【leetcode】Search Insert Position】的更多相关文章

Given a sorted array and a target value, return the index if the target is found. If not, return the index where it would be if it were inserted in order. You may assume no duplicates in the array. Here are few examples.[1,3,5,6], 5 → 2[1,3,5,6], 2 →…
这道题是LeetCode里的第35道题. 题目描述: 给定一个排序数组和一个目标值,在数组中找到目标值,并返回其索引.如果目标值不存在于数组中,返回它将会被按顺序插入的位置. 你可以假设数组中无重复元素. 示例 1: 输入: [1,3,5,6], 5 输出: 2 示例 2: 输入: [1,3,5,6], 2 输出: 1 示例 3: 输入: [1,3,5,6], 7 输出: 4 示例 4: 输入: [1,3,5,6], 0 输出: 0 二分查找,简单快捷.每一次将被查找区间分为两块,然后再与该区间…
题目描述: Given a sorted array and a target value, return the index if the target is found. If not, return the index where it would be if it were inserted in order. You may assume no duplicates in the array. Here are few examples. [1,3,5,6], 5 → 2 [1,3,5…
Given a sorted array and a target value, return the index if the target is found. If not, return the index where it would be if it were inserted in order. You may assume no duplicates in the array. Here are few examples.[1,3,5,6], 5 → 2[1,3,5,6], 2 →…
[ 问题: ] Given a sorted array and a target value, return the index if the target is found. If not, return the index where it would be if it were inserted in order. You may assume no duplicates in the array. 翻译:给你一个排好序的数组和一个目标值,请找出目标值能够插入数组的位置. [ 分析: ]…
problem Search Insert Position 一种容易想到的是暴力破解法,一种是常用的二分法. 暴力破解法1(不推荐) class Solution { public: int searchInsert(vector<int>& nums, int target) { ; ; i<nums.size()-; i++) { )) ; else if(target==nums[i]) return i; ]) ; } if(target>nums.back())…
Given a sorted array and a target value, return the index if the target is found. If not, return the index where it would be if it were inserted in order. You may assume no duplicates in the array. Here are few examples.[1,3,5,6], 5 → 2[1,3,5,6], 2 →…
题目: Given a sorted array and a target value, return the index if the target is found. If not, return the index where it would be if it were inserted in order. You may assume no duplicates in the array. Here are few examples.[1,3,5,6], 5 → 2[1,3,5,6],…
leetcode - 35. Search Insert Position - Easy descrition Given a sorted array and a target value, return the index if the target is found. If not, return the index where it would be if it were inserted in order. You may assume no duplicates in the arr…
索引:[LeetCode] Leetcode 题解索引 (C++/Java/Python/Sql) Github: https://github.com/illuz/leetcode 035. Search Insert Position (Medium) 链接: 题目:https://leetcode.com/problems/search-insert-position/ 代码(github):https://github.com/illuz/leetcode 题意: 要把一个数有序插入到一…
[LeetCode]380. Insert Delete GetRandom O(1) 解题报告(Python) 作者: 负雪明烛 id: fuxuemingzhu 个人博客: http://fuxuemingzhu.cn/ 题目地址:https://leetcode.com/problems/insert-delete-getrandom-o1/description/ 题目描述: Design a data structure that supports all following oper…
原文链接 http://oj.leetcode.com/problems/search-in-rotated-sorted-array-ii/ http://blog.csdn.net/linhuanmars/article/details/20588511 这道题是二分查找Search Insert Position的变体,思路在Search in Rotated Sorted Array中介绍过了,不了解的朋友可以先看看那道题哈.和Search in Rotated Sorted Array…
题目要求:Search Insert Position Given a sorted array and a target value, return the index if the target is found. If not, return the index where it would be if it were inserted in order. You may assume no duplicates in the array. Here are few examples.[1…
LeetCode中,有很多关于一组interval的问题.大体可分为两类: 1.查看是否有区间重叠: 2.合并重叠区间;  3.插入新的区间: 4. 基于interval的其他问题 [ 做题通用的关键步骤]: 1. 按照begin时间排序: 2. 判断两个相邻区间是否重叠: [假设] a. 给定的区间是半开区间 [begin, end); b. 已经按照"begin"排序. c. 当前的区间是begin, end; 要比较/合并的区间:[ intervals[i][0], interv…
[题目] Suppose a sorted array is rotated at some pivot unknown to you beforehand. (i.e., 0 1 2 4 5 6 7 might become 4 5 6 7 0 1 2). You are given a target value to search. If found in the array return its index, otherwise return -1. You may assume no d…
Given a sorted array and a target value, return the index if the target is found. If not, return the index where it would be if it were inserted in order. You may assume no duplicates in the array. Example 1: Input: [1,3,5,6], 5 Output: 2 Example 2:…
Given a sorted array and a target value, return the index if the target is found. If not, return the index where it would be if it were inserted in order.You may assume no duplicates in the array. Example 1:                      Input: [1,3,5,6], 5 …
题目:Given a sorted array and a target value, return the index if the target is found. If not, return the index where it would be if it were inserted in order. You may assume no duplicates in the array. Here are few examples.[1,3,5,6], 5 → 2[1,3,5,6],…
Given a sorted array and a target value, return the index if the target is found. If not, return the index where it would be if it were inserted in order. You may assume no duplicates in the array. Here are few examples.[1,3,5,6], 5 → 2[1,3,5,6], 2 →…
作者: 负雪明烛 id: fuxuemingzhu 个人博客: http://fuxuemingzhu.cn/ 目录 题目描述 题目大意 解题方法 日期 题目地址:https://leetcode.com/problems/insert-into-a-binary-search-tree/description/ 题目描述 Given the root node of a binary search tree (BST) and a value to be inserted into the t…
题目如下: Given the root node of a binary search tree (BST) and a value to be inserted into the tree, insert the value into the BST. Return the root node of the BST after the insertion. It is guaranteed that the new value does not exist in the original B…
Given a sorted array of integers, find the starting and ending position of a given target value. Your algorithm's runtime complexity must be in the order of O(log n). If the target is not found in the array, return [-1, -1]. For example,Given [5, 7,…
Suppose a sorted array is rotated at some pivot unknown to you beforehand. (i.e., 0 1 2 4 5 6 7 might become 4 5 6 7 0 1 2). You are given a target value to search. If found in the array return its index, otherwise return -1. You may assume no duplic…
题目描述: Given a sorted array of integers, find the starting and ending position of a given target value. Your algorithm's runtime complexity must be in the order of O(log n). If the target is not found in the array, return [-1, -1]. For example, Given…
1 题目: Given a sorted array and a target value, return the index if the target is found. If not, return the index where it would be if it were inserted in order. You may assume no duplicates in the array. Here are few examples.[1,3,5,6], 5 → 2[1,3,5,6…
基础题之一,是混迹于各种难题的基础,有时会在小公司的大题见到,但更多的是见于选择题... 题意:在一个有序数列中,要插入数target,找出插入的位置. 楼主在这里更新了<二分查找综述>第一题的解法,比较类似,当然是今天临时写的. 知道了这题就完成了leetcode 4的第二重二分的写法了吧,楼主懒... class Solution { public: int searchInsert(vector<int>& nums, int target) { , r = nums…
Search a 2D Matrix Write an efficient algorithm that searches for a value in an m x n matrix. This matrix has the following properties: Integers in each row are sorted from left to right. The first integer of each row is greater than the last integer…
Search in Rotated Sorted Array II Follow up for "Search in Rotated Sorted Array":What if duplicates are allowed? Would this affect the run-time complexity? How and why? Write a function to determine if a given target is in the array.   与I类似,只是在二…
Search in Rotated Sorted Array Suppose a sorted array is rotated at some pivot unknown to you beforehand. (i.e., 0 1 2 4 5 6 7 might become 4 5 6 7 0 1 2). You are given a target value to search. If found in the array return its index, otherwise retu…
Suppose a sorted array is rotated at some pivot unknown to you beforehand. (i.e., 0 1 2 4 5 6 7 might become 4 5 6 7 0 1 2). You are given a target value to search. If found in the array return its index, otherwise return -1. You may assume no duplic…