csu 1556(快速幂)

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1556: Jerry's trouble Time Limit: 10 Sec Memory Limit: 256 MBSubmit: 787 Solved: 317[Submit][Status][Web Board] Description Jerry is caught by Tom. He was penned up in one room with a door, which only can be opened by its code. The code is the answ…

快速幂 --- CSU 1556: Jerry's trouble

Jerry's trouble Problem's Link: http://acm.csu.edu.cn/OnlineJudge/problem.php?id=1556 Mean: 略. analyse: 水题,直接快速幂. Time complexity: O(n) Source code: // Memory Time // 1347K 0MS // by : crazyacking // 2015-03-29-19.18 #include<map> #include<que…

CSU 1556 Jerry's trouble

题目链接:http://acm.csu.edu.cn/csuoj/problemset/problem?pid=1556 Description Jerry is caught by Tom. He was penned up in one room with a door, which only can be opened by its code. The code is the answer of the sum of the sequence of number written on th…

矩阵快速幂 HDU 4565 So Easy!（简单？才怪！）

题目链接题意: 思路: 直接拿别人的图,自己写太麻烦了~ 然后就可以用矩阵快速幂套模板求递推式啦~ 另外: 这题想不到或者不会矩阵快速幂,根本没法做,还是2013年长沙邀请赛水题,也是2008年Google Codejam Round 1A的C题. #include <bits/stdc++.h> typedef long long ll; const int N = 5; int a, b, n, mod; /* *矩阵快速幂处理线性递推关系f(n)=a1f(n-1)+a2f(n-2)+.…

51nod 算法马拉松18 B 非010串矩阵快速幂

非010串基准时间限制:1 秒空间限制:131072 KB 分值: 80 如果一个01字符串满足不存在010这样的子串,那么称它为非010串. 求长度为n的非010串的个数.(对1e9+7取模) Input 一个数n,表示长度.(n<1e15) Output 长度为n的非010串的个数.(对1e9+7取模) Input示例 3 Output示例 7 解释: 000 001 011 100 101 110 111 读完题,这样的题目肯定是能找到规律所在的,要不然数据太大根本无法算.假设现在…

hdu 4704 Sum （整数和分解+快速幂+费马小定理降幂）

题意: 给n(1<n<),求(s1+s2+s3+...+sn)mod(1e9+7).其中si表示n由i个数相加而成的种数,如n=4,则s1=1,s2=3. (全题文末) 知识点: 整数n有种和分解方法. 费马小定理:p是质数,若p不能整除a,则 a^(p-1) ≡1(mod p).可利用费马小定理降素数幂. 当m为素数,(m必须是素数才能用费马小定理) a=2时.(a=2只是题中条件,a可以为其他值) mod m = * // k=…

Codeforces632E Thief in a Shop（NTT + 快速幂）

题目 Source http://codeforces.com/contest/632/problem/E Description A thief made his way to a shop. As usual he has his lucky knapsack with him. The knapsack can contain k objects. There are n kinds of products in the shop and an infinite number of pro…