Your music player contains N different songs and she wants to listen to L (not necessarily different) songs during your trip.  You create a playlist so that: Every song is played at least once A song can only be played again only if K other songs hav…

Your music player contains N different songs and she wants to listen to L (not necessarily different) songs during your trip.  You create a playlist so that: Every song is played at least once A song can only be played again only if K other songs hav…

Your music player contains N different songs and she wants to listen to L (not necessarily different) songs during your trip.  You create a playlist so that: Every song is played at least once A song can only be played again only if K other songs hav…

# Title Solution Acceptance Difficulty Frequency     4 Median of Two Sorted Arrays       27.2% Hard     10 Regular Expression Matching       25.6% Hard     23 Merge k Sorted Lists       35.8% Hard     25 Reverse Nodes in k-Group       37.7% Hard    …

请点击页面左上角 -> Fork me on Github 或直接访问本项目Github地址:LeetCode Solution by Swift    说明:题目中含有$符号则为付费题目. 如:[Swift]LeetCode156.二叉树的上下颠倒 $ Binary Tree Upside Down 请下拉滚动条查看最新 Weekly Contest!!! Swift LeetCode 目录 | Catalog 序        号 题名Title 难度     Difficulty  两数之…

Return value/code Description 0x00030200 STG_S_CONVERTED The underlying file was converted to compound file format. 0x00030201 STG_S_BLOCK The storage operation should block until more data is available. 0x00030202 STG_S_RETRYNOW The storage operatio…

BIMFACE二次开发系列目录     [已更新最新开发文章,点击查看详细] 在前两篇博客<C#开发BIMFACE系列42 服务端API之图纸对比>.<C#开发BIMFACE系列43 服务端API之图纸拆分>中介绍了单文件多图框的拆分与对比 本文将详细讲解如何计算图纸对比差异项来源自哪个图框. 以控制台中的2张图纸[建筑图纸1-已拆分.dwg] 与 [建筑图纸2-已拆分-已变更.dwg]为例 对比结果参考上面第2个动态图. 获取图纸对比结果API 调用BIMFACE服务端接口 1…

#include <pthread.h>#include <stdio.h>#include <sys/time.h>#include <string.h>#include <unistd.h>#define MAX 10 pthread_t thread[2];pthread_mutex_t mut;int number=0,i; void *thread1(){while(1){number=i;printf ("Thread1:…

目录 1. Math 对象:数学对象,提供对数据的数学计算.如:获取绝对值.向上取整等.无构造函数,无法被初始化,只提供静态属性和方法. 2. Number 对象 :Js中提供数字的对象.包含整数.浮点数等等.并提供数字的类型转换.小数点截取等方法. 1. Math 对象 1.1 介绍 Math 对象,是数学对象,提供对数据的数学计算,如:获取绝对值.向上取整等.无构造函数,无法被初始化,只提供静态属性和方法. 1.2 构造函数 无 :Math 对象无构造函数,无法被初始化,只提供静态属性和方法…

题意:求f(n)=1/1+1/2+1/3+1/4-1/n   (1 ≤ n ≤ 108).,精确到10-8    (原题在文末) 知识点:      调和级数(即f(n))至今没有一个完全正确的公式,但欧拉给出过一个近似公式:(n很大时)       f(n)≈ln(n)+C+1/2*n       欧拉常数值:C≈0.57721566490153286060651209       c++ math库中,log即为ln. 题解: 公式:f(n)=ln(n)+C+1/(2*n); n很小时直接求…