--The Troublesome Frogpoj1062--昂贵的聘礼poj1077--Eightpoj1084--Square Destroyerpoj1085--Triangle War(博弈,極大極小搜索+alpha_beta剪枝)poj1088--滑雪poj1129--Channel Allocation 着色问题 dfspoj1154--letters (dfs)p…

图论 图论解题报告索引 DFS poj1321 - 棋盘问题 poj1416 - Shredding Company poj2676 - Sudoku poj2488 - A Knight's Journey poj1724 - ROADS(邻接表+DFS) BFS poj3278 - Catch That Cow(空间BFS) poj2251 - Dungeon Master(空间BFS) poj3414 - Pots poj1915 - Knight Moves poj3126 - Prim…

Time Limit: 1000MS   Memory Limit: 65536K Total Submissions: 32961   Accepted: 14407 Description Flip game is played on a rectangular 4x4 field with two-sided pieces placed on each of its 16 squares. One side of each piece is white and the other one…

DFS深度搜索:之前一直和bfs的用法搞不太清楚:写了题才能慢慢参透吧,看了别的博客的代码,感觉能更好理解dfs在图中的应用: 这个题目的意思是一个人去救另一个人,找出最短的寻找路径: #include<stdio.h> ; ][],book[][]; void dfs(int x,int y,int step) { ][]={ {,},//向右走 {,},//向下走 {,-},//向左走 {-,},//向上走 }; int tx,ty,k; if(x==p && y==q)…

[题目大意] 有一个4x4规格的一个棋盘,现在有16个一面黑一面白的棋子分布在这个棋盘上. 翻转一个棋子能够使它以及它上下左右的四个棋子从黑变白,从白变黑. 现在问你至少要经过多少次操作才能够使得整个棋盘的颜色相同. [分析] 考虑到是4x4的规模,想到用BFS枚举+判重. 注意题目的内存限制是64MB,如果普通的用一个二维数组记录状态可能会超过内存限制. 考虑位运算,下面给出AC代码. #include <iostream> #include <fstream> #include…

Flip Game Time Limit: 1000MS   Memory Limit: 65536K Total Submissions: 37055   Accepted: 16125 Description Flip game is played on a rectangular 4x4 field with two-sided pieces placed on each of its 16 squares. One side of each piece is white and the…

https://vjudge.net/problem/POJ-1753 题意 4*4的棋盘,翻转其中的一个棋子,会带动邻接的棋子一起动.现要求把所有棋子都翻成同一种颜色,问最少需要几步. 分析 同一个棋子翻偶数次等于没有翻,翻奇数次就浪费步数,因此每个棋子最多翻一次,也就是说,答案最大就是16.故总状态数就是2^16,可以直接dfs暴力.还有另一种思路就是状态压缩,把棋盘压成16位的数字,翻转时采用异或操作,我们暴力枚举每个状态,即所有选择棋子的可能情况跑一遍,对于每一个棋子,对其能影响的位置可…

Flip Game Time Limit: 1000MS   Memory Limit: 65536K Total Submissions: 26492   Accepted: 11422 Description Flip game is played on a rectangular 4x4 field with two-sided pieces placed on each of its 16 squares. One side of each piece is white and the…

Flip Game Time Limit: 1000MS   Memory Limit: 65536K Total Submissions: 37427   Accepted: 16288 Description Flip game is played on a rectangular 4x4 field with two-sided pieces placed on each of its 16 squares. One side of each piece is white and the…

You are playing the following Flip Game with your friend: Given a string that contains only these two characters: + and -, you and your friend take turns to flip twoconsecutive "++" into "--". The game ends when a person can no longer…

You are playing the following Flip Game with your friend: Given a string that contains only these two characters: + and -, you and your friend take turns to flip twoconsecutive "++" into "--". The game ends when a person can no longer…

Flip Game Time Limit: 1000MS   Memory Limit: 65536K Total Submissions: 27005   Accepted: 11694 Description Flip game is played on a rectangular 4x4 field with two-sided pieces placed on each of its 16 squares. One side of each piece is white and the…

对缓冲区的读写操作首先要知道缓冲区的下限.上限和当前位置.下面这些变量的值对Buffer类中的某些操作有着至关重要的作用: limit:所有对Buffer读写操作都会以limit变量的值作为上限. position:代表对缓冲区进行读写时,当前游标的位置. capacity:代表缓冲区的最大容量(一般新建一个缓冲区的时候,limit的值和capacity的值默认是相等的). flip.rewind.clear这三个方法便是用来设置这些值的. clear方法 } 以上三种方法均使用final修饰,…

题目链接:http://acm.nyist.net/JudgeOnline/problem.php?pid=529 由于此题槽点太多,所以没忍住...吐槽Time: 看到这题通过率出奇的高然后愉快的进来想水掉...but... 一开始狂百度找讨论区也完全看不懂题意啊, 还好后来通过这些零碎的线索补脑了下面的题意, 能AC但不很确定484题目本意,希望对大家有帮助(话说这样会不会帮倒忙啊^_^). 题目意思:要通过x的二进制的任意位置上的数(0变为1,或1变为0)使十进制的x变为x+1, 一次只能…

  Flip Game Time Limit: 1000MS   Memory Limit: 65536K Total Submissions: 32384   Accepted: 14142 Description Flip game is played on a rectangular 4x4 field with two-sided pieces placed on each of its 16 squares. One side of each piece is white and th…

[OpenJudge 3061]Flip The Card 试题描述 There are N× Ncards, which form an N× Nmatrix. The cards can be placed upwards or downwards. Now Acer is going to do some operations so that all the cards are placed upwards after the operations. In each operation,…

Flip Game Time Limit: 1000MS   Memory Limit: 65536K Total Submissions: 33670   Accepted: 14713 Description Flip game is played on a rectangular 4x4 field with two-sided pieces placed on each of its 16 squares. One side of each piece is white and the…