---恢复内容开始--- Heron and His Triangle Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 262144/262144 K (Java/Others)Total Submission(s): 2543    Accepted Submission(s): 1060 Problem Description A triangle is a Heron’s triangle if it satisfies th…

题目链接:https://vjudge.net/problem/HDU-6222 思路:打表找规律. 然后因为数据范围较大可以考虑用字符串模拟,或者__int128要注意用一个快读快输模板. 1 #include <bits/stdc++.h> 2 #include <time.h> 3 #include <set> 4 #include <map> 5 #include <stack> 6 #include <cmath> 7 #i…

题面(本人翻译) A triangle is a Heron's triangle if it satisfies that the side lengths of it are consecutive integers t - 1, t, t + 1 and thatits area is an integer. Now, for given n you need to find a Heron's triangle associated with the smallest t bigger…

A triangle is a Heron’s triangle if it satisfies that the side lengths of it are consecutive integers t−1, t, t+ 1 and thatits area is an integer. Now, for given n you need to find a Heron’s triangle associated with the smallest t bigger than or equa…

A triangle is a Heron’s triangle if it satisfies that the side lengths of it are consecutive integers t−1, t, t+ 1 and thatits area is an integer. Now, for given n you need to find a Heron’s triangle associated with the smallest t bigger than or equa…

题意:让你找这样的一个三角形,三条边为t,t-1,t+1,并且面积为整数,最后满足t大于等于n. n<=1e30 思路:直接推式子不会,打表找规律 f(n)=4*f(n-1)-f(n-2)(n>=3) f(1)=4 f(2)=14 队友用Java写的,再写个二分就行 import java.math.BigInteger; import java.util.Arrays; import java.util.Scanner; public class Main { public static v…

HDU 6225 Little Boxes 题意 计算四个整数的和 解题思路 使用Java大整数 import java.math.BigInteger; import java.util.Scanner; /** * * @author reqaw */ public class Main { /** * @param args the command line arguments */ public static void main(String[] args) { Scanner in =…

HDU 6222 Heron and His Triangle 链接:http://acm.hdu.edu.cn/showproblem.php?pid=6222 思路: 打表找规律+大数运算 首先我们可以打个表暴力跑出前几个满足题意的T 打表代码: #include<bits/stdc++.h> using namespace std; bool fun(double n) { if(abs(round(n) - n) < 0.000000000000001) ; ; } int ma…

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A: BBP Formula https://www.cnblogs.com/LzyRapx/p/7802790.html #include <bits/stdc++.h> using namespace std; #define ll long long inline ll qpow(ll x, ll n, ll mod) { ll base = x; ll ans = ; while (n) { ) ans = (ans * base) % mod; base = base * base…