POJ - Til the Cows Come Home(Dijkstra)

【POJ - Til the Cows Come Home(Dijkstra)】的更多相关文章

POJ - Til the Cows Come Home(Dijkstra)

题意: 有N个点,给出从a点到b点的距离,当然a和b是互相可以抵达的,问从1到n的最短距离分析: 典型的模板题,但是一定要注意有重边,因此需要对输入数据加以判断,保存较短的边,这样才能正确使用模板. 题解 #include<iostream> #include<Queue> #include<cstdio> #include<vector> #include<string.h> using namespace std; #define maxn…

POJ 2387 Til the Cows Come Home Dijkstra求最短路径

Til the Cows Come Home Bessie is out in the field and wants to get back to the barn to get as much sleep as possible before Farmer John wakes her for the morning milking. Bessie needs her beauty sleep, so she wants to get back as quickly as possible.…

poj 2387 Til the Cows Come Home(dijkstra算法)

题目链接:http://poj.org/problem?id=2387 题目大意:起点一定是1,终点给出,然后求出1到所给点的最短路径. 注意的是先输入边,在输入的顶点数,不要弄反哦~~~ #include <iostream> #include <cstdio> using namespace std; ][],Min,node[],vis[],t,q; ; void set() { ; i<=; i++) { node[i]=INF; vis[i]=; ; j<=;…

POJ 2387 Til the Cows Come Home (Dijkstra)

传送门:http://poj.org/problem?id=2387 题目大意: 给定无向图,要求输出从点n到点1的最短路径. 注意有重边,要取最小的. 水题..对于无向图,从1到n和n到1是一样的. 直接Dijkstra即可 #include<cstdio> #include<cstring> const int MAXN=1000+10; const int INF=999999; int map[MAXN][MAXN]; int dis[MAXN]; int main() {…

Poj 2387 Til the Cows Come Home(Dijkstra 最短路径)

题目:从节点N到节点1的求最短路径. 分析:这道题陷阱比较多,首先是输入的数据,第一个是表示路径条数,第二个是表示节点数量,在这里WA了四次.再有就是多重边,要取最小值.最后就是路径的长度的最大值不是100,而是100001.用Dijkstra求最短路径,感觉 Dijkstra和Prim很像,都是从结点中找到路径最小的一条,然后再做某种更新.Dijkstra是看看源节点通过当前节点能否缩短从源头到其他节点的路径,而Prim则是通过加入当前节点到生成树,然后更新生成树中的路径数量,再从中找到最…

Til the Cows Come Home (dijkstra算法)

Bessie is out in the field and wants to get back to the barn to get as much sleep as possible before Farmer John wakes her for the morning milking. Bessie needs her beauty sleep, so she wants to get back as quickly as possible. Farmer John's field ha…