CSU1659: Graph Center(最短路)】的更多相关文章

Description The center of a graph is the set of all vertices of minimum eccentricity, that is, the set of all vertices A where the greatest distance d(A,B) to other vertices B is minimal. Equivalently, it is the set of vertices with eccentricity equa…
http://acm.csu.edu.cn/OnlineJudge/problem.php?id=1659 题意是找一个图的中心,图的中心定义是某一个点到其他点的最大距离最小,如果有多个排序输出. 注意这里大到其他点的距离是找一个最短的距离,那么就转化成了最短路的问题,求出每个点与其它点的最大距离, 保存并且求出最大距离中的最小距离,然后判断有几个点满足条件输出即可. #include <iostream> #include <cstdio> #include <cmath&…
1659: Graph Center Time Limit: 1 Sec  Memory Limit: 128 MB Submit: 63  Solved: 25 [id=1659">Submit][Status][Web Board] Description The center of a graph is the set of all vertices of minimum eccentricity, that is, the set of all vertices A where t…
Sparse Graph Problem Description   In graph theory, the complement of a graph G is a graph H on the same vertices such that two distinct vertices of H are adjacent if and only if they are notadjacent in G. Now you are given an undirected graph G of N…
B. Complete The Graph time limit per test 4 seconds memory limit per test 256 megabytes input standard input output standard output ZS the Coder has drawn an undirected graph of n vertices numbered from 0 to n - 1 and m edges between them. Each edge…
The Shortest Path in Nya Graph Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others)Total Submission(s): 37    Accepted Submission(s): 6 Problem Description This is a very easy problem, your task is just calculate el cam…
The Shortest Path in Nya Graph Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others)Total Submission(s): 13070    Accepted Submission(s): 2794 题目链接:http://acm.hdu.edu.cn/showproblem.php?pid=4725 Description: This is a ve…
The Shortest Path in Nya Graph Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others)Total Submission(s): 11694    Accepted Submission(s): 2537 Problem Description This is a very easy problem, your task is just calculate…
题目链接:http://acm.hdu.edu.cn/showproblem.php?pid=4725 题意:n个点,某个点属于某一层.共有n层.第i层的点到第i+1层的点和到第i-1层的点的代价均是C.另外有一类边连接两个点u.v,代价w.求1到n的最短路. 思路:拆点.n个点不动,编号1到n.将n层每层拆成两个点,第i层拆成n+i*2-1,n+i*2.相邻的层连边(n+i*2-1,n+(i+1)*2,C),(n+(i+1)*2-1,n+i*2,C).若顶点u属于第i层,连边(u,n+i*2-…
转载请注明出处,谢谢:http://www.cnblogs.com/KirisameMarisa/p/4297574.html      ---by 墨染之樱花 题目链接:http://acm.hdu.edu.cn/showproblem.php?pid=4725 题目描述:给一张图,每个点(1~N)都属于一个层(1~N),比如点1在第5层,点3在第4层,点4也在第5层.任何在x层的点都可以移动到x+1层和x-1层中的任何点上,并且需要耗费C的权值.除此之外,另外再给出M条带权无向边.求点1到点…