题目Median of Two Sorted Arrays(难度Hard) 方案1,数组合并&排序调用Java方法 import java.util.* class Solution { fun findMedianSortedArrays(nums1: IntArray, nums2: IntArray): Double { val lenNums1 = nums1.size val lenNums2 = nums2.size val array = Arrays.copyOf(nums1,…
LeetCode(3) || Median of Two Sorted Arrays 题记 之前做了3题,感觉难度一般,没想到突然来了这道比较难的,星期六花了一天的时间才做完,可见以前基础太差了. 题目内容 There are two sorted arrays A and B of size m and n respectively. Find the median of the two sorted arrays. The overall run time complexity should…
Median of Two Sorted Arrays 搜索时间复杂度的时候,看到归并排序比较适合这个题目.中位数直接取即可,所以重点是排序. 再来看看治阶段,我们需要将两个已经有序的子序列合并成一个有序序列 by 图解排序算法(四)之归并排序 第1次提交 class Solution: def findMedianSortedArrays(self, nums1, nums2): """ :type nums1: List[int] :type nums2: List[in…
Median of Two Sorted Arrays There are two sorted arrays A and B of size m and n respectively. Find the median of the two sorted arrays. The overall run time complexity should be O(log (m+n)). 解法一:保底做法,O(m+n)复杂度 按照归并排序的思路,先归并,再找中间值. class Solution { p…
Median of Two Sorted Arrays There are two sorted arrays A and B of size m and n respectively. Find the median of the two sorted arrays. The overall run time complexity should be O(log (m+n)).SOLTION 1: 1. 我们借用findKthNumber的思想.先实现findKthNumber,如果是偶数个,…
4. Median of Two Sorted Arrays Hard There are two sorted arrays nums1 and nums2 of size m and n respectively. Find the median of the two sorted arrays. The overall run time complexity should be O(log (m+n)). You may assume nums1 and nums2 cannot be b…
题目 There are two sorted arrays nums1 and nums2 of size m and n respectively. Find the median of the two sorted arrays. The overall run time complexity should be O(log (m+n)). You may assume nums1 and nums2 cannot be both empty. Example 1: nums1 = [1,…
There are two sorted arrays A and B of size m and n respectively. Find the median of the two sorted arrays. Have you met this question in a real interview? Example Given A=[1,2,3,4,5,6] and B=[2,3,4,5], the median is 3.5. Given A=[1,2,3] and B=[4…
要求:Median of Two Sorted Arrays (求两个排序数组的中位数) 分析:1. 两个数组含有的数字总数为偶数或奇数两种情况.2. 有数组可能为空. 解决方法: 1.排序法 时间复杂度O(m+n),空间复杂度 O(m+n) 归并排序到一个新的数组,求出中位数. 代码: class Solution { public: double findMedianSortedArrays(int A[], int m, int B[], int n) { int *C = new int…