Input array is sorted: Use binary search or two pointers Unsorted: Use hash map, key = target - a[i], value = a[i] Search and find containsKey…

167. Two Sum II - Input array is sorted Given an array of integers that is already sorted in ascending order, find two numbers such that they add up to a specific target number. The function twoSum should return indices of the two numbers such that t…

167. Two Sum II - Input array is sorted[easy] Given an array of integers that is already sorted in ascending order, find two numbers such that they add up to a specific target number. The function twoSum should return indices of the two numbers such…

Leetcode之二分法专题-167. 两数之和 II - 输入有序数组(Two Sum II - Input array is sorted) 给定一个已按照升序排列 的有序数组,找到两个数使得它们相加之和等于目标数. 函数应该返回这两个下标值 index1 和 index2,其中 index1 必须小于 index2. 说明: 返回的下标值(index1 和 index2)不是从零开始的. 你可以假设每个输入只对应唯一的答案,而且你不可以重复使用相同的元素. 示例: 输入: numbers…

package y2019.Algorithm.array; /** * @ProjectName: cutter-point * @Package: y2019.Algorithm.array * @ClassName: TwoSum2 * @Author: xiaof * @Description: 167. Two Sum II - Input array is sorted * Given an array of integers that is already sorted in as…

Question 167. Two Sum II - Input array is sorted Solution 题目大意:和Two Sum一样,这里给出的数组是有序的 思路:target - nums[i],这样就实现了降维了 Java实现: public int[] twoSum(int[] nums, int target) { int[] result = new int[2]; Map<Integer, Integer> map = new HashMap<>(); f…

Given an array of integers that is already sorted in ascending order, find two numbers such that they add up to a specific target number. The function twoSum should return indices of the two numbers such that they add up to the target, where index1 m…

167. Two Sum II - Input array is sorted Easy Given an array of integers that is already sorted in ascending order, find two numbers such that they add up to a specific target number. The function twoSum should return indices of the two numbers such t…

Two Sum II – Input array is sorted whowhoha@outlook.com Question: Similar to Question [1. Two Sum], except that the input array is already sorted in ascending order. 同上题:先排序,然后从开头和结尾同时向中间查找,原理也比较简单.O(nlogn) runtime, O(1) space vector<int> twoSumSore…

1.two sum 用hash来存储数值和对应的位置索引,通过target-当前值来获得需要的值,然后再hash中寻找 错误代码1: Input:[3,2,4]6Output:[0,0]Expected:[1,2] 同一个数字不能重复使用,但这个代码没排除这个问题 class Solution { public: vector<int> twoSum(vector<int>& nums, int target) { vector<int> result; uno…