B. A and B and Compilation Errors time limit per test 2 seconds memory limit per test 256 megabytes input standard input output standard output A and B are preparing themselves for programming contests. B loves to debug his code. But before he runs t…

题目意思还是蛮简单的,看 输入数据输出数据还是比较明显的 我用排序来写还是可以AC的 //#pragma comment(linker, "/STACK:16777216") //for c++ Compiler #include <stdio.h> #include <iostream> #include <fstream> #include <cstring> #include <cmath> #include <s…

这道题是超级水的,在博客上看有的人把这道题写的很麻烦. 用 Python 的话是超级的好写,这里就奉上 C/C++ 的AC. 代码如下: #include <cstdio> #include <iostream> using namespace std; int main(void) { long long int n, num; while (scanf("%lld", &n) != EOF) { long long int sum1 = 0, sum…

A and B are preparing themselves for programming contests. B loves to debug his code. But before he runs the solution and starts debugging, he has to first compile the code. Initially, the compiler displayed n compilation errors, each of them is repr…

B. A and B and Compilation Errors time limit per test 2 seconds memory limit per test 256 megabytes input standard input output standard output A and B are preparing themselves for programming contests. B loves to debug his code. But before he runs t…

A and B and Compilation Errors time limit per test 2 seconds memory limit per test 256 megabytes input standard input output standard output A and B are preparing themselves for programming contests. B loves to debug his code. But before he runs the…

SQL> create or replace function 2 remove_constants(p_query in varchar2) return varchar2 3 as 4 l_query long; 5 l_char varchar2(1); 6 l_in_quotes boolean default FLASE; 7 begin 8 for i in 1..length(p_query) 9 loop 10 l_char :=substr(p_query,i,1); 11 i…

codeforces 373 A - Efim and Strange Grade(算数模拟) 原题:Efim and Strange Grade 题意:给出一个n位的实型数,你可以选择t次在任意位进行四舍五入的进位,求最大结果. 解法:这道题一定不能忽略数位计算时本身带来的进位,如果我们要改变这个数的大小,一定是在最先的那个出现5以上的数字进行四舍五入,之后的t次允许我们多次四舍五入,如果自然进位则不消耗t. 最后一点,整数位的进位也是需要考虑的 #include <cstdio> #inc…

解决方案: sqlplus / as sysdba grant execute on UTL_I18N to scott; grant execute on DBMS_CRYPTO to scott;…

出现这错误的话,存储过程还是会成功创建的,创建好后再逐个打开查找存储过程的问题 问题:基本上就是存储过程里面的表不存在,dblink 不存在    ,用户名.xx表  要么用户名不存在要么表不存在 创建好后,右键view存储过程,下面消息栏就会提示表不存在什么什么之类的,修改完F8按下执行即可…