Remove Duplicates from Sorted Array Given a sorted array, remove the duplicates in place such that each element appear only once and return the new length. Do not allocate extra space for another array, you must do this in place with constant memory.…

以下三个问题的典型的两个指针处理数组的问题,一个指针用于遍历,一个指针用于指向当前处理到位置 一:Remove Element Given an array and a value, remove all instances of that value in place and return the new length. The order of elements can be changed. It doesn't matter what you leave beyond the new l…

Remove Duplicates from Sorted List Given a sorted linked list, delete all duplicates such that each element appear only once. For example, Given 1->1->2, return 1->2. Given 1->1->2->3->3, return 1->2->3. 思路: Easy. 依第二个开始,从前往后走一遍…

1. Remove Duplicates from Sorted List 题目链接 题目要求: Given a sorted linked list, delete all duplicates such that each element appear only once. For example, Given 1->1->2, return 1->2. Given 1->1->2->3->3, return 1->2->3. 这道题不难.具体程序…

1.合并两个排好序的list Merge Two Sorted Lists Merge two sorted linked lists and return it as a new list. The new list should be made by splicing together the nodes of the first two lists. 2.删除list倒数第n个元素 Remove Nth Node From End of List Given a linked list,…

Let's say we are going to find out number of occurrences of a number in a sorted array using binary search in O(log n) time. For example the given array is: [1,1,3,5,5,5,5,5,9,11], the number 5 appears 5 times; the number 3 appears 1 time; 2 appears…

这篇文章的图片链接发生了问题,无法正常查看图片,所以我在CSDN转载一下,特此声明. apt-getremove的行为我们很好理解,就是删除某个包的同时,删除依赖于它的包,例如:A依赖于B, B依赖于C,apt-getremove删除B的同时,将删除A(很好理解,A依赖于B,B被删了,A也就无法正常运行了) 先说明下apt-getautoremove与aptituderemove是一样的效果的,我们先了解下这两者的瓜葛 1 apt-get一开始并没有记录auto-install的信息 2 在ap…

卸载ipython pip uninstall ipython 安装ipython6.2.0 pip install ipython==6.2.0…

Search in Rotated Sorted Array Suppose a sorted array is rotated at some pivot unknown to you beforehand. (i.e., 0 1 2 4 5 6 7 might become 4 5 6 7 0 1 2). You are given a target value to search. If found in the array return its index, otherwise retu…

一:Search in Sorted Array 二分查找,可有重复元素,返回target所在的位置,只需返回其中一个位置,代码中的查找范围为[low,high),左闭右开,否则容易照成死循环. 代码: class Solution { public: int search(vector<int>& nums, int target) { int numsSize = nums.size(); ,high = numsSize; while(low < high){ ; if(n…